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English Pages 269 Year 1969
Table of contents :
Preface
Notation
Contents
Chapter 1
1. Definitions and Examples
2. Homomorphism Theorems
3. Lie p-Algebras
Chapter 2
1. Nilpotent and Solvable Lie Algebras
2. Cartan Subalgebras
3. Solvable Lie Algebras
Chapter 3
1. Semisimple Lie algeras
2. Jordan Decomposition in Lie Algebras
3. Cartan Subalgebras
4. Arbitrary Lie Algebras with Non-Degenerate Killing Form
5. Classical Lie Algebras
Chapter 4
1. Universal Enveloping Algebras
2. Irreducible Representations of Classical Lie Algebras
3. Complete Reducibility and Weyl's Theorem
4. Representation Theory in Prime Characteristic
Bibliography
Index
INTRODUCTION TO LIE ALGEBRAS
by
Richard D. Pollack
... Notes by Gordon Edwards
QUEEN'S PAPERS IN PURE AND APPLIED MATHEMATICS - NO. 23
QUEEN 1 S UNIVERSITY, KINGSTON, ONTARIO.
PREFACE
These notes constitute the contents of a course g-iven to graduate students at Uueen's University ~ring the sprin~ term of 1969.
An attempt was made to give a general over-
view of the sub.iect, with perhaps more .attention than usual
paid to a comparison between modular and non-modular Lie algebras; that is, those over fields of prime characteristic and those over fields of characteristic zero.
The only other
novelty is in giving Curtis' modification of the Cartan-Weyl classification of the finite-dimensional ir~educible representations for the classical Lie algebras of arbitrary characteristic (other than 2 or 3). Throu~twut, little more is required than standard linear algebra.
I am indebted to (~ordon Erlwa1·cts for writing, correct,-
in~, revising and clarifying these notes, and to .Mrs. Eileen Wight for typing them.
I have been much influenced in these
notes by the books of Jacobson [8] and Seligman [10], and by a course given by the latter at Yale University.
R.D. Pollack.
Note:
Operators, aside from linear functionals, are written on the right. Unproved results are preceded by an asterisk.
- i -
NOTATION
K
arhi1.rary field.
IN
natur·al numbers.
7L.
inte ,;rers
«l
rational numbers.
C
complex numbers.
L
Lie al~ebra over
Ln
Ln
L(n)
L(n)
L (a.)
L(a.) -
t,.l(B)
normalizer of
CL(B)
centralizer of
f.ndK (\')
al~ehra of endomorphisms of
gt ( V)
Lie al~ebra of endomorphisms of
,.,.t n .,..,
Lie algebra of
stn
matrjces of trace zero in
d
n
scalar matrices in
n
lower trian@:ular matrices in
n
lower nil triangular matrices in
T l1 €
=
K.
[L,L n-1] , L1
=
= [L,L ] •
[L(n-1),L(n-l)], L(l)..,, fL,L]
B
in
n
•
L.
L •
in
V • V
•
K.
matrices over
nxn
gtn •
gtn. @:.f,n • g,t
•
n identity matrix; identity endomorphism.
e. . _ _ _ _matrix ( i_,j) elsewhere. _l....J_ _ _ _ _with _ _ _ _1_ _as ___ _ _ _entry, _ _ _ _ _0_ _ _ _ _ __ DK(A)
derivation algehra of
A •
ad a
inner derivation defined by
a EL •
set of inner derivations of
L •
p-map in a Lie p-algebra.
, ] ( ' >p
t.rar.e form for a representation
< ' >
Killin~ form of
H
Cartan subalgebra of
[
Lie multiplication. p
L. L.
~}
II
dual space of
A
set of roots of
II. L
-
relat.ive t.o
ii -
11 •
of
L •
Tl
-~
fundamental system of roots.
*"
star sum of roots.
A A a. ' .., t(a)
Cartan integer (a ,B E b. , ~
, h
level of
a
element of ---'-a_______ _
E
6.
II. such that
I=
0)
•
'
=
a(h)
l1
universal enveloping algebra; u-algebra.
ii
u-algebra of
11(K,T,S)
standard monomial in
II
embedded in ll •
- iii -
lJ
•
•
CONTENTS
l'KHFACE
i
NOTA'f'lON
ii
CHAP'fEk. I 1. Definitions and Examples
1
2.
Homomorphism Theorems
10
3.
Lie p-al~ebras
15
CilAPTER II
1.
Nilpotent and Solvable Lie Algebras
24
2.
Cartftn Suhalgebras
45
3.
Solvable Lie Algebras
49
CHAPTER III
1.
Semisimple Lie Algebras
66
2.
,Jordan Decomposition in Lie Algebras
79
3. 4.
Cart,an Subalr.-ehras
94
)•
Arbitrary Lie Algebras with Non-de1~enerate KillinP. Forms
102
Classical Lie Algebras
127
CI IA PT E I{ IV
1.
Universal Enveloping Algebras
187
2.
Irreducible Representations of Classical Lie Algebras
200
Complete Reducibility and Weyl' s Theorem
231
3. 4.
Representation Theory in Prime Characteristic
BIBLIOGRAPHY
245 257
lNl>EX
259
- iv -
CHAPTEK I
I.l
Definitions and ExamQles.
Definition 1.
An alg~bra
A
over a field
space with a K-bilinear product
AXA--:+ A
K
is a vector
•
We do not require associativity of multiplication in our definition.
However we will assume that all vector
spaces mentioned in this paper are finite dimensional, unless otherwise specified.
As usual, the multiplication in a Lie algebra will be denoted by means of square brackets.
Definition 2.
An al~ebra
L
Lie algebra if the product
(i) (ii)
[x,x]
=
over a field [
for all
0
, ]
is called a
satisfies
x EL
[[x,y],z] + [[z,x],y] + [[y,z],x] for all
K
=
0
x,y,z E L •
The second condition in the above definition is called the Jacobi identity.
- 1 -
Note that any Lie algebra is ADticommutative.; that
=
Thie
llows
from
(i) and the bilinearity of multiplication:
=
[x+y,x+y]
for
x y.
[x,y]
0
-[y,x]
1
is,
=
[x,x] + [x,y] + [y,x] + [y,y]
= [x,y] + [y,x] ,
If [X,Y]
X
and
Y
so
[x,y] = -[y,x] .
algebra
are subsets of a
denotes the set
3.
A subspace
B
B
is
then
..!I.
of a Lie algebra [B,B] ~ B; and if
called a Lie sµbalgebr~ if then
9
r { I: [x. ,y.] : x~ E X , Y.; E Y} • · 1 l. 1 1= JI.
Definitipn
=
called an ideal of
L
is
[L,B] £ B •
L •
Examples
a)
Given an associative algebra
A , we can always
introduce a Lie algebra structure by defining a Lie multiplication denoted
[x,y]
AL.
= xy - yx ; the resulting Lie algebra is
This example is, in a sense, the universal
example, as will be explained later. called the commutator of
x
and
')
y •
[x,y]
=
xy - yx
is
h)
If
V
is any vector space over
of all endomorphisms of associat.ive algebra. is isomorphic to with entries in
K
K
n
V
(denoted
K , the set is
EndK(V))
811
It is well known that this algebra , the algebra of all
·( where
=
n
nXn
matrices
dim V) ; of course the
isomorphism depends upon a choice of basis for associated Lie algebra is denoted
g.t,(V)
or
V •
g.(, 0
,
The with
the commutator mult.iplication introduced above. c)
If
A
K
is any algehra over
(not necessarily
r
associative) let + x(yF,)
for all
DK(A)
= {F.i
x ,Y E A}
E EndK(A)
•
: (xy)6.
=
(xi)
)y +
This is not:. an algehra under
composition of mappings; in fact
DK(A)
is not even closed
we obtain a Lie algebra called the derivation algebra of the verification is trivial. derivation of the algebra
Definiti£!!..._4. .ruL.!_
for each
the map from
for all
L
Each
6 E DK(A)
A
is called a
A •
a
in a Lie algebra
L
into
defined by
x EL.
-
.1 ,..
L , denote by x(ad a)== [x,a]
a derivation of -----------
a f L •
L
Ptoof:
a
Evidently
is an endomorphism of
[x,y]ad a= [[x,y],a]
[[a,x],y] - [[y,a],x]
Since multiplication in a Lie algebra
have
ad a
is
(
.Jacob
ant, icommut at i ve ,
) ., wt:
adL(L)
f_t_:.~position
[x ad a,y] + [x, y ad a] •
is a derivation on
Def j nit ion 6. L
Moreover,
[x,y]ad a= [[x,a],y] + [x,[y,a]J
= Thus
L •
L.
The set of inner d e r i ~ § . of a Lie algehra
= {ad a : a
z.
If
L
EL}
•
is a Lie algebra over _a field
K
Proof: We first show that hy showing that
adL(L)
is a subspace of
ad a+ ad b = ad(a+b)
-
4 -
and
DK(L)
cad a - ad(cal
for all
a,b EL , c EK •
This follows immediately
from the identities below:
x ad(a+b)
and
x ad(ca)
= [x,a+b] = [x,a] + = [x,ca]
Next we show that 6 E DK(L)
x(ad a+ ad b)
[ad a,6] = ad(a6)
for any
a EL ,
, thus establishing the fact that
-
[x5,a]
= [x6,a] +
[ X,
[ X,
adL(L)
.
is an ideal in
Let
~: L1
=
--+ L2
[xq,,yq,]
DK(L) •
be Li~ algebras over
and
a Lie homomorphism [x,y]cp
80 ] - [x6,a]
a(>]
= x ad(a&)
Definition is-.
6(ad a ) )
= [x,a](>
=
such that
=
c[x,a] = ex ad a •
==
x[ad a, 6 J = x((ad a)6
Therefore
[x,b]
.
'
is a vector space homomorphism
for all
- 5 -
K
x,y E L •
Definition 9. ~pa,~e over
Thus if
yep ) -
L
be a Lie algebra and
A f',!:'presentatiorr of
K •
homomorphism
( XC!) )(
Let
q:>:
L ~ g.f. (V)
q:>
is a repN·:sentation,
L
in
V
a vector
V
is a Lie
•
[x,y]cµ
=
[xq,,ycp] ·-
( Yq:> ) ( Xq:> ) •
Propo_§ition 10. defined by
acp
C;iven a Lie al_g~.!'..!.
=
ad a
L , t'1!Lma,n
is _a re12resentation of
q:>
in
L
_itself.
Proof: In the proof of proposition 7 we have seen that
ad(a+h) and
=
ad a+ ad b
c EK
phism from
=~0
ad h
ad(ca) =cad a
in other words, L
into
[ad a,6] - ad(a&) 5
and
gt( L)
for every
, we obtain
thtis showing that
r·epresentat ion.
•
q:>
q:>
for
a,h EL
is a vector space homomor-
We have also seen that
a EL , 6 E DK(L)
[ ad a, ad b]
=
ad ( a ad h)
takint!
=
ad[ a, h
is a Lie homomorphism and hence a
J
t
:,i
Thus the centre of
,,:\. • 1 [ 1,.,./,.·.~.' L" 'RY ,
an
is
{c E
The d~'r'i\f~'ti ,algebra
Definition ,3:::3.
C 1 ~~r'.l.',y:,
L
L-J ·· 1c._" .[ U:1 ','L0
··.··J·
··_,
L:1(tl:Jli.L
gf'
.!.L ( ld)J ,
for all
O
1 a 1L11.'i'e_ .ia·'1' g·e b.>r a ' L
11 so':t " th ai'·t'·;:,
L{ l)
is
L •
is
an
r
Examples U~t h L·
space over
= K
g,t:(V1)
where'
V
'is ati' n-dimerisional .vector
with a given basis.
In accordance with the
isbhiorphisnf mehti'ohed. in example' (h) 'above' we may think of t.he ,~lements 01f.
L
I
as
nxn · matrices·.
- r-
d)
'l'hP.matrices of Lrace zero form an ideal
~tn •
o(
This follows directly from the al~ehraic
properties or the trace, namely that = Tr(a) + Tr(b)
and
Tr(a
Yr(ab) = T~(ba) •
± b) =
(Note that the
trace of an endomorphism, defined to be the trace of any .matrix representation of that endomorphism, is independent of the given basis of The centre of
e)
where as usual d
6. .
1J
=
n ' the set of all
in the centre.
for any
p
implies
ae
and
j
'
and
dn f)
e
pq .a
'
i 'j
=
p
1J
f9r any
q
i
(1)
=
6 ..
1J
1,1
for
1
( 6 .. ) .
~
€
'
i
a
=
e pq
(a .. ).
.
=
( 6. 6
.) .
which in turn implies
a 1 p6qj
=
with
Given
i
=
j
1 < i
and
'
to obtain i
j
+
j
Thus
•
j
Now
< .n •
.
1p QJ 1,J 0
. . a .. ; this aij =· 6 1J J.1
and also that and therea E dn '
gtn •
[ g"'n • ,g"'n • ]·~
6
-
•
tn •
8 -
·since
Tr(ab) =· Tr(bal
In order to show· the
.}
l.,J
j
:::
in
1J 1,J
=
-
= [gtn ,gtn] = . st . n
it is clear that
.
[a,epq]
1 < p,q < n •
is the centre of L
and
j
H:K
scalar matrices, is clearly contained
whenever
a .. ·= 0
a ... = ajj 11
fore
=
choose
shows that
nxn
= h.t::
is dn
+
i
for
0
with
q
for all
6. a . 1p QJ
= gtn
and consider the matrix
L
pq
L
To see the converse, take
the centre of
=
V .)
reverse inclusion we will make use of the matrix units e
introduced ahove.
pq
diag(>.. 1 , ••. ,>.. ) +
the form
st n
is of
where
n I: >...
Every element of
·
; a .. e .. . . l.J 1J
n
=
. 1 1 1=
J
1
0 ;
n-1 note that
t
diag(>.. 1 , ••. ,>,,n)= for
+j
i
>i,.(e .. - e ) . 1. 11 nn
i=l
it follows that [ e.
1n
for all
i ~ it follows that
g)
a
-
>.. € E st n
have n
'
a
=
>.. €
we may write and
.
>.. € E d n
with
Tr(a)
-
= (a
a
n1
K
= n>.. =
0
d n + n
and
s.t n n d JI
On the other hand if
n
=
{ o}
'
e 1. 1.
1J
l.,
e
-
nn
belongs
a E gt 0
a E flt
; hence
n ,
and
where
>.,E:) + >.. E:
Next, if
a. je ..
does not divide
is not a multiple of the characteristic.
= sl
=
,e . ]
First, if Tr(a) = >..
I:
i~j
diag(>,, 1 , ••• ,>..n)
If the characteristic of
Since
)
d n t1 n
=
0
Thus
1¥'e
since gtn
=
so the sum is direct.
is a multi12le of the characteristic
_t_h_e_n__T_r_(.,.\_t..,)_=_n_.>.,_= __o__f_o_r_a...,1_1_...e-..._E_-_K_____s_o_t_h_a_-t_,_d n s; s.f, 0
-
()
-
•
I.2
Homomorphism Theorems.
is an ideal in a Lie algebra
I
If
quotient space
[x,y]
::::
+
The c.anonical map
verify.
then the
'
has a Lie algebra structure given
L/I
[x + I' y + I]
by
L
I
as the reader may easily
'
L ~ L/I
TI;
(whece
Kn
=
X
I)
..j..
is then clearly a Lie homomorphism.
Prop~sition 1.
= ker
I
L/I
~
ls a Lie homonaor12hj..sm, l.!l.~
q:,: L--+ M
is an ideal of
q:i
H , and
of
If
L ,
=
N
im q,
is a Li~. subal_g_ebr:a
N •
Proof:
and
We know already that
I
If
a
respectively.
~l
[x,a}p
= rxco 'acp] = [xco,OJ =
an ideal of
.
because
L
.
E I 0
'
defined by
N
are subspaces of
N
and
so
Similarly we have
[L,L] £ L so '
: L/I ~ N
and
then
[L,I] £ I
and
[N ,N]
(x +
Ih =
xco
[x,y}p
= [x::p,yrp] = [(x+I)f , (y+Ih]
I
is
= [ L, L ]cp S. Lcp =
is a·subal~ebra of
be a vector space isomorphism, and since
=
E L
'
X
L
M
0
'l'he map
is already known to [x+I,y+I]iu
=
it follows that
~
is a Lie isomorphism.
I - 10 -
N
Corollary 2.
There is a one-to-one 2orrespondence
L
between tJwse subalgebras of all the subalgebras of
N
I
containing
( wit!!
L, I ,I\
and
as above).
Proof: We know there is a one-to-one correspondence between subspaces of
L
containing
I
, and subspaces of
It is therefore sufficient to show that if
L ,
algebra of
B~
is a subalgebra of
u~-l
is a sub-
N , and if
is a subalgebra of N
B
N •
D L
is a subalgebra of
lhese implications are both clear.
of a Lie algebra 13
n
I
L
is an ideal of
B+I
then
B , and
~f
is a sub.algebra 8/B
n
I -
13 + I/I
L (l!..§.
Lie algebras).
Proof: Since sec that
[ll+I, IHI]£ [B,B] + [H,I] + [I,I] £ B+I B+ I
is a subalgehra of
be the map defined by
xco
=
x+I
-
L for all
11 -
Let
qi:
x CB
n
, we
~ IHI/I
We know
aJ 1·eady that ·this is a vector space· homomorphism with
ker rf> = B n l
and
im cp =IHI/I.
Moreover
= rx,y] +I= [x+I, y+I) = [x~,y~] , so honiomorphism. 8
n
I
~
rx,y]cp
=
is a Lie
It follows from Proposition 1 above that
is an ideal in
B
and th~t
n
B/D
I~ B+I/I
(as Lie alaebras).
Definition
I.l.lJ). k > 1
4.
Recall that
~e now define
L(l) = [L,L]
(definition
L(k) = [L(k-l),L(k-l)]
for
•
Hy convention, we will write
easily seen that each L = L(o)
is~ and
L = L(o) •
is an ideal of
It is L , since
[L(k) ,L] = [[L(k~l) ,L(k-l)],L] £
£ [[L,L(k-1)], L(k-1)] £ [L(k-1), L(k-1)] = L(k) the Jacobi identity and induction.
by
The series is called
the derived series of the Lie algebra
Definition
5.
If
for some
called a solvable Lie algebra.
- 12 -
L •
k > 0 ,
L
is
Exampl~.
a)
Let
matrices in
Tn
be the set of all lower triangular Thus
gtn •
i < j}
whenever
i < j + 1}
1J
=
=
{ (a .. ) . . : aij 1J 1,J
T(l) = [T , T l n n n
whenever
a ..
Tn
'
and
Lie algebra,, since
T(n) n
=
0 •
Hence
If
L
=
0
T(k) = {(a .. )i j: n l.J ' n
is a solvable
T(l) = u n n
is called the
T
set of all lower nil triangular matrices in
Proposition~.
0
{ ( aij).1,J. : aij
in general
i < j + k} •
0 whenever
=
=
gtn •
is a solvable_Lie algebr~, so is
every Lie suhalgebra and every Lie homomorphic image of
L •
Proof: This follows immediately from the observations that B £. L
implies
B(k) £ L(k) , and that
for every Lie homomorphism
(L(k))cp = (Lcp)(k)
cp •
I
- 13 -
Proposition algebra
l•
L
If
I
such that
is a solvable ideal of a Lie
is solvable, th~
L/I
L
itself is solvable.
Proof: We know there exist integers
(L/l)(j) = 0
and
I(k)
=
0 •
L(j) £ I , which implies
But
k
and
j
such that
=
(L/I)(j)
L(j+k) £ I(k)
=
0
0
implies
•
I
r1
Proposition b.
If
and
L , then so is
I1 + I2 •
I2
are solvable ideals of
Proof: Since
1 1 /1 1 n 1 2 ~ (I 1 +I 2 )/I 2
solvable, it follows that
I1 + I1
and
I2
are both
is also solvable.
I
Definition
9.
The radical
R
of a Lie algebra
the sum of all the solvable ideals of
..;. 14 -
L •
L
is
It follows from proposition 8 that the radical of a Lie algebra is the unique maximal solvable ideal.
Definition 10.
A Lie algebra having no nonzero solvable
ideals is called semisimple.
Thus if
I.3
R
is the radical of
L , L/R
is semisimple.
Lie p-Algebras.
Let
A
over a field
be a finite dimensional associative algebra K
of prime characteristic
p .
make some observations about the Lie al~ebra
We will AL
and use
them as a basis for the definition of Lie p-algebras.
Le~~·
If
X
and
Y
are commuting indeterminates
over a field
K
.Q.L._P.rime characteristic
-
l '1 -
p , then in
p-1
t
(X-Y)p-l -
(ii)
xivp-i-1 •
i=o
!'roof:
The first result follows inunedia.tely from Newtou' s
p
binomial formula, since efficient
(r) 1
divides each binomial co-·
O < i < p •
with
The second result
follows from the first, together with the identity
= (X-Y)
p-1
'
'
]
t X1Yp-1-.
i=o
£.Fopo_~ition_l.
field
K
If
A
is an associative algebra over a
~rime characteristic
( i)
(ii)
(ad a)P = ad(aP)
p
for all
'
where
coefficient of of ring
AL
we
a C A
p-1
(a+b)P = aP + bp + a,b E A
, then in
t
i:::l
s.(a,b) 1
isi(a,b) i-1
X
for
is the
in the expansion
a(ad(aX+b))p-l , in the polynomial
A[X] , considered as a Lie algebra. - 16 -
Proof: Consider the endomorphisms of
at: x ~ ax at
commute.
A
into
a : x ~ xa r
and
Evidently
and
By lemma 1 it follows that
(ad a)P
A
•
=
.
)P .. a p - ap = ad(aP) J',foreover (ad a)p-1 r .t p-1 i p-i-1 by lemma (a - at )p-1 l so I: a r at r ' i=o p-1 b(ad a)p-1 = t aib a p-i-1 Similarly in A [X] we ' i=o p-1 . have a(ad(aX+b))p-l = t (aX+b) 1 a(aX+b)p-i-l i=o
= ( ar
-
at
=
.
each
p-1 I: si(a,blXi i=l
(aX+b)P = aPxP +hp+
Clearly si(a,b)
is a polynomial in
a
b •
and p-1
derivatives of both sides we obtain
where
Taking
.
t (aX+b) 1 a(aX+b)p-i-l =
i=o p-1 ( ) i-1 =-I: i s.1 a,b X i=l the derivative of hut rather
(Since
and
a
(aX + b)P
need not commute,
b
p(aX + h )P-1 .a
is not
p-l . )p-i-1 I: (aX + h) 1 a(aX + h i=o
=
0
'
as inrlicated.)
Makin~ use of the identity from the previous para~raph, we see that
i
s.(a,h) 1 .
the expansion of
is the coefficient of
a(ad(aX+b))p-l
Xi~l
Finally, setting
in X
= 1
in the identity displayed in the openine; sentence of this paragraph, we have
(a+b) p
=
a
JJ
+ hp
.L
p-1 I: s.(a,b) •
1=
1·
1
•
I
- 17
~
Since all the important examples of Lie algebras in prime characteristic have properties similar to those indicated above, we introduce the followin~ definition:
Dcfi11itiou a field
K
"p-map"
a
J.
A Li~ p-algebr~
L
is a Lie algebra over
p
of prime characteri~tic
~ a [ P]
(ii) (iii)
such that
(ad a)P
=
ad(a[p])
(a+b)[p] = a[p for
]
for all .
+ bfp
a,h EL , where
coefficient of of
which has a
Xi-l
]
p-1
+
E s.(a,b)
. l 1=
1
is.(a,b) 1
is the
in the expansion
a(ad(aX+b))p-l , and
indetermiriate over
a EL;
X
is an
K •
p-1 Note that the term expansion of
Note also that if for then
s 1 (a,b) L
s. (a,h)
occurring in the
is independent of the given p-
(a+b)[p]
map, since each
t
. 1 1 1=
is defined intrinsically. (a+b)[p] = a[p] + bfp]
is ahelian
a(ad(aX+b))p-l = 0 .
Lie p-algebras are some-
times called "restricted Lie algehras 11 (see Jacobson [ S J.
- lh -
chapter five).
Definiti01!__4_._
L
If
is a Lie p-al{!ehra. then hy a
p-suhalgehra (p-ideal) we mean a subal~ebra (ideal) of
L
which is closed under the p-map of
L.
Examples. a) ·
If
A
is an associative al{!ebra over
prime characteristic
p , then
algebra if we define
a[p]
AL
= ap
In particular
for all
gt(V)
the associative p-map, if field of characteristic
V
seen that every
(ab)~k =
~
~
a EA ; we ( see proposition
is a Lie p-algebra under
is a vector space over a
p > 0 •
Given an algebra
b)
of
becomes a Lie p-
will call this ''the associative p-map" 2 above).
K
A
over
K
,
it is easily
satisfies Leibniz' rule
E DK(A)
(~)(a~j)(b6k-j)
for
a. h E A •
If
j=o J
char ( K)
= 11 >
(ab)~P
= (a6P)b
of lemma 1). p-map
fl[p]
0
it follows that + a(bt,P)
DK(A)
=
tip
6 P E DK (A)
also, since
by Leibniz' rule (see the proof
becomes a Lie p-al~ebra under tl1e
•
- 19 -
c)
If
G
is an algebraic group over a field of
p > 0 , its Lie algebra
characteristic
is a
L(G),.,~
Lie p-al,:el>ra (see, for example, Aorel [15)).
Definition.__5.
If
characteristic
p
is a Lie algebra over
L
>
0
p - s em.i;..!.!_n~,.!U a .P of
f: L
~
for all
'
a,b EL
(a+b)f
=
af + bf
If
[p\ a~ a cent_££•
'
then by a
(>..a )f
and
=
A.P(af)
A EK •
and
p-maps, b~~h makin_g
C
into its centre we mean a map
L
such that
C
having centre
of
K
a~a
rP J,.·)
are two
into a Lie p-.!,_~ebra, !.!!..en
L
[pll - a
is_"'! p-!t_enaili..!!,ear map of
Moreover if
f
L
i11to_j.ts
is..!.,!!Y p-semilinear map of
L
[p]l
+ af
a---+ a for
is another p-m~p
L •
Proof:
[ p] l
We first show that map of
L
Since
a---+ a
[p ]2 -a
is a p-semilinear
into its center• ad(a
fp\ - a
[ pl') [p]l .... ) == ad(a )
-
20 -
[p]2 ad (a
)
=
::.-=
centre for every
we have
EL.
a
.
[p],,
"' )
.
f pl.,
(ad a) 11 - (ad a)fl = 0
- a . [p]l (la) · -
Clearly
[p]l
[p]2 (la)
•
[p]2
(a+b)
Also
in the·
=
h1+b)
[p]2 b
[ p]. 1
(a+b)
=
[p
Ji
(.p].
+ b
a
, because
)
p-1
t s.(a,b) j=l J
+
1
= 1,2)
(i
and
p-1
t
as previously remarked, the term
s.(a,b)
is independent
J
j=l of the choice of p-map.
On the other hand if
f
i~ a p-semilinear map of a [p]
into its centre, let us write
=
a[p]l
+ af.
L
Then we
have (i)
= (ii)
=
af
(a+b)[p]
[p]l
+ (la)f
(>..a)
a[p]
>.. p
au(a[p])
since (iii)
=
(>..a)[p]
for
a ~ a[ P]
>..P(a
+ af)
=
[p]
+ af)
[p]l ad(a
is in the centre of
= (a+b)
[p]l
=
E K
[p]l
ad(a
+ (b Hence
)._
=
1 + (a+b)f
)
= (ad a)P
L;
=
[p]l (a
+ af) +
p--1
[p]l +hf)+
"" s.(a,b) • ,., 1 . i=l
is a p-map as asserted.
I
- 21 -
As an Jm.mediate consequence we have
!f
Co_rollary_l. QY_~
L
!!LJ!..
of characte~isti,.£
K
.Q!~ p-!,llaP making
L
lie alge_pra with zero centre
p
> 0 , there is at most
into a Lie p-algebra.
Pro()f: This is so since the only p-semilinear map of
L
into its centre is the zero map.
I
Def3:.nitiot~-~. p-algebra (a[p])~
L
A representation
0 •
( Jacobso_f!) }
Let
(ad xi)P
yi EL
(i
= l, •.• ,n)
= ad yi , then there is a unigu~ p-
x.[p] = y.
map such that
he a Lie algebra
over a field of characterist~E_
If there exist elements
such that
L
1
1
(i
= 1 , ... , n) , makj...!!,g
L
into a Lie p-algebr~.
(Ad~-Iwasawa)
Every_Lie algebra has a
faithful (i.e., 9ne-to-one) finite dimensional represent~ti_o_!!.
Thus, every Lie algebra is "essentially" a suhalgebra of some
istic
g-t 0
p > 0
•
~
be embedded in a Lie p-algehra.
Proof: This follows immediately, since algehra for any positive integer
n
gt 0
is a Lie p-
(see example
a).
I
- 23 -
CHAPTER II
II.l
Nilpotent _and Solvable Lie Al_g_ebras.
Definition~.
If
L
1s a Lie algebra we define
L0
Clearly, the
are ideals of
L.
It is important
to distinguish these ideals from the ideals in
defined
r.2.4.
The series
Oefinition 2.
L
L2
>
>
the descending cen~ral series of Ln
in zero, i.e. ,
=
0
L
for some
L3
'
. ..
>
is called
and if it terminates
n > 2
L
'
is called
!:!!-lpotent.
Example. a)
Let
matrices in
so is
ad,-
Un gt 0
be the set of all lower nil triangular •
In general, if
; for we can write
,- E gt 0
is nilpotent,
,-t. as in the
ad
proof of proposition I.J.2, and so
= "
.
0
for
k
sufficiently large.
We will see (Corollary 8) that in ~eneral, a Lie algebra L
is nilpotent if and only if each
nilpotent endomorphism of
ad a, a EL , is a
un
That
L •
is nilpotent
also follows directly from the fact that
ll k ={(a .. ) . . : a .. n 1J 1, J 1J
so
U
Lemma
n
= o
n =
0
J.
For any Lie algebra
i < j + k}
whenever
'
•
( i)
(ii)
[Lj Lk] c Lj+k j
L (k)
-
s.;;_ L
2k
we have
L
for al],_
for all
k
j
>
0
and
k
.
Proof:
We will establish property (i) by induction on For
j = 1
£ Lj+k+l
we have
[L,Lk] = Lk+l
by definition 1.
This yields the result.
We now establish property (ii).
=
L
.
using definition 1, the Jacobi identity, and
the induction hypothesis.
L (l)
j
2
•
'"' 0uppose that
For
L(k) £;: L2k
k
k
k
= 1
for some
s;: [L 2 ,L 2 ] c L
2 k+l
we have k
>
1
.
by property (i).
I ... ,.
Proposition
4.
Every ni~_~nt Lie algebra is s9lvabJ.e.
Proof: This is an immediate consequence of property (ii)
above. Note that the converse is not true, since, for example T
n
T k = U
is solvable, while
n
n
for all
k
>
2
9
(as is
easily checked).
Definition~.
If
normalizer of
B
B
is a Lie subalgebra of
in
It is clear that that
B
is
L
NL(B)
is an ideal of
NL(B)
= {x
L , the
E L: [x,B)11 ~ B}
is a Lie subalgebra of
NL(B) , and that
NL(B)
L
,
is maximal
with respect to these properties.
If
L
is a Lie subalgebra of
consisting of nilpotent endomorphisms, where
V
space of dimension
> 0 , then there is a nonzero
such that
for all
VT= 0
TEL •
gt(V)
is a Kt
v EV
Proof: When
L
is of dimension
O
or
,.
obvious; in the latter case, if
,. n XT
=
0
n-1
,. n-1
'
+
+
0
'
and let
0
=
X 'T
E V
X
L
and
such that
n-1
dim L"" n > 1
Now suppose
the theorem is
generates
simply choose V
l
, and assume the theorem
is true for all Lie algebras having dimension less than and consisting of nilpotent endomorrhisms of some K-
n
space. It suffices to find an ideal For then
OJ\C •
L
=
KT
0
$
B
where
B
in T
0
L
i
B , and by the
induction hypothesis there is a nonzero
=
wo
0
a E B}
for all
=
0
Thus
ideal.
.
If
a E B
for any
Consider
a EB
for all
'
=
K ,-
0
we
9
[,-o,o] E n
E \\
V
with VT
=
V 'T
Let
adL ( n O
):
I~ L
0
---3,-·
=/=
L
0
==
0
W(J
WCTT
since
0
·- 0
0
.
for all
0
show the existence of an ideal
one,
E V:
{w
WT
such that
13
+ wr-r 0 ,a]
0
B
D
is a.n
+
w
0
,
Since T
C L
of codimension
be any proper suhalgebra of leaves
0
--
is a nilpotent endomorphism on
TO
, it follows that
B
w EV
W
we have
because
so there is a non-zero L
E w
w
of codimension
L •
Since
fixed, it induces a Lie algebra
0
of nilpotent endomorphisms of
L/B
-
27 -
0
(by example
a
)
which
we denote by
adL/B (B 0
)
Since the dimension of
•
0
adL/D (B 0
)
is less than the dimension of
L , it follows
0
from the induction hypothesis that there is a
of
B
cr
t
so
B
Now take a maximal proper subalgebra
B
other words
and
E NL{Bo)
p
we have ,seen, there exists that
E B0
for every
, such that
0
NL (B)
=
L
= Ko
0
0
0
E NL(B)
Hence
E9 B •
B
B
'
o EL ,
In
+NL(Bo) .
0
L ; as
of
with
0
t
B
'
so
is an ideal of co-
dimension one, and this concludes the proof.
I
morphism...§__of
, . then there is a basis of
V
~-e..rx.. endomorphi_.filll_ in
L
V
such that_
has a lower nil triangular matrix
representation.
Proof: If L
dim V
=
1
the result is trivially true, for then
contains only the zero endomorphism. Suppose
dim V
=
K-spaces of dimension
n
> 1
and the result is true for all
n-1 •
-
By Engel's theorem there is a
?~
-
nonzero
v 1 EV
such 'that
lt is clear that
L
endomorphisms on
V/Kv 1 •
V
1
'f = 0
for all
'f
E L •
induces a Lie al~ehra of nilpotent
Applyin~ the induction hypothesis to conclude that there is, a basis of
V/Kv 1
V/Kv 1 , we relative to
whicJ1 all of these endomorphisms are represented by lower rd 1 triangular matrices o
so that
If
v 2 , ••• , v n
{v 2 + Kv 1 , ••• ,v 0 + Kv 1 }
every endomorphism in
L
t V
are chosen
is such a basis, then
will have a lower nil triangular
matrix representation relative to the basis of
V
•
I
if
ad a
is_!lilpotent for all
a E L •
Proof: To B8.Y that
for some X
H.
'a·l , , a)m-l =
l)
L
is nilpotent is to say that
Civen any
a ( L
f or a 11
x l.: L, ;
Lm -
0
therefore we have
· 111
nilpotent.
- 29 -
o th er wor d s
cHj
a
is
Conver·sely if
ad a
is nilpotent for every
then hy corollary 7 there is a basis of
Let
a 1 ,a 2 , ••• ,an+l E L
=
n
ad a
are lower
dim(L) ; given arbitrary
it follows from example II.l.a that
= O •
a 1 a d a 2 a d a 3 ••• a d •n+l
L f ore T11ere
Ln+l
=
0
is nilpotent.
L
so
In the next two propositions we consider a given ,. ~ EndK(V)
having all of its characteristic roots k.
m
;\. 1 , ••• ,;\.m
in
K.
=
i
=
T
,
Il (X-)..)
i=l
and let
=
1 , ... , m
t
(D
i=l
f. (X) l.
l.
=
k. (X-).. ) l.
'
then
V.l. = {v . EV: vf.(,-) = o} l.
vi,.
C
V.
l.
for each
i
V.1
Proof: V.,-
be the
l.
m
V
1
1, .•• ,m •
If i
p(X) =
Let
minimal polynomial of for
c- V.l.
L ,
such that all
L
matrices corresponding to the linear maps nil triangular.
a l
because
,-f 1.(T) = f 1.(T)T
- 10 -
•
and
1
ancI
DI
r.v.l
v-
To see that
q. (X) ~
• l':"t
i
.
Since the
for each
1
i=I
qi(X} are relatively prime, there exist polynomials m
r.(X) i.: K[X]
E r. (X )q. (X) i=l 1 J.
such that
1
=
1 •
Thus for every
E V '
V
m
t
i;:l
V
r.(T)q.(T) 1
v r. ( -r )q, ( T) E V.
But
1
1
1
V
•
~
, since
1
fnr ~~rh
tn
In other words
V
=
i: V. i=l 1
This sum is in fact dir~ct, for if
v Ev. n
then
V
and
1
f. (X)
,, q.(-:-)
=
v(
Q. (
1
= f 1 (X)r(X)
Consequently
X)
n
j=/=i
J.
and
1
l
f .(,J)
ct
v.)
j=J.i
J.
f .1.(7)) = 0. - ,
J
But
are relAtively p~i~~, so
~
q 1 (X)s(X)
V
= "
r(X), s(X)
for soroe
f.;(,}r(-r) +
v
-'·
q.(T)s(,-) 1
=
0
~
KfX] .
,
and
m V ""
r. i.=l
ID V.
l.
•
I
- 31 -
is the algebraic closure of K-space with basis
{v 1 ® 1, ••. ,v 0
induces~
T = -r&.i.d
'T
®
=
(v 1 -r)
V
= V ®K K is
1) •
~ E End_(V) K
(i.e. (vi® l)i=
E f:nd_(V)
K , then
® 1
a
Every
by the rule for
=
:l
1, ••• ,n)
.
is diagonalizableo
K
Examples. b)
The only endomor,Ehism which is both nilpotent
and semisimple is the zero endomorEhism 9 because th0 only diagonal matrix that is nilpotent is zero. c)
The sum of
is semisimplc.
~ commuting semisimple
endomorphisms
This follows from the fact that if two
diagonalizable matrices commute, they can be simultaneously diagonalized.
Note too that the sum of~o comntuti~ n;L~-
potent endomorphisms is nilpoten~, as follows immediately from Newton's binomial formula.
---------·--·
As in proposition 9, let
-r C EndK(V)
have ~11 its Ol
eigenvalues
x1- ." .•
,).. m
the minimal polynomial of
and let
'T'
v. = {.v Ev: v f.(.,.) 1
1
Let
K
in
(where
=
o} •
p(X) f.(X) 1
=
0: f.(X) i=l l. k.
=
(X-A,) l.
1 )
he
l'ro_g_osition 11. belong to
K , then
,.s +·,-n and
If all the e~nvalues of
[,- 8 ,Tn]
=
can be unigue~.Eressed in ti~!!
T
where 0 •
T
s
= s('i)
'i
n
'is semisimple, ,-
s
n
is ni~potent,
Moreover, there exist polynomials s(X}, n(X) E K[X]
without constant terms
,.
,- E EndK(V)
=
n('i)
such that
•
Proof: The only characteristic root of
Vi
is
Ai •
For if
f. (X)
prime to
1
and
q(X), r(X) E K[X] •
Thus
,. -1-l f:
restricted to
(X-~)
~+Ai , then 1
,.
is relatively
= (X-~)q(X) + fi(X)r(X)
If
v E V.
, we have
1
is invertible on
V.
,.
on
is the only eigenvalue of
for some
1
'
and consequently
V.
1
.
It is therefore possible to choose a basis for so that
,.
( restricted to
X.i
V.
1
V.) has a matrix representation 1
of the form 0
A.= 1 X. 1. If we let
- 33 -
and
where
is semisimple,
IL
1.
[B.,C.] l.
=
then we have
l.
=
Since
0
C.
1s
J.
B. + (:. l.
1
nilpotent, and
. V
-
m
t
EB
i=l
together a basis for
by proposition 9, we can piece
V.l.
so that
V
has a matrix represents-
T
tion of the form
A
=
cl·
0
A
m 0
Bl
n =
Setting
we obtain
and
[B,C]
A= B+C
=
0 •
corresponding to
where If
B
'f s
and
~nd
.
C
=
B
0
is semisimple,
\
is nilpotent,
are the endomorphisms
and
C
C
'
cJ
0
m
B
0
cl
respectively, then
is the desired decomposition of
T
T
=
T8
+
T0
•
By the Chinese remainder theorem there is a polynomial
s(X)
satisfying- the congruences
- 34 -
s(X) -
0 (mod X)
=
s(X)
A . ( mod f . ( X )) 1
for
1
=
i
\ . =
(These congruences are consistent, because k. f.(X) =X J .)
For any
vs(T)
=
i
each
V.
J
\.v , for 1
=
VE V.1
1, ... ,m •
implies
0
J
therefore, we have
1, ••. ,m.
Thus
=
s(T)
T
on
S
m
'
1
=
s(T)
and since on
T
s
.
V
V
I:: EB V.1 i=l
=
Now if
=
n(X)
'
it follows that
X-s(X)
'
--
n(T) = 'r-S(T)
We must still show the uniqueness of the decompositiono Accordingly, suppose is nilpotent, and
commute with -r
n
T8
--
n(T)
-
a=
T
,
From v
-
T0
T
= cr+v
where
[o,vJ = 0 •
Since
o
is semisimple, o
they also commute with
+
T8
=
T0
, with
Ts -
T
cr
=a+ v
T
s
both
v
= s(T)
and
it follows that
semisimple and
Therefore
nilpotent (see example c).
and
\J
v
-
Tn
an
the weigh!_ spaces).
Proof: ( i) and
u
\:
must
\v~
To show that. L
implies
produce
V
co
L £ V c,o
. E V rp
VO
an integer
In other words, ~iven
0
such that
n
p = r - cp( ,- )(£
is nilpotent because
L
(ad p ) ·i == 0
V
(
V
,p
'
14
j
it follows that
sufficiently large.
V
~r
\.
(vJ)(r-w(Tk l 11
note that
Op
n
adp =ad,.
=
But
is sufficiently large, and s.:ince
vp
n-j
=
0
For large enough
_ 1x _
provided n
O·-.i
is
, therefore,
i.
()
is nilpotent (see corollary 8).
we have
provided
(
,~)
For this purpose let
By lemma
,,
we must show that
'
(va)pn = o •
llence
Vci>L ~ Vcp
vo ( Vcp , so
m
(ii)
t
\\'e now show t.hat the sum
V
is direct
i=l cpi
cp 1 , ... ,cpm
whenever
are distinct weights; from this it
follows that there are only a finite number of distinct weights in all. m = 1
If m > 1
'
the assertion is trivially true.
and assume the result is true for
-
m
1
Suppose
.
We
m-1 V
will show that
cpm
n (
}: V
i=l
co.1
=
)
every other such
0 ;
intersection just amounts to a relabelling of the weights. Accordingly, let
0
t
m-1
v E V
com
m-1
= }:
V
V,
i=l
say, that , ( 'T")
'+-'}
=t
v. ( V
with
1
1
v1
=t O .
for
)
1, ... ,m-1
,. EL
Now choose
V
•
Write
i=l cpi
=
i
coi
n ( t
, and assume,
such that
( we are assuming that the weights are
q m ( ,- .)
distinct).
v ( V
Since
=
0
v(T - CO (,-)€) 8
1
V
co.1
=
m
v.(,- - co (,-)€) 6
m
L c V coi
and
there is an integer
com
EV
coi
(T -
such that ~ote that
for
i
=
l, •.. ,m-1
.:.p (,-)e;)S m
because
is a polynomial in
T
m-1
t
By the induction hypothesis
i=l therefore
s
v 1 (,-
- r,pm(T)t)s
=
0 •
- 39 -
V
cpi
is a direct sum;
•
011 the other hand
t
inte12,"er choice of
such that
E L
T
(X - ~ (T)) 6 polynomials c.0 1
-
v 1 (,-
col
qil('!")&)t
r(X)
(.,-))
t
and
q(X)
there is an
=
.
0
By our
(X - cp.1 ( 'f) )t
it follows that
are relatively prime.
m
1 == (X -
vl E V
since
and
Hence there exist
such th.at
r(X) + (X - qim(r))
s
q(X); this implies
v 1 = v 1 (,- - cp 1 (,-)c }tr(,-)+ v 1 (T - com(,-)t) 6 q(1) ""' 0 ,
that
which contl'adicts the choice of V
Consequently
cpm
n
y
1 •
m-1 ) ( I: V cp. i=l 1
m
=
0
and
t
V
is
Cf).
i=l
Bl.
.l.
direct sum.
this we shall do by induction on
If
n
V =
It only remains to show that
(iii)
= l
n
V
1: co
=t- 0
V cp
= dim(V) •
the whole situation is trivial, since eveP}
endomorphism has exactly one eigenvalue; there is exactly one weight
~ , and exactly one weight space
V
q)
= V •
Let
us suppose that the result has been established for all vector spaces potent l f
t
lien
W
of dimension less than
Lie suhalgebras of ever·y
T
l"
L
g,t (\\')
k ;
, and all nil-
•
has just one eigenvalue, say
the minimal polynomial of
fur some integer
n
,-
An
T}
•
( X-ro ( ,- ) )
is of the form
from this it follows that
co(
co
is the
k
one and only weight and
V
Suppose there is a
CD
=
V •
TEL
with einenvalues "'
r
> 1 •
r
where
i
-
(X
i=l
,.
polynomial of
'
then
== 1 , ..• , r
n
p(X) =
Let
.) 1
k.
1
-
f. (X) = (X
and let
V =
),,
1
r I: EB V.1 i=l
' , /\.1,••••I\ . r
he the minimal ),,
.)
k.
1
for
1
(proposition 9 ) •
Uy an argument exactly similar to the one that shows V L c .:p
'Now
it can he seen that
V
-
rp
dim V.
since
n
1 , and the elements of
L
form a nilpotent Lie subal€£ebra of
1
L.1.
which we shall denote by
g_t{V.) . 1
for
V. L c V.
By the induction
co . • : L . - ~ K
hypothesis there exist weights
1J
such that
1
r.
1
v.1 =
EB (V.)
~
1
j=l
for
CO, ,
= l, ... ,r , where the
i
r.
are
1
1J
certain positive integ-ers. Let
n.: 1
for every
be the restriction map:
L~L.
1
a (- L •
are wei~hts for
We assert that the maps
L , and that
=
V
=
~--
and
j lt
, because it is known that
1
(V. )
is clear that
1,1) . .
1J
is the set of all for· all
o t L.1
v
t V.1
and
V
c -
(V. ) 1
V
, ..
-
CJ •.
1=
,1
l
-
,,
1 1J
To see i
0
1J
, since
v(o -
(V. ) J_
CJ) • •
1,1
co .. {c )e ) 0 = O 1J
is the set of all
Ill .. 1J
I1
1
for all
c.p •• 1J
1J
such that
rJ
1,1
(V.)
1J
=
.. =rr.cp ..
1J
VI¥ ..•
E © i, j
V
this it is sufficient to show
~
OTT.1
V
E V
such
that
v{a -
~- .(a)E:)n 1J
=
for all
O
Conversely, :it is evident that .si11ct•
\. l
, .. (-r) 1J
,.
' ..
v ( V.
V
(
V
implies
l.
l.J
1¥1·j·
c(V.) -
1
cp 1,1 •.
~
tv,
>... = q, .. ( 1
I
1J
restricted to
is Uw only eigenvalue of
it follows that V
o EL •
V.]
, and hence that
•
This concludes the proof.
Dt.:..fjn.:i:!:_ion l.].
A Lie subalg;ebra
act indecomposajll;y on
V
if
V
L
of
r;t (V)
is said to
is not the direct sum of
two L-invariant subspaces.
Corollary 18. gt (V)
If
L
is a nilpotent Lie subalgeb~_cL.9f
over an algehrai~_ly closed field which acts
one eigenvalu~.
The converse of Zassenhaus' theorem follows readily
from Engel's theorem; we drop the requirement that al~ehraically closed.
- 42 -
K
he
1=..2..
Corollary
If
L
Let
V L