This book is intended to be a problem-solving book in mathematics. In the current edition, there are around 150 problems
150 66 5MB
English Pages [204]
Table of contents :
Contents
Preface
Acknowledgments
Topics of Olympiad Math
150 Challenges For Mathletes
Solved Challenges
Unsolved Challenges
INMO Problems
TST Problems
Solutions for Solved Problems
About the Authors
Recommended Resources for Olympiad Mathematics
150 Challenges For Mathletes Along with INMO and TST Problems
Pranav M. Sawant Piyush K. Jha Anshuman Shukla
Contents Preface
3
Acknowledgments
4
Topics of Olympiad Math
5
I
9
150 Challenges For Mathletes ……………………………… A.
Solved Challenges………………………………………………..
10
B.
Unsolved Challenges………………………………………….…
20
INMO Problems .…………………………..………………………
44
III Team Selection Test Problems ……………………………….
101
IV Solutions of Solved Problems .……………………………….
181
About the Authors
202
Recommended Resources for Olympiad Mathematics
204
II
Preface Olympiad Mathematics is significantly different from what a normal math student would study in standard math courses such as calculus, pre-calculus, algebra etc. This makes it challenging but at the same time, it is a lot of fun indeed! Mathematics, as you all know, is the essence of science, without which nearly every field of higher study would be impenetrable. Mathematics is, in its way, the poetry of logical ideas. This book is intended to be a problem-solving book in mathematics. In the current edition, there are around 150 problems, crafted by me and my team, at the level of the IOQM (Indian Olympiad Qualifier in Mathematics) / AIME (American Invitational Mathematics Examination) although certain questions involve concepts regularly used in exams such as the USAMO (United States of America Mathematical Olympiad) and the INMO (Indian National Mathematical Olympiad). However we have included certain questions of calculus and real analysis as well. These problems are typically at the level of PUTNAM We have not classified the problems according to the difficulty level as we know that difficulty is a subjective concept and problems that may be hard for some might be very easy for others. Likewise, we have not added the questions topic-wise as most of these questions contain concepts from multiple topics and hence require a good level of analysis and problem-solving abilities across different areas. In the current edition of the book, we have 50 problems with their solutions (labeled as solved problems) and 100 unsolved problems, left as an exercise for the readers. In future editions, I will be looking to add more problems and give hints and solutions for them. If you need any hints or solutions to the unsolved problems, feel free to shoot me an email anytime at [email protected]. At the end of this book, there is a special section for Indian students as well, although it is a good resource for all mathletes. It contains the previous year's INMO (1986-2022) and Indian Team Selection Test (TST) Problems (2001-2019). I have also given certain handouts and book suggestions at the end. Constructive criticism is always welcome and feel free to let me know if you find any errors in this edition. Hope you enjoy this book!
Pranav Sawant India
Acknowledgments This book is a small excursion in my mathematics journey and there is no measure of length when it comes to mentioning who helped me in this journey. A special thanks to Scribe T for helping me with LaTeX and a huge thank you to the editor of this book Anshuman Shukla for the wonderful editing and cover page design. I would also like to thank all my mathematics teachers: Paresh Kokney, Chandrakant Choubey, Prabha Verma, Yury Ustinovskiy, Abhishek Das, Alok Kumar, Prashant Jain, Nikhil Nagaria, Valsamma Varghese, Mini Santhosh and of course, my grandmother and grandfather, without whom I probably would have never loved mathematics. And how can I forget my mom and dad who have supported me throughout the way. A big Thank you to all the institutions and persons who provided me invaluable knowledge and supported me through this journey. Also, a big thank you to all of the AOPS users and members, without you, we would never have a brilliant collection of problems and their elegant solutions on AOPS. Pardon me if I forgot someone! The rights to Indian National Mathematics Olympiad problems and Indian Team Selection Test problems are exclusively held by Homi Bhabha Centre For Science Education (HBCSE) and Mathematics Teachers' Association (India) (MTA(I)).
Topics of Olympiad Math Number Theory ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ●
Euclidean Division Algorithm and Properties of GCD Fundamental Theorem of Arithmetic Sum of divisors and number of divisors Chicken McNugget Theorem Bezout’s Theorem Congruence Modulo Chinese Remainder Theorem and solving basic congruences Fermat’s Little Theorem, Euler’s Totient Function and Euler’s Totient Theorem Wilson’s Theorem and Lucas’s Theorem Order of an Element Primitive Roots Quadratic congruences Quadratic residues, quadratic reciprocity, Legendre’s symbol, Euler’s criterion Cyclotomic Polynomials Lagrange’s Theorem for Polynomials Diophantine equations p-adic valuation and Legendre’s formula Lifting the Exponent Lemma (LTE) Hensel’s Lemma Pell’s equation and its properties Fermat’s last theorem, Catalan Conjecture and Pythagorean triplets Bertrand’s Postulate Zsigmondy’s Theorem
Algebra ● ● ● ● ● ● ● ● ● ● ●
Algebraic Identities Fundamental Theorem of Algebra Polynomial Division and Synthetic Division Veita’s Relations Factor Theorem and Remainder Theorem Rational Root Theorem Binomial Theorem and Multinomial Theorem Complex Numbers Brahmagupta Identity Euler’s Four-Square Identity Sequences and Series
● ● ● ● ● ●
Fibonacci Sequence and its properties Lagrange Interpolation Symmetric Polynomials Chebyshev Polynomials Rouche’s Theorem Intermediate Value Theorem, Lagrange’s Mean Value Theorem, Rolle’s Theorem, Taylor and Maclaurin series. ● Irreducibility Criterions: Gauss’s Lemma, Eisenstien’s and Extended Eisenstien’s Irreducibility criterion, Cohn’s irreducibility criterion and Perron’s Irreducibility criterion. ● Infinite Descent and Vieta’s Root Jumping
Functional Equations ● Domain, co-domain, range, injectivity, surjectivity, bijectivity, involution functions, additive, multiplicative, periodic and cyclic functions ● Cauchy’s Functional Equations ● Jensen’s Functional Equation ● Monotonicity and continuity ● Polynomial Functional Equations
Inequalities ● ● ● ● ● ● ● ● ● ● ● ● ● ● ●
Triangle Inequalities QM-AM-GM-HM Weighted Means Jensen’s Inequality Cauchy Schwarz and Titu’s Inequality Rearrangement Inequality Muirhead’s inequality Holder’s inequality Minkowski Inequality Isoperimetric inequalities Chebyshev’s Inequality Schur’s Inequality Karamata’s Inequality Ravi Substitution Lagrange Multipliers
Geometry ● ● ● ●
Congruence and Similarity of Triangles Angle Chasing, length chasing and trig bashing Cyclic Quadrilaterals Centroid, circumcentre, incentre, orthocentre, incircles and excircles
● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ●
Tangents, Power of a Point and Radical Axis Incentre-Excentre Lemma Nine-point circle Homotheties Ceva’s Theorem and Menelaus Theorem Simson and Symmedian Lines Midpoint of altitudes Isogonal/Isotonic conjugates Cartesian and Barycentric Coordinates Curvilinear and Mixtilinear Incircles Special Points; HM Point, Fermat Point, Isodynamic Point, Bevan Point Inversion and angle conservation in inversion Overlays and orthogonal circles Inversion distance formula Cross Ratio Harmonic Bundles and Quadrilaterals Apollonian Circles Pascal’s Theorem and Projective Transformations Polars/Poles and Bruhcard’s Theorem Brianchon’s Theorem Spiral Symmetry Miquel’s Theorem and Miquel Points Gauss-Bodenmiller Theorem Moving Points and Circle Tangency through Homothety Cayley-Bacharach Theorem Napoleon’s Theorem Sawayama-Thebault Theorem
Combinatorics ● Set Theory, relations and Cartesian Product, image and preimage, composition, cardinality, De-Morgan’s Laws, Venn Diagrams and Syllogism ● Basic counting and Fundamental Theorem of Counting ● Circular Permutations, Selection and Division of Objects, Arrangements and Derangements ● Bijections ● Double Counting ● Recursion ● Principle of Inclusion and Exclusion (PIE) ● Pigeonhole Principle ● Permutation groups, Burnside Counting Lemma and Polya’s Theorem ● Hall’s Marriage Theorem ● Dilworth’s Lemma ● Pascal’s Triangle and Pascal’s Identity
● ● ● ● ● ●
Hockey-Stick Identity Vandermonde’s Identity Bayes Theorem Invariants and monovariants Generating Functions Game Theory
Graph Theory ● Graphs, edges, vertices, faces, adjacent, incident, degree, path, cycle, length of path and cycle, walk, connect/disconnect, tree, forest, Hamiltonian path/cycle, Eulerian circuit, complete, planar, bipartite, k-partite graphs. ● Handshake Lemma ● Euler’s Formula for Planar Graphs ● Kuratowski’s Theorem ● Dirac’s Theorem ● Ore’s Theorem ● Cayley’s Theorem ● Turan’s Lemma ● Four color theorem ● Ramsey Theory ● Zarankiewicz’s Lemma
150 Challenges For Mathletes
Solved Challenges Problem 1.
Let f ( x ) = x3 + ax2 + bx + c and g( x ) = x3 + bx2 + cx + a, where a, b, c
are integers with c ̸= 0. Suppose that the following conditions hold: f (1) = 0, the roots of g( x ) = 0 are the squares of the roots of f ( x ) = 0. Find the value of a2023 + b2023 + c2023 .
Problem 2. if α, β, γ are roots of the equation x3 + 2x2 + 3x + 1 = 0 Find last four digits of α35005 + β35005 + γ35005
Problem 3. In △ ABC, let D be the foot of the altitude from A to BC. Construct squares ABWX and CAYZ outside △ ABC. Let M be the midpoint of XY and P be the intersection of BZ and CW. Prove that M, A, P, and D are collinear.
Problem 4. p √ Define a function g : N → R Such that g( x ) = 4x + 4x+1 + 4x+2 + .... Find the sum of last 4 digits in the decimal representation of g(2023). q
Problem 5. Compute the number of ordered quadruples (w, x, y, z) of complex numbers (not necessarily non-real) such that the following system is satisfied: wxyz = 1 wxy2 + wx2 z + w2 yz + xyz2 = 2 wx2 y + w2 y2 + w2 xz + xy2 z + x2 z2 + ywz2 = −3 w2 xy + x2 yz + wy2 z + wxz2 = −1 10
Solved Challenges Problem 6.
The positive reals x, y, z satisfy the relations x2 + xy + y2 = 1 y2 + yz + z2 = 2 z2 + zx + x2 = 3. √ m−n p
The value of y2 can be expressed uniquely as , where m, n, p, q are positive q integers such that p is not divisible by the square of any prime and no prime dividing q divides both m and n. Compute m + n + p + q
Problem 7.
Solve the equation p +
p
q2 + r =
√
s2 + t in prime numbers.
Problem 8. F ind all functions f : R → R, satisfying the condition f ( x f (y) + f ( x )) = 2 f ( x ) + xy for any real x and y.
Problem 9.
How many f : A → A are there satisfying f ( f ( a)) = a for every
a ∈ A = {1, 2, 3, 4, 5, 6, 7}?
21 times
z }| { Problem 10. W hat is the least positive integer n such that f ( f (. . . f (n))) = 2013 √ where f ( x ) = x + 1 + ⌊ x ⌋? (⌊ a⌋ denotes the greatest integer not exceeding the real number a.) 11
Solved Challenges Problem 11.
How many triples of positive integers ( a, b, c) are there such that
a! + b3 = 18 + c3 ?
Problem 12.
Let x, y, z be real numbers such that x + y + z = 2,
xy + yz + zx = 1
Find the maximum possible value of x − y.
Problem 13.
Let ϕ(n) be the number of positive integers less than n that are
relatively prime to n, where n is a positive integer. Find all pairs of positive integers (m, n) such that 2n + (n − ϕ(n) − 1)! = nm + 1.
Problem 14. L et z1 , z2 , z3 be nonzero complex numbers and pairwise distinct, having the property that (z1 + z2 )3 = (z2 + z3 )3 = (z3 + z1 )3 . Show that |z1 − z2 | = | z2 − z3 | = | z3 − z1 | .
Problem 15.
Show: 8 < 9
Z π/2 0
sin(sinx )dx < 1
12
Solved Challenges Let a ∈ (1, ∞) and a countinuous function f : [0, ∞) −→ R having the
Problem 16. property:
lim x f ( x ) ∈ R.
x →∞
R ∞ f (x) Ra a) Show that the integral 1 x dx and the limit limt→∞ t 1 f x t dx both exist, are finite and equal. R a dx b) Calculate limt→∞ t 1 1+ . xt
For any integer n ≥ 2 denote by An the set of solutions of the equation
Problem 17.
x=
jxk 2
+
jxk 3
+···+
jxk n
.
Determine the set A2 ∪ A3 .
Find all injective functions f : Z → Z that satisfy: | f ( x ) − f (y)| ≤
Problem 18.
| x − y| ,for any x, y ∈ Z.
Determine continuous functions f : R → R such that
Problem 19. a2 + ab + b2
Rb a
Problem 20.
f ( x ) dx = 3
Rb
x2 f ( x ) dx, for every a, b ∈ R .
a
Calculate: lim
n→∞
R1 0
n
e x dx
13
Solved Challenges Problem 21.
Let the matrices of order 2 with the real elements A and B so that
AB = A2 B2 − ( AB)2 and det ( B) = 2. Calculate det ( A + 2B) − det ( B + 2A).
Problem 22.
Find the minimum number of perfect cubes such that their sum is
equal to 346346 .
Problem 23.
Prove that for any integers a, b, the equation 2abx4 − a2 x2 − b2 − 1 = 0
has no integer roots.
Problem 24.
ABCD is a cyclic convex quadrilateral whose diagonals meet at X. The
circle ( AXD ) cuts CD again at V and the circle ( BXC ) cuts AB again at U, such that D lies strictly between C and V and B lies strictly between A and U. Let P ∈ AB ∩ CD. If M is the intersection point of the tangents to U and V at (UPV ) and T is the second intersection of circles (UPV ) and ( PAC ), prove that ∠ PTM = 90o .
Problem 25.
Let ABC be a triangle. Consider the circle ω B internally tangent to
the sides BC and BA, and to the circumcircle of the triangle ABC, let P be the point of contact of the two circles. Similarly, consider the circle ωC internally tangent to the sides CB and CA, and to the circumcircle of the triangle ABC, let Q be the point of contact of the two circles. Show that the incentre of the triangle ABC lies on the segment PQ if and only if AB + AC = 3BC.
14
Solved Challenges 4 x −cos2 x
Problem 26.
Solve the following equation 2sin
Problem 27.
Let a, b, c, d ∈ N∗ such that the equation
4 x −sin2 x
− 2cos
= cos 2x
x2 − ( a2 + b2 + c2 + d2 + 1) x + ab + bc + cd + da = 0 has an integer solution. Prove that the other solution is integer too and both solutions are perfect squares.
Problem 28.
Solve the equation 2023x
Problem 29.
2 +x
+ log2023 x = 2023x+1
In a triangle ABC, where a = BC, b = CA and c = AB, it is known
that: a + b − c = 2 and 2ab − c2 = 4. Prove that ABC is an equilateral triangle.
Problem 30.
Prove that the number 1010 can’t be written as the product of two
natural numbers which do not contain the digit "0" in their decimal representation.
Problem 31.
Show that for every natural n > 1 we have: (n − 1)2 | nn−1 − 1
15
Solved Challenges Problem 32.
Let a, b, c > 0 the sides of a right triangle. Find all real x for which
a x > b x + c x , with a is the longest side.
Problem 33.
(a) Show that for every n ∈ N there is exactly one x ∈ R+ so that
x n + x n+1 = 1. Call this xn . (b) Find lim xn . n→+∞
Problem 34.
Show that for p > 1 we have
1 p + 2 p + ... + (n − 1) p + n p + (n − 1) p + ... + 2 p + 1 p = +∞ n→+∞ n2 lim
Find the limit if p = 1.
Problem 35.
An acute triangle ABC (AB > AC) has circumcenter O, but D is
the midpoint of BC. Circle with diameter AD intersects sides AB and AC in E and F respectively. On segment EF pick a point M so that DM ∥ AO. Prove that triangles ABD and FDM are similar.
∞
Problem 36. I f 1 ≤ r ≤ n are integers, prove the identity:
∑
d =1
n−r+1 d
r−1 d−1
=
n . r
16
Solved Challenges 1
1
1
1
Problem 37.
Show that for every positive integer n, 2 2 · 4 4 · 8 8 · ... · (2n ) 2n < 4.
Problem 38.
Find all non-negative integer x for which
p 3
13 +
√
x+
p 3
13 −
√
x is
an integer.
Problem 39.
Determine all functions f : R → R such that: f (max { x, y} + min { f ( x ), f (y)}) = x + y
for all real x, y ∈ R
Problem 40.
Find all real quadruples ( a, b, c, d) satisfying the system of equations ab + cd = 6 ac + bd = 3 ad + bc = 2 a + b + c + d = 6.
Problem 41.
If tan( x + y + z) =
sin 3x +sin 3y+sin 3z cos 3x +cos 3y+cos 3z ,
compute difference between
maximum and minimum value of R = cos( x + y + z)(cos 3x + cos 3y + cos 3z) + sin( x + y + z)(sin 3x + sin 3y + sin 3z)
17
Solved Challenges Given that x2 + y2 = 1 and 4xy 2x2 − 1 = 1. If the largest possible p √ value of x that satisfies these equations can be expressed as 12 a + b. Find a + b. Problem 42.
Problem 43.
For how many rational numbers p is the area of the triangle formed
by the intercepts and vertex of f ( x ) = − x2 + 4px − p + 1 an integer?
Problem 44.
Compute 1 lim A→+∞ A
Problem 45.
Z A 1
1
A x , dx.
a, b, c, d ∈ R, solve the system of equations: 3 a +b = c b3 + c = d c3 + d = a 3 d +a=b
Problem 46.
f , g : R → R find all f , g satisfying ∀ x, y ∈ R: g( f ( x ) − y) = f ( g(y)) + x.
18
Solved Challenges Problem 47.
Find all pairs of positive integers x, y satisfying the equation y x = x50
Problem 48.
In the isosceles triangle ABC the angle BAC is a right angle. Point D
lies on the side BC and satisfies BD = 2 · CD. Point E is the foot of the perpendicular of the point B on the line AD. Find the angle CED.
Problem 49.
Let k,m and n be three different positive integers. Prove that
Problem 50.
1 k− k
1 m− m
1 n− n
≤ kmn − (k + m + n).
If R and S are two rectangles with integer sides such that the perimeter
of R equals the area of S and the perimeter of S equals the area of R, then we call R and S a friendly pair of rectangles. Find all friendly pairs of rectangles.
19
B. Unsolved Challenges
Problem 51. The sum 44
∑ 2𝑠𝑖𝑛𝑥𝑠𝑖𝑛1[1 + 𝑠𝑒𝑐(𝑥 − 1)𝑠𝑒𝑐(𝑥 + 1)] 𝑥=2 4 𝑛=1
( ) ( ) , where Φ, Ψ are trigonometric functions and θ1,
𝑛 Φ θ𝑛 Ψ θ𝑛
can be written in the form ∑ (− 1)
θ2, θ3, θ4 are degrees ∈ [0, 45]. Find θ1 + θ2 + θ3 + θ4.
Problem 52 A function 𝑓 from the positive integers to the positive integers is called INMO if it satisfies 𝑔𝑐𝑑(𝑓(𝑓(𝑥)), 𝑓(𝑥 + 𝑦)) = 𝑔𝑐𝑑(𝑥, 𝑦) for all pairs of positive integers 𝑥 and 𝑦. Find all positive integers 𝑚 such that 𝑓(𝑚) = 𝑚 for all INMO functions 𝑓.
Problem 53 In △𝐴𝐵𝐶, let 𝐷 be the foot of the altitude from 𝐴 to 𝐵𝐶. Construct squares 𝐴𝐵𝑊𝑋 and 𝐶𝐴𝑌𝑍 outside △𝐴𝐵𝐶. Let 𝑀 be the midpoint of 𝑋𝑌 and 𝑃 be the intersection of 𝐵𝑍 and 𝐶𝑊. Prove that 𝑀, 𝐴, 𝑃, and 𝐷 are collinear.
Problem 54 If the maximum value of 𝑓(θ) = 𝑠𝑖𝑛θ + 𝑠𝑖𝑛3θ + 𝑠𝑖𝑛5θ Across all 𝑅 is of the form
𝑎 𝑏 𝑐
where 𝑔𝑐𝑑(𝑏, 𝑐) = 1 and 𝑎, 𝑏, 𝑐 are positive integers, Where point of maxima is of
the form θ = 𝑎𝑟𝑐𝑠𝑖𝑛
( ) and ℓ, 𝑚 are positive integers. Compute the distance of the point ℓ 𝑚
(ℓ, 𝑚) From the line 𝑎𝑥 + 𝑏𝑦 + 𝑐 = 0 (if ans is a irrational report its greatest integer function)
20
B. Unsolved Challenges Problem 55 Suppose 𝑋, 𝑌, 𝑍 are collinear points in that order such that 𝑋𝑌 = 1 and 𝑌𝑍 = 3. Let 𝑊 be a point such that 𝑌𝑊 = 5, and define 𝑂1 and 𝑂2 as the circumcenters of triangles △𝑊𝑋𝑌 and △𝑊𝑌𝑍, respectively. What is the minimum possible length of segment 𝑂1𝑂2?
Problem 56 If
Then find
(
− 𝑥 + 𝑦)
−2024
Problem 57 The line 𝑦 = 𝑘𝑥 (where 𝑘 is a positive real number) makes an acute angle of ◦
70 with the 𝑥-axis. Point 𝑂 is at the origin and point 𝐴 is at (0, 4). Point 𝑃 is a point on segment 𝑂𝐴 and 𝑀 and 𝑁 are points on the line 𝑦 = 𝑘𝑥. Let
𝑎 𝑏 𝑐
be the minimum possible
value of 𝐴𝑀 + 𝑀𝑃 + 𝑃𝑁 where 𝑎 and 𝑐 are relatively prime and 𝑏 is squarefree. Find 𝑎 + 𝑏 + 𝑐.
Problem 58 Let sequence
and
for all 𝑥, 𝑦 ϵ [𝑎, 𝑏]. Define a
. Show that 𝑥𝑛 converges to a fixed point of 𝑓.
21
B. Unsolved Challenges
Problem 59 Define 𝑓: 𝑅 → 𝑅 be a function such that 𝑁
𝑓(𝑥) = ∑ (𝑖 − 𝑥)(2𝑖 − 𝑥) 𝑖=1
if 𝑆(𝑁) be the set of minimum values of 𝑓(𝑥) for different 𝑁 find number of 𝑁 such that +
subset of 𝑆(𝑁) are also the subset of 𝑍
Problem 60 Consider points 𝐷, 𝐸 and 𝐹 on sides 𝐵𝐶, 𝐴𝐶 and 𝐴𝐵, respectively, of a triangle 𝐴𝐵𝐶, such that 𝐴𝐷, 𝐵𝐸 and 𝐶𝐹 concurr at a point 𝐺. The parallel through 𝐺 to 𝐵𝐶 cuts 𝐷𝐹 and 𝐷𝐸 at 𝐻 and 𝐼, respectively. Show that triangles 𝐴𝐻𝐺 and 𝐴𝐼𝐺 have the same areas.
Problem 61 Let 𝐴𝐵𝐶 be a triangle with 𝐼 as incenter. The incircle touches 𝐵𝐶 at 𝐷. Let 𝐷′ be the antipode of 𝐷 on the incircle. Make a tangent at 𝐷′ to incircle. Let it meet (𝐴𝐵𝐶) at 𝑋, 𝑌 respectively. Let the other tangent from 𝑋 meet the other tangent from 𝑌 at 𝑍. Prove that (𝑍𝐵𝐷) meets 𝐼𝐵 at the midpoint of 𝐼𝐵
Problem 62 For a positive integer 𝑛, denote by 𝑔(𝑛) the number of strictly ascending triples chosen from the set {1, 2, ..., 𝑛}. Find the least positive integer 𝑛 such that the following holds: The number 𝑔(𝑛) can be written as the product of three different prime numbers which are (not necessarily consecutive) members in an arithmetic progression with common difference 336.
{ }𝑛≥1 and {𝑏𝑛}𝑛≥1 be two infinite arithmetic progressions, each of which
Problem 63 Let 𝑎𝑛
the first term and the difference are mutually prime natural numbers. It is known that for
22
B. Unsolved Challenges
(
2
)(
2
2
2
)
any natural 𝑛, at least one of the numbers 𝑎𝑛 + 𝑎𝑛+1 𝑏𝑛 + 𝑏𝑛+1 or
(𝑎
2 𝑛
2
)(
2
2
)
+ 𝑏𝑛 𝑎𝑛+1 + 𝑏𝑛+1 is a perfect square. Prove that 𝑎𝑛 = 𝑏𝑛, for any natural 𝑛.
Problem 64 Let .
Find
Problem 65 A tournament is played between 𝑛 people. Everyone plays with everyone else, and no game ends in a draw. A number 𝑘 is said to be 𝑛-good if there exists such a tournament in which there is, for every 𝑘 people, a player who has lost all of them. a) Prove that 𝑛 ≥ 2
𝑘+1
− 1 b) Give all 𝑛 for which 2 is 𝑛-good.
Problem 66 For a positive integer 𝑛, two players 𝐴 and 𝐵 play the following game: Given a pile of 𝑠 stones, the players take turn alternatively with 𝐴 going first. On each turn the player is allowed to take either one stone, or a prime number of stones, or a positive multiple of 𝑛 stones. The winner is the one who takes the last stone. Assuming both 𝐴 and 𝐵 play perfectly, for how many values of 𝑠 the player 𝐴 cannot win?
Problem 67 Let 𝑀(𝑛) = {𝑛, 𝑛 + 1, 𝑛 + 2, 𝑛 + 3, 𝑛 + 4, 𝑛 + 5} be a set of 6 consecutive integers. Let’s take all values of the form 𝑎 𝑏
+
𝑐 𝑑
+
𝑧 𝑤
=
+
𝑒 𝑓
with the set {𝑎, 𝑏, 𝑐, 𝑑, 𝑒, 𝑓 = 𝑀(𝑛)}. Let 𝑥 𝑢
+
𝑦 𝑣
𝑥𝑣𝑤+𝑦𝑢𝑤+𝑧𝑢𝑣 𝑢𝑣𝑤
be the greatest of all these values.
23
B. Unsolved Challenges a) show: for all odd 𝑛 hold: 𝑔𝑐𝑑(𝑥𝑣𝑤 + 𝑦𝑢𝑤 + 𝑧𝑢𝑣, 𝑢𝑣𝑤) = 1 iff 𝑔𝑐𝑑(𝑥, 𝑢) = 𝑔𝑐𝑑(𝑦, 𝑣) = 𝑔𝑐𝑑(𝑧, 𝑤) = 1. b) for which positive integers 𝑛 hold 𝑔𝑐𝑑(𝑥𝑣𝑤 + 𝑦𝑢𝑤 + 𝑧𝑢𝑣, 𝑢𝑣𝑤) = 1?
𝑛
Problem 68 A polynomial 𝑝(𝑥) of degree 1000 is such that 𝑝(𝑛) = (𝑛 + 1)2 for all nonnegative integers 𝑛 such that 𝑛 ≤ 1000. Given that 𝑏
𝑝(1001) = 𝑎 · 2 − 𝑐, where 𝑎 is an odd integer, and 0 < 𝑐 < 1001, find 𝑐 − (𝑎 + 𝑏))
Problem 69 Call a convex quadrilateral angle-Pythagorean if the degree measures of its angles are integers 𝑤 ≤ 𝑥 ≤ 𝑦 ≤ 𝑧 satisfying 2
2
2
2
𝑤 +𝑥 +𝑦 =𝑧 . Determine the maximum possible value of 𝑥 + 𝑦 for an angle-Pythagorean quadrilateral.
Problem 70 One can define the greatest common divisor of two positive rational numbers as follows: for 𝑎, 𝑏, 𝑐, and 𝑑 positive integers with 𝑔𝑐𝑑(𝑎, 𝑏) = 𝑔𝑐𝑑(𝑐, 𝑑) = 1, write 𝑔𝑐𝑑
(
𝑎 𝑏
,
𝑐 𝑑
)=
𝑔𝑐𝑑(𝑎𝑑,𝑏𝑐) 𝑏𝑑
.
For all positive integers 𝐾, let 𝑓(𝐾) denote the number of ordered pairs of positive rational numbers (𝑚, 𝑛) with 𝑚 < 1 and 𝑛 < 1 such that 𝑔𝑐𝑑(𝑚, 𝑛) =
What is
1 𝐾
.
?
24
B. Unsolved Challenges
Problem 71 Euclid places a morsel of food at the point (0, 0) and an ant at the point (1, 2). Every second, the ant walks one unit in one of the four coordinate directions. However, whenever the ant moves to (𝑥, ± 3), Euclid’s notorious friend uncle chipotle picks it up and puts it at (− 𝑥, ∓ 2), and whenever it moves to (± 2, 𝑦), his cousin uncle john puts it at 𝑝 (∓ 1, 𝑦), If 𝑝 and 𝑞 are relatively prime positive integers such that 𝑞 is the expected number of steps the ant takes before reaching the food, find 𝑝 + 𝑞.
Problem 72 Determine all the triples {𝑎, 𝑏, 𝑐} of positive integers coprime (not necessarily pairwise prime) such that 𝑎 + 𝑏 + 𝑐 simultaneously divides the three numbers 12
𝑎
12
+𝑏
23
12
+ 𝑐 ,𝑎
23
+𝑏
23
+𝑐
11004
and 𝑎
11004
+𝑏
11004
+𝑐
Problem 73 In a group of 2021 people, 1400 of them are squid game runners. James Bond wants to find one squid game runner. There are some missions that each need exactly 3 people to be done. A mission fails if at least one of the three participants in that mission is a squid game runner. In each round James chooses 3 people, sends them to a mission and sees whether it fails or not. What is the minimum number of rounds he needs to accomplish his goal?
Problem 74 𝑛 > 1 is an odd number and 𝑎1, 𝑎2, ···, 𝑎𝑛 are positive integers such that
(
)
𝑔𝑐𝑑 𝑎1, 𝑎2, ···, 𝑎𝑛 = 1. If
(
𝑛
𝑛
𝑛
)
𝑑 = 𝑔𝑐𝑑 𝑎1 + 𝑎1 · 𝑎2 ··· 𝑎𝑛, 𝑎2 + 𝑎1 · 𝑎2 ··· 𝑎𝑛, ···, 𝑎𝑛 + 𝑎1 · 𝑎2 ··· 𝑎𝑛 find all possible values of 𝑑.
25
B. Unsolved Challenges
Problem 75 A complete number is a 9 digit number that contains each of the digits 1 to 9 exactly once. The difference number of a number 𝑁 is the number you get by taking the differences of consecutive digits in 𝑁 and then stringing these digits together. For instance, the difference number of 25143 is equal to 3431. The complete number 124356879 has the additional property that its difference number, 12121212, consists of digits alternating between 1 and 2. Determine all 𝑎 with 3 ≤ 𝑎 ≤ 9 for which there exists 𝑎 complete number 𝑁 with the additional property that the digits of its difference number alternate between 1 and 𝑎.
◦
Problem 76 𝐴𝐵𝐶 is a right angled triangle with ∠𝐴 = 90 and 𝐷 be the midpoint of 𝐵𝐶. A point 𝐹 is chosen on 𝐴𝐵. 𝐶𝐴 and 𝐷𝐹 meet at 𝐺 and 𝐺𝐵 ‖ 𝐴𝐷. 𝐶𝐹 and 𝐴𝐷 meet at 𝑂 and 2 𝐴𝐹 = 𝐹𝑂. 𝐺𝑂 meets BC at 𝑅. Find The sides of 𝐴𝐵𝐶 if the area of 𝐺𝐷𝑅 is 15
Problem 77 Shishimaru and hattori play a game. 2021 stones lie on a table. Starting with shishimaru, they alternatively remove stones from the table, while obeying the following rule. At the 𝑛-th turn, the active player (shishimaru if 𝑛 is odd, hattori if 𝑛 is even) can remove from 1 to 𝑛 stones. Thus, shishimaru first removes 1 stone; then, hattori can remove 1 or 2 stones, as she wishes; then, shishimaru can remove from 1 to 3 stones, and so on. The player who removes the last stone on the table loses, and the other one wins. Which player has a strategy to win regardless of the other player’s moves?
Problem 78 You have a 3 × 2021 chessboard from which one corner square has been removed. You also have a set of 3031 identical dominoes, each of which can cover two adjacent chessboard squares. Let 𝑚 be the number of ways in which the chessboard can be covered with the dominoes, without gaps or overlaps. What is the remainder when 𝑚 is divided by 19?
Problem 79 Let 𝑀 be the midpoint of segment 𝐵𝐶 of △𝐴𝐵𝐶. Let 𝐷 be a point such that 𝐴𝐷 = 𝐴𝐵, 𝐴𝐷 ⊥ 𝐴𝐵 and points 𝐶 and 𝐷 are on different sides of 𝐴𝐵. Prove that: 𝐴𝐵 · 𝐴𝐶 + 𝐵𝐶 · 𝐴𝑀 ≥
2 2
𝐶𝐷. 26
B. Unsolved Challenges
Problem 80 Let 𝑇1 = 8, 𝑇2 = 8, 𝑇𝑛 = (𝑇𝑛−1 + 𝑇𝑛−2)𝑚𝑜𝑑 10. Then find the value of 𝑇42.
Problem 81 Doraemon is a robot who can move freely on the unit circle and its interior, but is attached to the origin by a retractable cord such that at any moment the cord lies in a straight line on the ground connecting doraemon to the origin. Whenever his movement is counterclockwise (relative to the origin), the cord leaves a coating of black paint on the ground, and whenever his movement is clockwise, the cord leaves a coating of black paint on the ground, and whenever his movement is clockwise, the cord leaves a coating of orange paint on the ground. The paint is dispensed regardless of whether there is already 2
paint on the ground. The paints covers 1 liter/unit , and doraemon starts at (1, 0).Each second, he moves in a straight line from the point (𝑐𝑜𝑠(θ), 𝑠𝑖𝑛(θ)) to the point ◦
(𝑐𝑜𝑠(θ + 𝑎), 𝑠𝑖𝑛(θ + 𝑎)), where 𝑎 changes after each movement. 𝑎 starts out as 253 and ◦
decreases by 2 each step. If he takes 89 steps, then the difference, in liters, between the amount of black paint used and orange paint used can be written as
𝑎− 𝑏 𝑐
◦
𝑐𝑜𝑡1 , where 𝑎, 𝑏
and 𝑐 are positive integers and no prime divisor of 𝑐 divides both 𝑎 and 𝑏 twice. Find 𝑎 + 𝑏 + 𝑐. Problem 82 Cynthia loves Pokemon and she wants to catch them all. In victory Road, there are a total of 80 Pokemon. Cynthia wants to catch as many of them as possible. However, she cannot catch any two Pokemon that are enemies with each other. After exploring around for a while, she makes the following two observations: 1. Every Pokemon in Victory Road is enemies with exactly two other Pokemon. 2. Due to her inability to catch Pokemon that are enemies with one other, the maximum number of the Pokemon she can catch is equal to 𝑛. What is the sum of all possible values of 𝑛?
Problem 83 In △𝐴𝐵𝐶, 𝐴𝐵 = 4, 𝐵𝐶 = 5, and 𝐶𝐴 = 6. Circulars arcs 𝑝, 𝑞 and 𝑟 of measure ◦
60 are drawn from 𝐴 to 𝐵, from 𝐴 to 𝐶, and from 𝐵 to 𝐶, respectively, so that 𝑝, 𝑞 lie completely outside △𝐴𝐵𝐶 but 𝑟 does not. Let 𝑋, 𝑌, 𝑍 be the midpoint of 𝑝, 𝑞, 𝑟, respectively. If 𝑠𝑖𝑛∠𝑋𝑍𝑌 =
𝑎 𝑏+𝑐 𝑑
, where 𝑎, 𝑏, 𝑐, 𝑑 are positive integers, 𝑔𝑐𝑑(𝑎, 𝑐, 𝑑) = 1, and 𝑏 is not
divisible by the square of a prime, compute 𝑎 + 𝑏 + 𝑐 + 𝑑.
27
B. Unsolved Challenges
Problem 84 On a table near the sea, there are 𝑁 glass boxes where 𝑁 < 2021, each containing exactly 2021 balls. Sowdha and Rafi play a game by taking turns on the boxes where Sowdha takes the first turn. In each turn, a player selects a non-empty box and throws out some of the balls from it into the sea. If a player wants, he can throw out all of the balls in the selected box. The player who throws out the last ball wins. Let 𝑆 be the sum of all values of 𝑁 for which Sowdha has a winning strategy and let 𝑅 be the sum of all values 𝑅−𝑆 of 𝑁 for which Rafi has a winning strategy. What is the value of 10
Problem 85 A series of lockers, numbered 1 through 100, are all initially closed. Student 1 goes through and "flips" every 3rd locker ("flipping") a locker means changing its state: if the locker is open he closes it, and if the locker is closed he opens it. Thus, Student 3 will close the third locker, open the sixth, close the ninth Student 5 then goes through and "flips" every 5th locker. This process continues with all students with odd numbers 𝑛 < 100 going through and "flipping" every 𝑛-th locker. How many lockers are open after this process?
Problem 86 Say there is a polynomial with integral coefficients such that there exists four distinct integers such that 𝑓 𝐼1 = 𝑓 𝐼2 = 𝑓 𝐼3 = 𝑓 𝐼4 = 2021, find sum of all such
( )
( )
( )
( )
integers such 𝐼′ such that 𝑓(𝐼′) = 2023. [note 𝐼𝑖 is integer for 𝑖 = 1, 2, 3, ··· 𝑛]
Problem 87 There is a table with 𝑛 rows and 18 columns. Each of its cells contains a 0 or a 1. The table satisfies the following properties: 1) Every two rows are different. 2) Each row contains exactly 6 cells that contain 1. 3) For every three rows, there exists a column so that the intersection of the column with the three rows (the three cells) all contains 0. What is the greatest possible value of 𝑛?
28
B. Unsolved Challenges
Problem 88 On a party with 99 guests, hosts shin chan and masao play a game (the hosts are not regarded as guests). There are 99 chairs arranged in a circle; initially, all guests hang around those chairs. The hosts take turns alternately. By a turn, a host orders any standing guest to sit on an unoccupied chair 𝑐. If some chair adjacent to 𝑐 is already occupied , the same host orders one guest on such chair to stand up (if both chairs adjacent to 𝑐 are occupied, the host chooses exactly one of them). All orders are carried out immediately. shinchan makes the first move; her goal is to fulfill, after some move of hers, that at least 𝑘 chairs are occupied. Determine the largest 𝑘 for which shinchan can reach the goal, regardless of masao play.
Problem 89 Find all positive integer 𝑚 such that there exist an infinite AP (𝑎𝑛) and an infinite GP of positive integer such that 𝑚|𝑎𝑛 − 𝑔𝑛 for all 𝑛 ≥ 1 and 𝑚|𝑎2 − 𝑎1.
Problem 90 Vertices of a triangle are taken from the set A,B,C in the same order and its sides are extended to vertices P,Q,R in same order. if BP is thrice of AB, RC is twice of AC and 𝑎 BQ is just half of BC. if ratio of △𝐴𝐵𝐶 to △𝑃𝑄𝑅 is in form 𝑏 where a and b are positive 2
2
integers and 𝑔𝑐𝑑(𝑎, 𝑏) = 1, find 5𝑎 + 𝑏
Problem 91 201 positive integers are written on a line, such that both the first one and the last one are equal to 19999. Each one of the remaining numbers is less than the average of its neighboring numbers, and the differences between each one of the remaining numbers and the average of its neighboring numbers are all equal to a unique integer. Find the second-to-last term on the line
Problem 92 Points 𝑋 and 𝑌 are the midpoints of arcs 𝐴𝐵 and 𝐵𝐶 of the circumscribed circle of triangle 𝐴𝐵𝐶. Point 𝑇 lies on side 𝐴𝐶. It turned out that the bisectors of the angles 𝐴𝑇𝐵 and 𝐵𝑇𝐶 pass through points 𝑋 and 𝑌 respectively. What angle 𝐵 can be in triangle 𝐴𝐵𝐶 ?
29
B. Unsolved Challenges
Problem 93 In △𝐴𝐵𝐶 the median 𝐴𝑀 is drawn. the foot of perpendicular from 𝐵 to the angle bisector of ∠𝐵𝑀𝐴 is 𝐵1 and the foot of perpendicular from 𝐶 to the angle bisector of ∠𝐴𝑀𝐶 is 𝐶1. Let 𝑀𝐴 and 𝐵1𝐶1 intersect at 𝐴1. Find
𝐵1𝐴1 𝐴1𝐶1
.
Problem 94 Kalia has 3 red color ice cream and 3 black color ice cream. Find the number of distinct ways that kalia can place these checkers in stacks. Two ways of stacking ice creams are the same if each stack of the rest way matches a corresponding stack in the second way in both size and color arrangement. So, for example, the 3 stack arrangement 𝑅𝐵𝑅, 𝐵𝑅, 𝐵 is distinct from 𝑅𝐵𝑅, 𝑅𝐵, 𝐵, but the 4 stack arrangement 𝑅𝐵, 𝐵𝑅, 𝐵, 𝑅 is the same as 𝐵, 𝐵𝑅, 𝑅, 𝑅𝐵.
Problem 95 A water bottle (cylindrical in shape) stands upon a horizontal table. from a point on this plane, a man stares the cap of the water bottle, from which four of its corner ◦
◦
◦
points are visible, their angular elevations from the eye of the observer are 30 , α , 30 and ◦
60 . assuming the cap of the bottle to be perfectly circular and ratio of circumference of bottle cap to circular base of cylinder to be 1:1. find distance of point from the observer ◦
which subtends the α , from the observer’s eye, also find alpha and sum of distance of the ◦
◦
distance between the eye and points that subtended 30 , 60 given that the point which subtend angle α is in the extended line of sight of first point from the observer, horizontal distance between contact point and point at which the angle α is subtended is 6 units, and distance between first point and the point at which the first point subtends angle is 4 units
Problem 96 Find the number of pairs (𝑛, 𝑞), where 𝑛 is a positive integer and 𝑞 a 𝑛! { 2} { 2000 }
non-integer rational number with 0 < 𝑞 < 2000, that satisfy 𝑞 =
30
B. Unsolved Challenges
Problem 97 Suppose 𝐴𝐵𝐶𝐷 is a trapezoid with 𝐴𝐵 ‖ 𝐶𝐷 and 𝐴𝐵 ⊥ 𝐵𝐶. Let 𝑋 be a point on segment 𝐴𝐷 such that 𝐴𝐷 bisects ∠𝐵𝑋𝐶 externally, and denote 𝑌 as the intersection of 𝐴𝐶 and 𝐵𝐷. If 𝐴𝐵 = 10 and 𝐶𝐷 = 15, compute the maximum possible value of 𝑋𝑌.
Problem 98 21 bandits live in the city of Wasseypur, each of them having some enemies among the others. Initially each bandit has 240 bullets, and duels with all of his enemies. Every bandit distributes his bullets evenly between his enemies, this means that he takes the same number of bullets to each of his duels, and uses each of his bullets in only one duel. In case the number of his bullets is not divisible by the number of his enemies, he takes as many bullets to each duel as possible, but takes the same number of bullets to every duel, so it is possible that in the end the bandit will have some remaining bullets. Shooting is banned in the city, therefore a duel consists only of comparing the number of bullets in the guns of the opponents, and the winner is whoever has more bullets. After the duel the police take the bullets of the winner and as an act of protest the loser shoots all of his bullets into the air. What is the largest possible number of bullets the police can have after all of the duels have ended? Being someone's enemy is mutual. If two opponents have the same number of bullets in their guns during a duel, then the police take the bullets of the bandit who has the wider hat among them. Example: If a bandit has 13 enemies then he takes 18 bullets with himself to each duel, and they will have 6 leftover bullets after finishing all their duels.
Problem 99 Define 12
𝑃(𝑥) = 𝑥
11
+ 12𝑥
10
+ 66𝑥
9
8
7
6
5
4
3
2
+ 220𝑥 + 495𝑥 + 792𝑥 + 924𝑥 + 792𝑥 − 159505𝑥 + 220𝑥 + 66𝑥 + 12𝑥 + 1
Find sum of digits of integers
𝑃(19) 4
20
.
Problem 100 Triangle 𝐴𝐵𝐶 is inscribed in circle ω with 𝐴𝐵 = 5, 𝐵𝐶 = 7, and 𝐴𝐶 = 3. The bisector of angle 𝐴 meets sid 𝐵𝐶 at 𝐷 and circle ω at a second point 𝐸. Let γ be the circle
31
B. Unsolved Challenges 2
with diameter 𝐷𝐸. Circles ω and γ meet at 𝐸 and a second point 𝐹. Then 𝐴𝐹 =
𝑚 𝑛
, where 𝑚
and 𝑛 are relatively prime positive integers. Find 𝑚 + 𝑛.
Problem 101 Let 𝑚 ≥ 𝑛 be positive integers. MOTU is given 𝑚𝑛 posters of patlu with different integer dimensions of 𝑘 × 𝑙 with 1 ≥ 𝑘 ≥ 𝑚 and 1 ≥ 𝑙 ≥ 𝑛. He must put them all up one by one on his bedroom wall without rotating them. Every time he puts up a poster, he can either put it on an empty spot on the wall or on a spot where it entirely covers a single visible poster and does not overlap any other visible poster. Determine the minimal area of the wall that will be covered by posters.
Problem 102 Bheem and raju are playing a game. raju has 𝑘 +
( ) cards with their front 𝑘 2
sides face down on the table. The cards are constructed as follows: For each 1 ≤ 𝑛 ≤ 𝑘, there is a blue card with 𝑛 written on the back, and a fraction
(
)
𝑎𝑛 𝑏𝑛
written on the front,
where 𝑔𝑐𝑑 𝑎𝑛, 𝑏𝑛 = 1 and 𝑎𝑛, 𝑏𝑛 > 0. For each 1 ≤ 𝑖 < 𝑗 ≤ 𝑘, there is a red card with (𝑖, 𝑗) written on the back, and a fraction
𝑎𝑖+𝑎𝑗 𝑏𝑖+𝑏𝑗
written on the front. It is given that no two
cards have equal fractions. In a turn bheem can pick any two cards and raju tells bheem which card has the larger fraction on the front. Show that, in fewer than 10000 turns, bheem can determine which red card has the largest fraction out of all of the red cards.
Problem 103 There are three flies of negligible size that start at the same position on a circular track with circumference 1000 meters. They fly clockwise at speeds of 2, 6, and 𝑘 meters per second, respectively, where 𝑘 is some positive integer with 7 ≤ 𝑘 ≤ 1000. Suppose that at some point in time, all three flies meet at a location different from their starting point. How many possible values of 𝑘 are there?
32
B. Unsolved Challenges
Problem 104 The number of sequences 𝑎𝑛 of 2𝑛 terms can be formed using exactly 𝑛(1’s) 𝑘
(
)
ans exactly 𝑛(-1’s) whose partial sums are always non negative: ∑ 𝑎𝑖 ≥ 0 , 1 ≤ 𝑘 ≤ 2𝑛 𝑖=1
Problem 105 Is there a number 𝑛 such that one can write 𝑛 as the sum of 2022 perfect squares and (with at least) 2022 distinct ways?
Problem 106 Let 𝑀 be a set of six distinct positive integers whose sum is 60. These numbers are written on the faces of a cube, one number to each face. A move consists of choosing three faces of the cube that share a common vertex and adding 1 to the numbers on those faces. Determine the number of sets 𝑀 for which it’s possible, after a finite number of moves, to produce a cube all of whose sides have the same number.
Problem 107 While running from an unrealistically rendered zombie, uncle chipotle runs into a vacant lot in the shape of a square, 100 meters on a side. Call the four corners of the lot corners 1, 2, 3, and 4, in clockwise order. For 𝑘 = 1, 2, 3, 4, let 𝑑𝑘 be the distance between chipotle and corner 𝑘. Let (a) 𝑑1 < 𝑑2 < 𝑑4 < 𝑑3, (b) 𝑑2 is the arithmetic mean of 𝑑1 and 𝑑3, and (c) 𝑑4 is the geometric mean of 𝑑2 and 𝑑3. 2
If 𝑑1 can be written in the form
𝑎−𝑏 𝑐 𝑑
, where 𝑎, 𝑏, 𝑐, and 𝑑 are positive integers, 𝑐 is
square-free, and the greatest common divisor of 𝑎, 𝑏, and 𝑑 is 1, find the sum of all possible remainder when 𝑎 + 𝑏 + 𝑐 + 𝑑 is divided by 1000.
33
B. Unsolved Challenges
Problem 108 To any triangle with side lengths 𝑎, 𝑏, 𝑐 and the corresponding angles α, β, γ (measured in radians), the 6-tuple (𝑎, 𝑏, 𝑐, α, β, γ) is assigned. Find the minimum possible number 𝑛 of distinct terms in the 6-tuple assigned to a scalene triangle.
Problem 109 Rama and bholi play a game writing numbers on a board as follows: The two players play in turns and if in the board is written the positive integer 𝑛, the player whose turn is chooses a prime divisor 𝑝 of 𝑛 and writes the numbers 𝑛 + 𝑝. In the board, it is written at the start number 2 and Rama plays first. The game is won by whoever shall be first able to write a number bigger or equal to 31. Find who player has a winning strategy, that is who may write the appropriate numbers may win the game no matter how the other player plays.
Problem 110 Find all positive integers 𝑛 such that the number 6
3
𝑛 + 5𝑛 + 4𝑛 + 116 is the product of two or more consecutive numbers.
Problem 111 Laxman has a standard four-sided die. Each roll, he gains points equal to the value of the roll multiplied by the number of times he has now rolled that number; for example, if his first rolls were 3, 3, 2, 3, he would have 3 + 6 + 2 + 9 = 20 points. Find the expected number of points laxman will have after the die 25 times.
Problem 112 Raiyan stands on the bottom-left square of a 2022 by 2022 grid of squares, where each square is colored either black, gray, or white according to the pattern as depicted to the right. Each second he moves either one square up, one square to the right, or both one up and to the right, selecting between these three options uniformly and independently. Noting that he begins on a black square, find the probability that Raiyan is still on a black square after 2022 seconds.
34
B. Unsolved Challenges
Problem 113 Find number of integer from 0 to 2022 such that
(𝑛(𝑛+1)(2𝑛+1))! is an ((𝑛−1)𝑛(2𝑛+5))!
integer.
Problem 114 Simplify 𝑛
∑
(2𝑛)! 2
2
𝑘=0 (𝑘!) ((𝑛−𝑘)!)
.
2
2
Problem 115 Find all pairs of positive integers (𝑚, 𝑛) such that 𝑚 − 𝑚𝑛 + 𝑛 + 1 divides both numbers 3
𝑚+𝑛
3
+ (𝑚 + 𝑛)! and 3
3
𝑚 +𝑛
+ 𝑚 + 𝑛.
Problem 116 𝑂 is the circumcenter of △𝐴𝐵𝐶 and 𝐶𝐷 is the median to 𝐴𝐵. 𝐺 is the centroid of △𝐴𝐶𝐷. Prove that 𝑂𝐺 is perpendicular to 𝐶𝐷 only and only if △𝐴𝐵𝐶 is isosceles with 𝐴𝐵 = 𝐴𝐶.
Problem 117 let be a natural number 𝑛, and 𝑛 real numbers 𝑎1, 𝑎2, ···, 𝑎𝑛. Prove that there exists a real number 𝑎 such that 𝑎 + 𝑎1, 𝑎 + 𝑎2, ···, 𝑎 + 𝑎𝑛 are all irrational.
Problem 118 In a ∆𝑃𝑄𝑅 𝑋ϵ𝑃𝑄 𝑎𝑛𝑑 𝑌ϵ𝑃𝑅, if ∠QPR = 30° such that PQ = 7 and PR = 8, computer minimum value of the distance QY + XR + XY.
35
B. Unsolved Challenges
Problem 119 given a 4-digit number (𝑎𝑏𝑐𝑑)10 such that both (𝑎𝑏𝑐𝑑)10 and (𝑑𝑐𝑏𝑎)10 are multiples of 7, having the same remainder modulo 37. Find 𝑎, 𝑏, 𝑐, 𝑑
3
Problem 120 Let 𝑁 be the number of ordered triples (𝑎, 𝑏, 𝑐) ∈ {1, ···, 2022} such that 2
2
2
𝑎 + 𝑏 + 𝑐 = 0 ( 𝑚𝑜𝑑 2023). What are the last three digits of 𝑁?
𝑘
Problem 121 Find 𝑘 where 2 is the largest power of 2 that divides tha product 2022 · 2023 · 2024 ··· 4048.
4
Problem 122 Vijay picks two random distinct primes 1 ≤ 𝑝, 𝑞 ≤ 10 . Let 𝑟 be the 2205403200
probability that 3 , 𝑓 are decimal digits.
≡ 1 𝑚𝑜𝑑 𝑝𝑞. Estimate 𝑟 in the form 0. 𝑎𝑏𝑐𝑑𝑒𝑓, where 𝑎, 𝑏, 𝑐, 𝑑, 𝑒
𝑝−1 2
{
2
}
Problem 123 Determine the number of primes 𝑝 < 100 such that ∑ 𝑘 𝑝 is an integer, 𝑘=1
where {𝑥} = 𝑥 − [𝑥].
36
B. Unsolved Challenges
Problem 124 Let 𝑓(𝑥) = Φ(𝑥)Ψ(𝑥), where Φ(𝑥) and Ψ(𝑥) are monic polynomials of positive degree with integer coefficients. Then prove at least one of the polynomials Φ(𝑥) and Ψ(𝑥) is recursive.
Problem 125 Find all positive integer solutions (𝑎, 𝑏, 𝑐) to the function 2
2
2
𝑎 + 𝑏 + 𝑐 = 2005, where 𝑎 ≤ 𝑏 ≤ 𝑐.
Problem 126 Let 𝑆 be a set of 𝑛 distinct real numbers. Let 𝐴𝑆 be the set of numbers that occur as averages of two distinct elements of 𝑆. For a given 𝑛 ≥ 2, what is the smallest possible number of elements in 𝐴𝑆?
Problem 127 The incircle of a triangle ABC touches the sides BC and AC at point D and E, respectively. Suppose P is the point on the shorter arc DE of the incircle such that Angle APE = Angle DPB. The segments AP and BP meet the segment DE at points K and L, respectively. If KL = 4 find DE.
Problem 128 A sequence of positive integers 𝑎1, 𝑎2, 𝑎3, 𝑎4 ··· 𝑎𝑛 (necessarily not in same order or order of ascending or descending), such that 𝑛 ≤ 99, if
(
)2 − 4(𝑎𝑛)(𝑎𝑛+1) + (𝑎𝑛)2 = 0, find number of possible values of 𝑎1.
4 𝑎𝑛+1
Problem 129 There are three distinct positive integers, 𝑎, 𝑏, 𝑐 where 1 ≤ 𝑎, 𝑏, 𝑐 ≤ 100. 𝑐
𝑐
How many ways are there for 𝑎 + 𝑏 to be divisible by 130.
37
B. Unsolved Challenges
Problem 130 Let 𝑋 = {1, 2, 3,..., 𝑛} where 𝑛ϵ𝑁 define Compute number of injective functions possible from 𝑋 → 𝑆.
.
Problem 131 In triangle △𝐴𝐵𝐶, the points 𝐴′, 𝐵′, 𝐶′ are on sides 𝐵𝐶, 𝐴𝐶, 𝐴𝐵 respectively. Also, 𝐴𝐴′, 𝐵𝐵′, 𝐶𝐶′ intersect at the point 𝑂 (they are concurrent at 𝑂). Also, 𝐴𝑂 𝐵𝑂 𝐶𝑂 𝐴𝑂 𝐵𝑂 𝐶𝑂 + 𝑂𝐵′ + 𝑂𝐶′ = 92. Find the value of 𝑂𝐴′ × 𝑂𝐵′ × 𝑂𝐶′ . 𝑂𝐴′
Problem 132 Let 𝐼 be the incenter of a triangle 𝐴𝐵𝐶. 𝐷, 𝐸, 𝐹 are the symmetric points of 𝐼 with respect to 𝐵𝐶, 𝐴𝐶, 𝐴𝐵 respectively. Knowing that 𝐷, 𝐸, 𝐹, 𝐵 are concyclic, find all possible values of ∠𝐵.
Problem 133 Given is a triangle 𝐴𝐵𝐶 and points 𝐷 and 𝐸, respectively on 𝐵𝐶 and 𝐴𝐵. 𝐹 it is intersection of lines 𝐴𝐷 and 𝐶𝐸. We denote as |𝐶𝐷| = 𝑎, |𝐵𝐷| = 𝑏, |𝐷𝐹| = 𝑐 and |𝐴𝐹| = 𝑑. |𝐵𝐸| Determine the ratio |𝐴𝐸| in terms of 𝑎, 𝑏, 𝑐 and 𝑑
Problem 134 Jamuna lowers five matching wooden discs over bars placed on the vertices of a regular pentagon. Then she leaves five smaller congruent checkers these rods drop. Then she stretches a ribbon around the large discs and a second ribbon around the small discs. The first ribbon has a length of 56 centimeters and the second one of 50 centimeters. jamuna looks at her construction from above and sees an area demarcated by the two ribbons, what is the area of that area
38
B. Unsolved Challenges
Problem 135 Find the number of pairs of integers (𝑥, 𝑦) such that: 2
6(𝑥! + 3) = 𝑦 + 5
Problem 136 How many ways can the vertices of a cube be colored red or blue so that the color of each vertex is the color of the majority of the three vertices adjacent to it?
Problem 137 Consider the following three lines in the Cartesian plane: {ℓ1: 2𝑥 − 𝑦 = 7 ℓ2: 5𝑥 + 𝑦 = 42 ℓ3: 𝑥 + 𝑦 = 14 and let 𝑓𝑖(𝑃) correspond to the reflection of the point 𝑃 across ℓ𝑖. Suppose 𝑋 and 𝑌 are
( (
)) = 𝑌. Let 𝑡 be the length of
points on the 𝑥 and 𝑦 axes, respectively. such that 𝑓1 𝑓2 𝑓3(𝑋) 2
segment 𝑋𝑌; what is the sum of all possible values of 𝑡 ?
Problem 138 Let 𝐴𝐵𝐶 be a triangle. Let Ω denote the incircle of △𝐴𝐵𝐶 having radius 𝑟𝑜. Draw tangents to Ω which are parallel to the sides of 𝐴𝐵𝐶. Let Ω1, Ω2, Ω3 be the inradii of the three corner triangles so formed each having equal radii of
1 9
. Also, tangents to these three
circles are drawn which are also parallel to the sides of the inner corner triangles. Find the minimum value of perimeter of triangle 𝐴𝐵𝐶.
Problem 139 Suppose that in a certain society, each pair of persons can be classified as either amicable or hostile. We shall say that each member of an amicable pair is a friend of the other, and each member of a hostile pair is a foe of the other. Suppose that the society has 𝑛 persons and 𝑞 amicable pairs, and that for every set of three persons, at least one pair 39
B. Unsolved Challenges
is hostile. Prove that there is at least one member of the society whose does include
(
2
𝑞 1 − 4𝑞/𝑛
) or fewer amicable pairs.
Problem 140 Consider a function 𝑓: 𝑁→𝑁 Suppose that for all 𝑚, 𝑛∈𝑁, exactly one of 𝑓(𝑚 + 1), 𝑓(𝑚 + 2), ⋯, 𝑓(𝑚 + 𝑓(𝑛)) is divisible by 𝑛. Prove that 𝑓 has an infinite number of fixed points (inputs that get mapped to themselves).
Problem 141 Two trains start from point A and point B simultaneously towards each other. Their initial speed is 0 after which they move with some uniform speed. Then, they accelerate for a while (acceleration of both trains is different) before attaining some uniform speed again. The ratio of speeds during uniform motion is 4:3. At the time of their meeting, the speeds of the train were equal and they arrived at point A and B simultaneously. If the ratio of the accelerations of the train is given by 2
𝑎 2
𝑏+𝑘
, where a,b are
3
twin prime and k is an integer, calculate 𝑎 + 𝑏 + 𝑘 .
Problem 142 The circumference of a circle is divided into 𝑝 equal parts by the points 𝐴1, 𝐴2, ⋯𝐴𝑝, where 𝑝 is an odd prime number. How many different self-intersecting 𝑝-gons are there with these points as vertices if two 𝑝 -gons are considered different only when neither of them can be obtained from the other by rotating the circle? (A self-intersecting polygon is a polygon such that some of its sides intersect at other points besides the vertices).
Problem 143 If A and B are two rectangles with integer sides such that perimeter of A = area of B and perimeter of B = area of A, then we call A and B friendly pair of rectangles.
40
B. Unsolved Challenges
Set S contains all {𝑎, 𝑏, 𝑐, 𝑑} such that (𝑎 * 𝑏, 𝑐 * 𝑑) are dimensions of friendly pairs of rectangles. Call (𝑎𝑖, 𝑏𝑖, 𝑐𝑖, 𝑑𝑖)∀ 1 ≤ 𝑖 ≤ 𝑛(𝑆) where 𝑛(𝑆) is the cardinality of set S cyclic if (𝑎𝑖, 𝑏𝑖, 𝑐𝑖, 𝑑𝑖) given in order are sides of a cyclic φquadrilateral. Denote 𝐴𝑟(𝑖) as the area of cyclic quadrilateral having sides cyclic. Denote Ω(𝑖) as , where ɸ and φ are adjacent angles of cyclic quadrilateral having sides cyclic. Denote ω(𝑖) as . (Note: i is assorted in increasing order of perimeter of cyclic quadrilateral, i.e. indice 1 is assigned to cyclic quadrilateral having minimum perimeter and indice 𝑛(𝑆) is assigned to cyclic quadrilateral having maximum perimeter and equal to x)
is greatest integer less than or
Let XYZ be an equilateral triangle, extend XY beyond Y to a point 𝑌' so that 𝑌𝑌' = . XY, similarly extend YZ beyond Z to a point 𝑍' so that 𝑍𝑍' = Ω(𝑖). YZ and extend XZ beyond X to a point 𝑋' so that 𝑋𝑋' = ω(𝑖) · 𝑋𝑍. If area ∆𝑋𝑌𝑍 =
3 4
remains constant but length
of 𝑋𝑋', 𝑌𝑌', 𝑍𝑍' changes for each value of i, then sum of all possible values of area of ∆𝑋'𝑌'𝑍' is K. Compute
.
Problem 144 Two touching circles with fixed center 𝐴 and 𝐵 respectively having same radii 𝑟. 𝐴 third circle touching both of circles is drawn with center 𝑂 and radius 𝑟1. another circle which is moving in the plane with center 𝐶 and radius 𝑅 is drawn externally tangent to circle with center 𝑂. Again, two circles with center 𝐷 and 𝐸 are drawn such that they are externally tangent to circles with center 𝐴, 𝑂 and 𝐵, 𝑂 respectively. if the minimum perimeter of the pentagon 𝐴𝐵𝐸𝐶𝐷 is obtained for 𝑅 = 𝑘 · 𝑟1. find value of k
2
2
Problem 145 x and y are real numbers such that 6 − 𝑥, 3 + 𝑦 , 11 + 𝑥, 14 − 𝑦 are greater than zero. Find the maximum of the function
41
B. Unsolved Challenges
Problem 146 Fix an integer 𝑛 ≥ 4. Let 𝐶𝑛 be the collection of all 𝑛-point configurations in the plane, every three points of which span a triangle of area strictly greater than 1. For each configuration 𝐶 ∈ 𝐶𝑛 let 𝑓(𝑛, 𝐶) be the maximal size of a sub configuration of 𝐶 subject to the condition that every pair of distinct points has distance strictly greater than 2. Determine the minimum value 𝑓(𝑛) which 𝑓(𝑛, 𝐶) achieves as 𝐶 runs through 𝐶𝑛.
Problem 147 Consider the sequence 𝑥𝑛 > 0 defined with the following recurrence relation 𝑥1 = 0 and for 𝑛 > 1 2 2
(
𝑛
𝑛+1
)
(𝑛 + 1) 𝑥𝑛+1 + 2 + 4 (𝑛 + 1)𝑥𝑛+1 + 2
2𝑛−2
+2
2 2
= 9𝑛 𝑥𝑛 + 36𝑛𝑥𝑛 + 32.
Show that if 𝑛 is a prime number larger or equal to 5, then 𝑥𝑛 is an integer
Problem 148 A jalebi is a loop of 2𝑎 + 2𝑏 + 4 unit squares which can be obtained by cutting a concentric 𝑎 × 𝑏 hole out of an (𝑎 + 2) × (𝑏 + 2) rectangle, for some positive integers 𝑎 and 𝑏. (The side of length 𝑎 of the hole is parallel to the side 𝑎 + 2 of the rectangle). Consider an infinite grid of unit square cells. For each even integer 𝑛 ≥ 8, a bakery of order 𝑛 is a finite set of cells 𝑆 such that, for every 𝑛-cell jalebi 𝐵 in the grid, there exists a congruent copy of 𝐵 all of whose cells are in 𝑆. (The copy can be translated and rotated). We denote by 𝑓(𝑛) the smallest possible number of cells in a bakery of order 𝑛. Find a real number α such that, for cell sufficiently large even integers 𝑛 ≥ 8, we have 1 100
0 then 𝑓 𝑘2 < 𝑐𝑜𝑠 20 < 𝑓 𝑘1
Problem 150 Define 𝑓: 𝑁→𝑁 ∀𝑛 ∊ 𝑁
Computer remainder when A is divided by 2023.
43
Indian National Mathematics Olympiad (INMO) Problems (1986 - 2022)
44
Problem 1 A person who left home between 4 p.m. and 5 p.m. returned between 5 p.m. and 6 p.m. and found that the hands of his watch had exactly exchanged places, when did he go out ? INMO 1986
Problem 2
Solve
INMO 1986
Problem 3 Two circles with radii a and b respectively touch each other externally. Let c be the radius of a circle that touches these two circles as well as a common tangent to the two circles. Prove that INMO 1986
Problem 4 Find the least natural number whose last digit is 7 such that it becomes 5 times larger when this last digit is carried to the beginning of the number. INMO 1986
Problem 5
If
is a polynomial with integer coefficients and , , , three distinct
integers, then show that it is impossible to have
,
, INMO 1986
45
Problem 6 Construct a quadrilateral which is not a parallelogram, in which a pair of opposite angles and a pair of opposite sides are equal. INMO 1986
Problem 7
If , , , are integers greater than 1 such that and have no common
factor except 1 and than 1.
show that
,
for some integer greater INMO 1986
Problem 8 Suppose are six sets each with four elements and are sets each with two elements, Let . Given that each elements of belongs to exactly four of the 's and to exactly three of the 's, find . INMO 1986
Problem 9 Show that among all quadrilaterals of a given perimeter the square has the largest area. INMO 1986
Problem 10 Given that
and as relatively prime positive integers greater than one, show
is not a rational number. INMO 1987
46
Problem 11 Determine the largest number in the infinite sequence INMO 1987
Problem 12 Let
be the set of all triplets
of integers such that
For each triplet in , take number . Add all these numbers corresponding to all the triplets in . Prove that the answer is divisible by 7. INMO 1987
Problem 13 If , , , and are natural numbers, and relation does not hold.
then prove that the INMO 1987
Problem 14 Find a finite sequence of 16 numbers such that: (a) it reads same from left to right as from right to left. (b) the sum of any 7 consecutive terms is , (c) the sum of any 11 consecutive terms is . INMO 1987
Problem 15 Prove that if coefficients of the quadratic equation odd integers, then the roots of the equation cannot be rational numbers.
are INMO 1987
47
Problem 16 Construct the , the median from the vertex
, given
,
(the altitudes from
and
) and
. INMO 1987
Problem 17 Three congruent circles have a common point and lie inside a given triangle. Each circle touches a pair of sides of the triangle. Prove that the incentre and the circumcentre of the triangle and the common point are collinear. INMO 1987
Problem 18 Prove that any triangle having two equal internal angle bisectors (each measured from a vertex to the opposite side) is isosceles. INMO 1987
Problem 19 Let
be a rearrangement of the numbers
. Suppose that is odd. Prove that the product an even integer.
is INMO 1988
Problem 20 Prove that the product of 4 consecutive natural numbers cannot be a perfect cube. INMO 1988
48
Problem 21 Five men, , , , , are wearing caps of black or white color without each knowing the color of his cap. It is known that a man wearing black cap always speaks the truth while the ones wearing white always tell lies. If they make the following statements, find the color worn by each of them: : I see three black caps and one white cap. : I see four white caps : I see one black cap and three white caps : I see your four black caps. INMO 1988
Problem 22 If and are positive and
, prove that
INMO 1988
Problem 23 Show that there do not exist any distinct natural numbers , , , such that and . INMO 1988
Problem 24 If
are the coefficients of the polynomial show that
is even. INMO 1988
49
Problem 25 Given an angle and a point outside the angle . Draw a straight line through meeting in and in such that the triangle has a given perimeter. INMO 1988
Problem 26 A river flows between two houses and , the houses standing some distances away from the banks. Where should a bridge be built on the river so that a person going from to , using the bridge to cross the river may do so by the shortest path? Assume that the banks of the river are straight and parallel, and the bridge must be perpendicular to the banks. INMO 1988
Problem 27 Show that for a triangle with radii of circumcircle and incircle equal to , respectively, the inequality holds. INMO 1988
Problem 28 Prove that the Polynomial be expressed as a product , where and polynomial with integral coefficients and with degree at least .
can't are both INMO 1989
Problem 29 Let
and be any four real numbers, not all equal to zero. Prove that
the roots of the polynomial
can't all be real. INMO 1989
50
Problem 30 Let denote a subset of the set property that no two elements of add up to elements.
. Prove that
having the can't have more than INMO 1989
Problem 31 Determine all divides .|
for which
is not the square of any integer, INMO 1989
Problem 32 For positive integers , define positive integers for which (a)
is an even number,
(b)
is a multiple of .
to be
. Determine the sets of
INMO 1989
Problem 33 Triangle has incentre and the incircle touches at respectively. Let meet at . Show that is perpendicular to . INMO 1989
Problem 34 Let be one of the two points of intersection of two circles with centers respectively.The tangents at to the two circles meet the circles again at . Let a point be located so that is a parallelogram. Show that is also the circumcenter of triangle . INMO 1989 51
Problem 35 Given the equation has four real, positive roots, prove that (a) (b) with equality in each case holding if and only if the four roots are equal. INMO 1990
Problem 36 Determine all non-negative integral pairs
for which INMO 1990
Problem 37 Let be a function defined on the set of non-negative integers and taking values in the same set. Given that
(a) (b)
for all non-negative integers ; ,
find the possible values that can take. (Notation : here refers to largest integer that is
, e.g.
). INMO 1990
52
Problem 38 Consider the collection of all three-element subsets drawn from the set . Determine the number of those subsets for which the sum of the elements is a multiple of 3. INMO 1990
Problem 39 Let , , denote the sides of a triangle. Show that the quantity
must lie between the limits
and 2. Can equality hold at either limit? INMO 1990
Problem 40 Triangle is scalene with angle having a measure greater than 90 degrees. Determine the set of points that lie on the extended line , for which
where
refers to the (positive) distance between
and
. INMO 1990
Problem 41 Let be an arbitrary acute angled triangle. For any point lying within the triangle, let , , denote the feet of the perpendiculars from onto the sides , , respectively. Determine the set of all possible positions of the point for which the triangle is isosceles. For which position of will the triangle become equilateral? INMO 1990
53
Problem 42 Find the number of positive integers for which (i)
;
(ii) 6 is a factor of
. INMO 1991
Problem 43 Given an acute-angled triangle , let points be located as follows: is the point where altitude from on meets the outwards-facing semicircle on as diameter. Points are located similarly. Prove that the area of triangle
where
is
. INMO 1991
Problem 44 Given a triangle
Prove that
let
. INMO 1991
54
Problem 45 Let
be real numbers with
,
,
, and
. Prove that
. INMO 1991
Problem 46 Triangle has an incenter . Let points , be located on the line segments , respectively, so that and . Given that the points lie on a straight line, find the possible values of the measure of angle . INMO 1991
Problem 47 (i) Determine the set of all positive integers for which ; (ii) Prove that
does not divide
divides
for any positive integer . INMO 1991
Problem 48 Solve the following system for real
INMO 1991
55
Problem 49 There are objects of total weight , each of the weights being a positive integers. Given that none of the weights exceeds , prove that the ten objects can be divided into two groups that balance each other when placed on 2 pans of a balance. INMO 1991
Problem 50 Triangle has an incenter l its incircle touches the side at . The line through parallel to meets the incircle again at and the tangent to the incircle at meets at points respectively. Prove that triangle is similar to triangle . INMO 1991
Problem 51 For any positive integer , let
denote the number of ordered pairs
of positive integers for which integers for which
. Determine the set of positive INMO 1991
Problem 52 In a triangle
Problem 53 If that each of or ?
,
such that lies in the closed interval
. Prove that
and
. INMO 1992
, then show
. Can attain the extreme value INMO 1992
56
Problem 54 Find the remainder when
is divided by 92. INMO 1992
Problem 55 Find the number of permutations of such that for any , does not form a permutation of . INMO 1992
Problem 56 Two circles and intersect at two distinct points in a plane. Let a line passing through meet the circles and in and respectively. Let be the midpoint of and let meet the circles and in and respectively. Show that is also the midpoint of . INMO 1992
Problem 57 Let be a polynomial in with integer coefficients and suppose that for five distinct integers one has . Show that there does not exist an integer such that . INMO 1992
Problem 58 Let be an integer. Find the number of ways in which one can place the numbers in the squares of a chess board, one on each, such that the numbers in each row and in each column are in arithmetic progression. INMO 1992
57
Problem 59 Determine all pairs perfect square.
of positive integers for which
is a INMO 1992
Problem 60 Let
be an -sided regular polygon. If , find . INMO 1992
Problem 61 Determine all functions
such that
INMO 1992
Problem 62 The diagonals and of a cyclic quadrilateral intersect at . Let be the circumcenter of triangle and be the orthocenter of triangle . Show that the points are collinear. INMO 1993
Problem 63 Let be a quadratic polynomial with any integer , show that there is an integer such that
. Given INMO 1993
58
Problem 64 If
and
, show that INMO 1993
Problem 65 Let be a triangle in a plane . Find the set of all points from ) in the plane such that the circumcircles of triangles have the same radii.
(distinct , , INMO 1993
Problem 66 Show that there is a natural number such that notation ends exactly in 1993 zeros.
when written in decimal INMO 1993
Problem 67 Let be a triangle right-angled at and be its circumcircle. Let be the circle touching the lines and , and the circle internally. Further, let be the circle touching the lines and and the circle externally. If be the radii of prove that . INMO 1993
Problem 68 Let and be a subset of having elements. Show that has 2 distinct elements and whose sum is divisible by . INMO 1993
59
Problem 69 Let be a bijective function from there is a positive integer denotes the composition
to itself. Show that
such that
for each in
, where
times. INMO 1993
Problem 70 Show that there exists a convex hexagon in the plane such that (i) all its interior angles are equal; (ii) its sides are
in some order. INMO 1993
Problem 71 Let be the centroid of the triangle in which the angle at is obtuse and and be the medians from and respectively onto the sides and . If the points . If further is a point on the line show that triangle and
Problem 72 If
and are concyclic, show that extended such that is a parallelogram, are similar. INMO 1994
prove that
. INMO 1994
Problem 73 In any set of square integers, prove that one can always find a subset of numbers, sum of whose elements is divisible by INMO 1994
60
Problem 74 Find the number of nondegenerate triangles whose vertices lie in the set of points in the plane such that , , and are integers. INMO 1994
Problem 75 A circle passes through the vertex of a rectangle and touches its sides and at and respectively. If the distance from to the line segment is equal to units, find the area of rectangle . INMO 1994
Problem 76 Find all real-valued functions on the reals such that for all , and
,
for INMO 1994
Problem 77 In an acute angled triangle is the midpoint of . On the line . Show that .
, , , take a point
is the orthocenter, and such that INMO 1995
Problem 78 Show that there are infinitely many pairs (not necessarily positive) such that both the equations integer roots.
of relatively prime integers have INMO 1995
61
Problem 79 Show that the number of element subsets with is less than the number of those with
of INMO 1995
Problem 80 Let be a triangle and a circle be drawn lying outside the triangle, touching its incircle externally, and also the two sides and . Show that the ratio of the radii of the circles
and is equal to INMO 1995
Problem 81 Let that
. Let for
be real numbers all less than and such . Show that
INMO 1995
Problem 82 Find all primes for which the quotient
is a square. INMO 1995
Problem 83 a) Given any positive integer , show that there exist distinct positive integers and such that divides for ; b) If for some positive integers and , , prove that
divides
for all positive integers INMO 1996 62
Problem 84 Let and be two concentric circles in the plane with radii and respectively. Show that the orthocenter of any triangle inscribed in circle lies in the interior of circle . Conversely, show that every point in the interior of is the orthocenter of some triangle inscribed in . INMO 1996
Problem 85 Solve the following system for real
:
INMO 1996
Problem 86 Let be a set containing elements. Find the number of ordered triples of subsets of such that is a subset of and is a proper subset of . INMO 1996
Problem 87 Define a sequence for this sequence.
by and . prove that for any
and ,
is also a term in INMO 1996
63
Problem 88 There is a array (matrix) consisting of and and there are exactly zeroes. Show that it is possible to remove all the zeros by deleting some rows and some columns. INMO 1996
Problem 89 Let be a parallelogram. Suppose a line passing through and lying outside the parallelogram meets and produced at and respectively. Show that INMO 1997
Problem 90 Show that there do not exist positive integers
and such that
INMO 1997
Problem 91 If are three real numbers and real number , prove that
for some INMO 1997
Problem 92 In a unit square one hundred segments are drawn from the center to the sides dividing the square into one hundred parts (triangles and possibly quadrilaterals). If all parts have equal perimeter , show that
. INMO 1997
64
Problem 93 Find the number of array whose entries are from the set and which are such that the sum of the numbers in each of the four rows and in each of the four columns is divisible by . INMO 1997
Problem 94 Suppose and are two positive real numbers such that the roots of the cubic equation are all real. If is a root of this cubic with minimal absolute value, prove that INMO 1997
Problem 95 In a circle with center , let be a chord that is not a diameter. Let be the midpoint of this chord . Take a point on the circle with as diameter. Let the tangent to at meet at . Show that . INMO 1998
Problem 96 Let and be two positive rational numbers such that is also a rational number. Prove that and themselves are rational numbers. INMO 1998
Problem 97 Let integer such that integer such that
be four integers such that is not divisible by . If there is an is divisible by 5, prove that there is an is also divisible by 5. INMO 1998
65
Problem 98 Suppose unit. If
Problem 99 Suppose
is a cyclic quadrilateral inscribed in a circle of radius one , prove that is a square. INMO 1998
are three real numbers such that the quadratic equation
has roots of the form and are real numbers. Show that (i) The numbers are all positive. (ii) The numbers
where
form the sides of a triangle. INMO 1998
Problem 100 It is desired to choose integers from the collection of integers, namely, such that the average of these chosen integers is itself an integer and as minimum as possible. Show that this can be done for each positive integer and find this minimum value for each . INMO 1998
Problem 101 Let be an acute-angled triangle in which are points on respectively such that ; ; and bisects internally, Suppose meets and in and respectively. If , , , find the perimeter of . INMO 1999
66
Problem 102 In a village persons volunteered to clean up, for a fair, a rectangular field with integer sides and perimeter equal to feet. For this purpose, the field was divided into equal parts. If each part had an integer area, find the length and breadth of the field. INMO 1999
Problem 103 Show that there do not exist polynomials and each having integer coefficients and of degree greater than or equal to 1 such that INMO 1999
Problem 104 Let and be two concentric circles. Let equilateral triangles inscribed in and respectively. If points on and respectively, show that
and be any two and are any two
INMO 1999
Problem 105 Given any four distinct positive real numbers, show that one can choose three numbers from among them, such that all three quadratic equations
have only real roots, or all three equations have only imaginary roots. INMO 1999
67
Problem 106 For which positive integer values of can the set be split into disjoint -element subsets such that in each of these sets . INMO 1999
Problem 107 The incircle of touches , , at , , respectively. The line through parallel to meets at , and the line through parallel to meets at . Show that the line bisects and bisects . INMO 2000
Problem 108 Solve for integers
: INMO 2000
Problem 109 If
are real numbers such that
and then prove that
Problem 110 In a convex quadrilateral . Prove that
,
,
. INMO 2000
and INMO 2000
68
Problem 111 Let be three real numbers such that that if is a root of the cubic equation then
. prove (real or complex), INMO 2000
Problem 112 For any natural numbers , ( ), let denote the number of congruent integer-sided triangles with perimeter . Show that (i) (ii)
; . INMO 2000
Problem 113 Let be a triangle in which no angle is . For any point in the plane of the triangle, let denote the reflections of in the sides respectively. Prove that (i) If
is the incenter or an excentre of ;
, then
is the circumcenter of
(ii) If
is the circumcentre of
, then
is the orthocentre of
(iii) If
is the orthocentre of .
, then
is either the incentre or an excentre of
;
INMO 2001
Problem 114 Show that the equation infinitely many solutions in integers
has . INMO 2001
69
Problem 115 If
are positive real numbers such that
, Prove that INMO 2001
Problem 116 Show that given any nine integers, we can find four, such that is divisible by . Show that this is not always true for eight integers. INMO 2001
Problem 117 , show that
is a triangle. is the midpoint of . , and . Show that is obtuse. If is the circumcenter of is equilateral. INMO 2001
Problem 118 Find all functions all
such that
for INMO 2001
70
Problem 119 For a convex hexagon unequal, consider the following statements. (
)
is parallel to
. (
)
(
)
is parallel to
. (
)
(
)
is parallel to
. (
)
in which each pair of opposite sides is
. . .
Show that if all six of these statements are true then the hexagon is cyclic. Prove that, in fact, five of the six statements suffice. INMO 2002
Problem 120 Find the smallest positive value taken by integers , , . Find all , , which give the smallest value
for positive
INMO 2002
Problem 121 If , are positive reals such that
show that
. INMO 2002
Problem 122 Is it true that there exist 100 lines in the plane, no three concurrent, such that they intersect in exactly 2002 points? INMO 2002
71
Problem 123 Do there exist distinct positive integers , , such that , , , , , , form an arithmetic progression (in some order). INMO 2002
Problem 124 The numbers , , are arranged in an array, so that the numbers in each row increase from left to right, and the numbers in each column increase from top to bottom. Let be the number in position . Let be the number of possible values for
. Show that INMO 2002
Problem 125 Let be an interior point of an acute-angled triangle . The line meets the line at , and the line meets the line at . The lines and intersect each other at . Let be the foot of the perpendicular from the point to the line . Show that the line bisects the angle . INMO 2003
Problem 126 Find all primes
and even .
such that INMO 2003
Problem 127 Show that for all real . Find the sum of the non-real roots.
has at least one real root INMO 2003
72
Problem 128 Find all -digit numbers which use only the digits and and are divisible by . INMO 2003
Problem 129 Let a, b, c be the side lengths and S the area of a triangle ABC. Denote ,
and
. Prove that there exists a triangle with side
lengths x, y, z, and the area of this triangle is
. INMO 2003
Problem 130 Each lottery ticket has a 9-digit numbers, which uses only the digits , , . Each ticket is colored red, blue or green. If two tickets have numbers which differ in all nine places, then the tickets have different colors. Ticket is red, and ticket is green. What color is ticket ? INMO 2003
Problem 131 sides ,
,
is a convex quadrilateral. , , , . bisects at .
. Prove that
,
are the midpoints of the , and
is a square INMO 2004
Problem 132
is a prime. Find all integers , , such that . INMO 2004
73
Problem 133 If is a real root of
, show that INMO 2004
Problem 134 If
is a triangle, with sides , , , circumradius , and exradii , , , show that , , , and . INMO 2004
Problem 135 S is the set of all ( , , , , , ) where , , , , , are integers such that . Find the largest which divides abcdef for all members of .” INMO 2004
Problem 136 Show that the number of 5-tuples ( , , , , ) such that is odd INMO 2004
Problem 137 Let be the midpoint of side of a triangle . Let the median intersect the incircle of at and being nearer to than . If , prove that the sides of triangle are in the ratio in some order. INMO 2005
74
Problem 138 Let and be positive integers such that minimum possible value of .
. Find the INMO 2005
Problem 139 Let
be positive real numbers, not all equal, such that some two of
the equations
have a common root, say . Prove that
is real and negative; the remaining third quadratic equation has non-real roots. INMO 2005
Problem 140 All possible -digit numbers, in each of which the digits occur in nonincreasing order (from left to right, e.g. ) are written as a sequence in increasing order. Find the -the number in this sequence. INMO 2005
Problem 141 Let be a given positive integer. A sequence of positive integers is such that , for , is obtained from by adding some nonzero digit of . Prove that a) the sequence contains an even term; b) the sequence contains infinitely many even terms. INMO 2005
75
Problem 142 Find all functions
such that for all
. INMO 2005
Problem 143 In a non equilateral triangle the sides form an arithmetic progression. Let be the incentre and the circumcentre of the triangle Prove that (1)
is perpendicular to
;
(2) If meets in , and , are the midpoints of then is the circumcentre of triangle .
,
respectively INMO 2006
Problem 144 Prove that for every positive integer there exists a unique ordered pair of positive integers such that
INMO 2006
Problem 145 Let by Find all triples
denote the set of all triples
of integers. Define
such that INMO 2006
76
Problem 146 Some 46 squares are randomly chosen from a chess board and colored in red. Show that there exists a block of 4 squares of which at least three are colored in red. INMO 2006
Problem 147 In a cyclic quadrilateral , and . Prove that (1)
,
,
,
;
(2)
. INMO 2006
Problem 148(a) Prove that if is a integer such that
then there exists an
integer such that (b) Find the smallest positive integer
for which whenever an integer is such that
then there exists an integer such that INMO 2006
Problem 149 In a triangle right-angled at , the median through angle between and the bisector of . Prove that
bisects the
INMO 2007
77
Problem 150 Let be a natural number such that numbers . Prove that where one of
's ,
's , 's are all nonzero integers. Further, if does not divide at least prove that can be expressed in the form , where are natural numbers none of which is divisible by . INMO 2007
Problem 151 Let and be positive integers such that roots and . Prove that and are integers if and only if integer. (Here
for some natural
has real
is the square of an
denotes the largest integer not exceeding ) INMO 2007
Problem 152 Let be permutation of . A pair is said to correspond to an inversion of if but . How many permutations of , , have exactly two inversions? For example, In the permutation the pairs
, there are 6 inversions corresponding to . INMO 2007
78
Problem 153 Let be a triangle in which . Let be the midpoint of and be a point on . Suppose is the foot of perpendicular from on . Define
Prove that
Hence show that
and
if and only if
is equilateral. INMO 2007
Problem 154 If , , are positive real numbers, prove that INMO 2007
Problem 155 Let be triangle, its in-center; be the reflections of in respectively. Suppose the circum-circle of triangle passes through . Prove that are concyclic, where is the in-center of triangle . INMO 2008
Problem 156 Find all triples and are natural numbers.
such that
, where is a prime and INMO 2008
79
Problem 157 Let be a set of real numbers such that has at least four elements. Suppose has the property that is a rational number for all distinct numbers in . Prove that there exists a positive integer such that is a rational number for every in . INMO 2008
Problem 158All the points with integer coordinates in the -Plane are coloured using three colors, red, blue and green, each color being used at least once. It is known that the point is red and the point is blue. Prove that there exist three points with integer coordinates of distinct colors which form the vertices of a right-angled triangle. INMO 2008
Problem 159 Let be a triangle; be three equal, disjoint circles inside such that touches and ; touches and ; and touches and . Let be a circle touching circles externally. Prove that the line joining the circum-center and the in-center of triangle passes through the center of . INMO 2008
Problem 160 Let be a polynomial with integer coefficients. Prove that there exist two polynomials and , again with integer coefficients, such that (i) is a polynomial in , and (ii) is a polynomial in . INMO 2008
80
Problem 161 Let
be a triangle and let be an interior point such that .Let be the mid points of respectively.Suppose .Prove that are collinear. INMO 2009
Problem 162 Define a a sequence
as follows
, if number of positive divisors of is odd , if number of positive divisors of is even (The positive divisors of include as well as .)Let number whose decimal expansion contains in the -th place, .Determine,with proof,whether is rational or irrational.
be the real
INMO 2009
Problem 163 Find all real numbers such that:
(Here
denotes the largest integer not exceeding .) INMO 2009
Problem 164 All the points in the plane are colored using three colors.Prove that there exists a triangle with vertices having the same color such that either it is isosceles or its angles are in geometric progression. INMO 2009
81
Problem 165 Let be an acute angled triangle and let be its ortho center. Let denote the largest altitude of the triangle . Prove that:
INMO 2009
Problem 166 Let
be positive real numbers such that
.Prove that:
. INMO 2009
Problem 167 Let be a triangle with circum-circle . Let be a point in the interior of triangle which is also on the bisector of . Let meet in respectively. Suppose is the point of intersection of with ; and is the point of intersection of with . Prove that is parallel to . INMO 2010
Problem 168 Find all natural numbers
Problem 169 Find all non-zero real numbers equations:
such that
does
divide . INMO 2010
which satisfy the system of
INMO 2010
82
Problem 170 How many 6-tuples is from the set for
(where
are there such that each of and the six expressions
is to be taken as
) are all equal to one another? INMO 2010
Problem 171Let be an acute-angled triangle with altitude . Let be its ortho-center and be its circum-center. Suppose is an acute-angled triangle and its circum-center. Let be the reflection of in the line . Show that lies on the line joining the mid-points of and . INMO 2010
Problem 172 Define a sequence
by
,
and
for For every
and
prove that
divides
. Suppose
divides for some natural numbers and . Prove that
divides
INMO 2010
Problem 173 Let be points on the sides triangle such that and Show that is equilateral.
respectively of a
INMO 2011
83
Problem 174 Call a natural number faithful if there exist natural numbers such that and and Show that all but a finite number of natural numbers are faithful. Find the sum of all natural numbers which are not faithful. INMO 2011
Problem 175 Let
and
be two polynomials with integral coefficients such that is a prime and and Suppose that there exists a rational number such that Prove that INMO 2011
Problem 176 Suppose five of the nine vertices of a regular nine-sided polygon are arbitrarily chosen. Show that one can select four among these five such that they are the vertices of a trapezium. INMO 2011
Problem 177 Let be a cyclic quadrilateral inscribed in a circle Let be the midpoints of arcs of respectively. Suppose that Show that are all concurrent. INMO 2011
Problem 178 Find all functions
satisfying For all
. INMO 2011
84
Problem 179 Let
be a quadrilateral inscribed in a circle. Suppose
and subtends maximum possible area of .
degrees at the center of the circle . Find the INMO 2012
Problem 180 Let numbers, such that . Prove that divides
and and
be two sets of prime . Suppose and
. INMO 2012
Problem 181 Define a sequence
of functions by for
. Prove that each
is a polynomial with integer coefficients. INMO 2012
Problem 182 Let be a triangle. An interior point of is said to be good if we can find exactly rays emanating from intersecting the sides of the triangle such that the triangle is divided by these rays into smaller triangles of equal area. Determine the number of good points for a given triangle . INMO 2012
Problem 183 Let be an acute angled triangle. Let be points on such that is the median, is the internal bisector and is the altitude. Suppose that and Show that is equilateral. INMO 2012 85
Problem 184 Let
for all
be a function satisfying
,
and
, simultaneously.
Find the set of all possible values of the function . If
and
, find the set of all integers such that
. INMO 2012
Problem 185 Let and be two circles touching each other externally at Let and be the centers of and respectively. Let be a line which is tangent to at and passing through and let be the line tangent to at and passing through Let If then prove that the triangle is equilateral. INMO 2013
Problem 186 Find all
and primes
satisfying INMO 2013
Problem 187 Let
such that . Show that the equation has no integer solution. INMO 2013
86
Problem 188 Let be an integer greater than and let be the number of non empty subsets of with the property that the average of the elements of is an integer.Prove that is always even. INMO 2013
Problem 189 In an acute triangle orthocenter. Let midpoint of If the triangles possible values of
let and
be its circumcentre, centroid and Let be the have the same area, find all the INMO 2013
Problem 190 Let and
be six positive real numbers satisfying and Further, suppose that Prove that and INMO 2013
Problem 191 In a triangle triangles
and
, let be the point on the segment such that . Suppose that the points , and the centroids of lie on a circle. Prove that . INMO 2014
Problem 192 Let be a natural number. Prove that,
is even. INMO 2014
87
Problem 193 Let be natural numbers with . Suppose that the sum of their greatest common divisor and least common multiple is divisible by . Prove that the quotient is at most
. When is this quotient exactly equal to INMO 2014
Problem 194 Written on a blackboard is the polynomial . Calvin and Hobbes take turns alternately (starting with Calvin) in the following game. At his turn, Calvin should either increase or decrease the coefficient of by . And at this turn, Hobbes should either increase or decrease the constant coefficient by . Calvin wins if at any point of time the polynomial on the blackboard at that instant has integer roots. Prove that Calvin has a winning strategy. INMO 2014
Problem 195 In a acute-angled triangle , a point lies on the segment . Let denote the circumcenter of triangles and respectively. Prove that the line joining the circumcentre of triangle and the orthocentre of triangle is parallel to . INMO 2014
Problem 196 Let be a natural number. Let , and define to be the set of all those elements of which belong to exactly one of and . Show that , where is a collection of subsets of such that for any two distinct elements of of we have . Also find all such collections for which the maximum is attained. INMO 2014
88
Problem 197 Let be a right-angled triangle with . Let is the altitude from on . Let and be the incenters of triangles and respectively.Show that circumcenter of triangle lie on the hypotenuse . INMO 2015
Problem 198 For any natural number example we write
write the finite decimal expansion of
as its infinite decimal expansion not
length of non-periodic part of the (infinite) decimal expansion of
(for
. Determine the . INMO 2015
Problem 199 Find all real functions .
such that INMO 2015
Problem 200 There are four basketball players . Initially the ball is with . The ball is always passed from one person to a different person. In how many ways can the ball come back to after moves? (for example , or . INMO 2015
89
Problem 201 Let intersect at . Let and
be a convex quadrilateral.Let diagonals and and are altitudes from on the side respectively. Show that has a incircle if and only if
INMO 2015
Problem 202 Show that from a set of
square integers one can select six numbers
such that
Problem 203 Let
. INMO 2015
be a triangle in which
the triangle lies on the incircle. Find the ratio
. Suppose the orthocentre of . INMO 2016
Problem 204 For positive real numbers necessarily implies
which of the following statements
: (I)
, (II) ? Justify your answer. INMO 2016
Problem 205 Let denote the set of natural numbers. Define a function and
. We write for any
(i) Show that for each
by and in general
.
, there exists such that
.
90
(ii) For . Prove that
, let
denote the number of elements in the set , for . INMO 2016
Problem 206 Suppose points of the circumference of a circle are colored red and the remaining points are colored blue . Given any natural number , prove that there is a regular -sided polygon all of whose vertices are blue INMO 2016
Problem 207 Let be a right-angle triangle with . Let be a point on such that the inradii of the triangles and are equal. If this common value is and if is the inradius of triangle , prove that
INMO 2016
Problem 208 Consider a non constant arithmetic progression . Suppose there exist relatively prime positive integers and
such that
and are also the terms of the same arithmetic progression. Prove that the terms of the arithmetic progression are all integers. INMO 2016
91
Problem 209 In the given figure, is a square sheet of paper. It is folded along such that goes to a point different from and , on the side and goes to . The line cuts in . Show that the inradius of the triangle is the sum of the inradii of the triangles and .
INMO 2017
Problem 210 Suppose
is an integer and all the roots of are integers. Find all possible values of . INMO 2017
Problem 211 Find the number of triples
where is a real number and ,
belong to the set such that denotes the fractional part of the real number . (For example .)
where
INMO 2017
92
Problem 212 Let
be a convex pentagon in which and the side lengths are five consecutive integers in some order. Find all possible values of . INMO 2017
Problem 213 Let
be a convex pentagon in which and the side lengths are five consecutive integers in some order. Find all possible values of . INMO 2017
Problem 214 Let
be an integer and consider the sum
Show that form the sides of a triangle whose area and inradius are also integers. INMO 2017
Problem 215 Let be a non-equilateral triangle with integer sides. Let and be respectively the mid-points of and ; let be the centroid of . Suppose, , , , are concyclic. Find the least possible perimeter of . INMO 2018
93
Problem 216 For any natural number , consider a rectangular board made up of unit squares. This is covered by types of tiles : red tile, green tile and domino. (For example, we can have types of tiling when : red-red ; red-green ; green-red ; green-green ; and blue.) Let denote the number of ways of covering rectangular board by these types of tiles. Prove that, divides . INMO 2018
Problem 217 Let and be two circles with respective centers and intersecting in two distinct points and such that is an obtuse angle. Let the circumcircle of intersect and respectively in points and . Let the line intersect in ; let the line intersect in . Prove that, the points are concyclic. INMO 2018
Problem 218 Find all polynomials with real coefficients divides
such that
. INMO 2018
Problem 219 There are girls in a class sitting around a circular table, each having some apples with her. Every time the teacher notices a girl having more apples than both of her neighbors combined, the teacher takes away one apple from that girl and gives one apple each to her neighbors. Prove that this process stops after a finite number of steps. (Assume that the teacher has an abundant supply of apples.) INMO 2018
94
Problem 220 Let denote set of all natural numbers and let such that for all divides
be a function
; for all
.
Prove that, there exists an odd natural number such that
Problem 221 Let be a triangle with segment and be a point on line circumcircle of triangle at and and . Determine
for all in INMO 2018
. Let be a point on the such that is tangent to the is perpendicular to . Given that in degrees. INMO 2019
Problem 222 Let
be a regular pentagon.For , let be the pentagon whose vertices are the midpoint of the sides . All the vertices of each of the pentagons are arbitrarily coloured red or blue. Prove that four points among these points have the same color and form the vertices of a cyclic quadrilateral. INMO 2019
Problem 223 Let
be distinct positive integers. Prove that Further,
determine when equality holds. INMO 2019
95
Problem 224 Let and are distinct primes .
be positive integers such that such that divides
. Prove that there for all INMO 2019
Problem 225 Let be the diameter of a circle and let be a point on different from and . Let be the foot of perpendicular from onto .Let be a point on the segment such that is equal to the semi perimeter of .Show that the excircle of opposite is tangent to . INMO 2019
Problem 226 Let be a function defined from all positive real numbers such that for all for all for all Prove that for all for all
real,
to the set of
INMO 2019
Problem 227 Let and be two circles of unequal radii, with centers and respectively, intersecting in two distinct points and . Assume that the center of each circle is outside the other circle. The tangent to at intersects again in , different from ; the tangent to at intersects again at , different from . The bisectors of and meet and again in and , respectively. Let and be the circumcenter of triangles and , respectively. Prove that is the perpendicular bisector of the line segment . INMO 2020
96
Problem 228 Suppose is a polynomial with real coefficients, satisfying the condition , for every real . Prove that can be expressed in the form for some real numbers
and non-negative integer . INMO 2020
Problem 229 Let be a subset of . Suppose there is a positive integer such that for any integer , one can find positive integers so that and all the digits in the decimal representations of (expressed without leading zeros) are in . Find the smallest possible value of . INMO 2020
Problem 230 Let numbers such that
be an integer and let
be real . Prove that INMO 2020
Problem 231 Infinitely many equidistant parallel lines are drawn in the plane. A positive integer is called frameable if it is possible to draw a regular polygon with sides all whose vertices lie on these lines, and no line contains more than one vertex of the polygon. (a) Show that are frameable. (b) Show that any integer is not frameable. (c) Determine whether is frameable. INMO 2020
97
Problem 232 A stromino is a rectangle. Show that a board divided into twenty-five squares cannot be covered by strominos such that each stromino covers exactly three squares of the board, and every square is covered by one or two strominos. (A stromino can be placed either horizontally or vertically on the board.) INMO 2020
Problem 233 Suppose
is an integer, and let
be
integers such that for any two integers and satisfying . Determine the maximum possible value of . INMO 2021
Problem 234 Find all pairs of integers so that each of the two cubic polynomials has all the roots to be integers. INMO 2021
Problem 235 Betal marks points on the plane such that no three are collinear, and draws all possible segments joining these. He then chooses any of these segments, and marks their midpoints. Finally, he chooses a segment whose midpoint is not marked yet, and challenges Vikram to construct its midpoint using only a straightedge. Can Vikram always complete this challenge? Note. A straightedge is an infinitely long ruler without markings, which can only be used to draw the line joining any two given distinct points. INMO 2021
98
Problem 236 A Magician and a Detective play a game. The Magician lays down cards numbered from to face-down on a table. On each move, the Detective can point to two cards and inquire if the numbers on them are consecutive. The Magician replies truthfully. After a finite number of moves, the Detective points to two cards. She wins if the numbers on these two cards are consecutive, and loses otherwise. Prove that the Detective can guarantee a win if and only if she is allowed to ask at least questions. INMO 2021
Problem 237 In a convex quadrilateral and . Extend at . Prove that .
, , , to meet the circumcircle of triangle INMO 2021
Problem 238 Let functions
be the set of all polynomials with real coefficients. Find all satisfying the following conditions:
a. maps the zero polynomial to itself, b. for any non-zero polynomial , c. for any two polynomials , the polynomials have the same set of real roots.
, and and INMO 2021
99
Problem 239 Let
be an interior point on the side
. Let the circumcircle of triangle circumcircle of triangle intersect
intersect again at
intersect the circumcircle of triangle , respectively. Let and , respectively. Prove that
of an acute-angled triangle again at . Let
again at
be the incentres of triangles are concyclic.
and the , and
,
,
and and INMO 2022
Problem 240 Find all natural numbers for which there is a permutation of that satisfies:
INMO 2022
Problem 241 For a positive integer , let denote the number of arrangements of the integers into a sequence such that for all , and for all , . For example, is , since the possible arrangements are
and
(a) Find (b) If
is the largest non-negative integer so that .
(c) Find the largest non-negative integer
so that
divides
, show that
divides INMO 2022
100
Indian Team Selection Test (TST) Problems (2001 - 2019)
101
Problem 1
Let , ,
. Prove that if
, then
. TST 2001
Problem 2
Two symbols and obey the rule . Given a word consisting of letters and letters , show that there is a unique cyclic permutation of this word which reduces to . TST 2001
Problem 3 In a triangle with incircle and incenter , the segments , , cut at , , , respectively. Rays , , meet the sides , , at , , respectively. Prove that: When does equality occur? TST 2001
Problem 4
For any positive integer , show that there exists a polynomial
degree with integer coefficients such that powers of .
of
are all distinct TST 2001
102
Problem 5
Let
be a cubic polynomial with integer coefficients. Suppose that a
prime divides
for
, , , , where
integers from the set
are distinct
. Prove that divides all the coefficients of
. TST 2001
Problem 6
Find the number of all unordered pairs
-element set, such that
and
of subsets of an . TST 2001
Problem 7
If on
such that ,
, triangles , .
and .
COnstructed externally on is triangle . Prove that 1. is perpendicular to . 2. If
is the projection of
are constructed externally
on
with
, then prove that
,
. TST 2001
Problem 8
Find all functions
satisfying :
for all
. TST 2001
103
Problem 9
Points
triangle
are chosen on side
in that order. Let
be the inradius of triangle
, and be the inradius of independent of such that :
of a for
. Show that there is a constant
TST 2001
Problem 10 Complex numbers , , have the property that integer for every natural number . Prove that the polynomial
is an
has integer coefficients. TST 2001
Problem 11 Let
be a prime. For each
the unique integer in
such that
, define
to be
and set
. Prove that :
TST 2001
Problem 12 Each vertex of an grid is colored blue, green or red in such a way that all the boundary vertices are red. We say that a unit square of the grid is properly colored if: all the three colors occur at the vertices of the square, and one side of the square has the endpoints of the same color. Show that the number of properly colored squares is even. TST 2001
104
Problem 13 Let be a rectangle, and let be a circular arc passing through the points and . Let be the circle tangent to the lines and and to the circle , and lying completely inside the rectangle . Similarly let be the circle tangent to the lines and and to the circle , and lying completely inside the rectangle . Denote by and the radii of the circles and , respectively, and by the inradius of triangle . (a) Prove that . (b) Prove that one of the two common internal tangents of the two circles and is parallel to the line
and has the length
. TST 2001
Problem 14 A strictly increasing sequence for all for which there exist positive integers and
has the property that . Suppose is the least positive integer such that
. Prove that
. TST 2001
Problem 15 Let be a polynomial of degree with real coefficients and let . Prove that
TST 2001
105
Problem 16 Let
and
be three points on a line with
between
and
. Let be semicircles, all on the same side of and with as diameters, respectively. Let be the line perpendicular to through . Let be the circle which is tangent to the line , tangent to internally, and tangent to externally. Let be the point of contact of and . The diameter of through meets in . Show that . TST 2002
Problem 17 Show that there is a set of consecutive positive integers containing exactly primes. (You may use the fact that there are primes less than 1000) TST 2002
Problem 18 Let form of ?
. How many quadratics are there of the , with equal roots, and such that
are distinct elements TST 2002
Problem 19 Let be the circumcenter and the orthocenter of an acute triangle . Show that there exist points , , and on sides , , and respectively such that and the lines , , and are concurrent. TST 2002
Problem 20 Let
be positive reals such that
. Prove that
TST 2002
106
Problem 21 Determine the number of -tuples of integers that
for each
and
such
for
. TST 2002
Problem 22 Given two distinct circles touching each other internally, show how to construct a triangle with the inner circle as its incircle and the outer circle as its nine point circle. TST 2002
Problem 23 Let
be the sum of positive divisors of an integer Show that
for positive integers
.
and with TST 2002
Problem 24 Find all positive integers such that
is a power of . TST 2002
107
Problem 25 On each day of their tour of the West Indies, Sourav and Srinath have either an apple or an orange for breakfast. Sourav has oranges for the first days, apples for the next days, followed by oranges for the next days, and so on. Srinath has oranges for the first days, apples for the next days, followed by oranges for the next days, and so on. If , and if the tour lasted for eat the same kind of fruit?
days, on how many days did they TST 2002
Problem 26 Let
denote the set of all ordered triples
integers. Find all functions
of nonnegative
satisfying
for all nonnegative integers , , . TST 2002
Problem 27 Let be a triangle and an exterior point in the plane of the triangle. Suppose the lines , , meet the sides , , (or extensions thereof) in , , , respectively. Suppose further that the areas of triangles , , are all equal. Prove that each of these areas is equal to the area of triangle itself. TST 2002
108
Problem 28 Let
be integers with
. A set
of non-negative
integers is olympic if and if . Show that the set of all non-negative integers is the union of pairwise disjoint olympic sets. TST 2002
Problem 29 Let and
and
be two triangles such that
is the midpoint of
Prove that
.
bisects
is the midpoint of
and
bisects
. TST 2002
Problem 30 Let be an odd prime and let be an integer not divisible by . Show that there are
triples of integers
with
and such
that TST 2002
Problem 31 Let
be arbitrary real numbers. Prove the inequality
TST 2002
Problem 32 Is it possible to find positive integers not exceeding that all pairwise sums of them are different?
, such TST 2002
109
Problem 33 Let be a positive integer and let is the square root of
where
, and and are polynomials with real coefficients. Show
that for any real number the equation
has only real roots. TST 2002
Problem 34 Consider the square grid with and at its diagonal ends. Paths from to are composed of moves one unit to the right or one unit up. Let (n-th catalan number) be the number of paths from to which stay on or below the diagonal . Show that the number of paths from to which cross
from below at most twice is equal to TST 2002
Problem 35 Let triangles exterior to that
be an acute triangle. Let , with
the intersection of lines and , and let be the intersection of sum
, and , and
, let and
be isosceles , such
Let be be the intersection of and . Find, with proof, the value of the
TST 2002
Problem 36 Let
be positive real numbers. Prove that
TST 2002 110
Problem 37 Given a prime , show that there exists a positive integer such that the decimal representation of
has a block of
consecutive zeros. TST 2002
Problem 38 Let
be the midpoints of the sides
of an acute non-isosceles triangle
, and let
, respectively, be the feet of the
altitudes through the vertices on these sides respectively. Consider the arc of the nine point circle of triangle lying outside the triangle. Let the point of trisection of this arc closer to be . Define analogously the points (on arc ) and (on arc ). Show that triangle is equilateral. TST 2003
Problem 39 Find all triples (i) ; (ii) (iii)
of positive integers such that
; and is divisible by each of the numbers
. TST 2003
Problem 40 Find all functions
such that for all reals and , TST 2003
111
Problem 41 There are four lines in the plane, no three concurrent, no two parallel, and no three forming an equilateral triangle. If one of them is parallel to the Euler line of the triangle formed by the other three lines, prove that a similar statement holds for each of the other lines. TST 2003
Problem 42 On the real number line, paint red all points that correspond to integers of the form , where and are positive integers. Paint the remaining integer point blue. Find a point on the line such that, for every integer point , the reflection of with respect to is an integer point of a different color than . TST 2003
Problem 43 A zig-zag in the plane consists of two parallel half-lines connected by a line segment. Find , the maximum number of regions into which zig-zags can divide the plane. For example, (see the diagram). Of these regions how many are bounded? [The zig-zags can be as narrow as you please.] Express your answers as polynomials in of degree not exceeding .
TST 2003
112
Problem 44
is a polynomial with integer coefficients and for every natural we
have
.
is divisible by
is a sequence that:
for every
one of
Prove that TST 2003
Problem 45 Let
be a triangle, and let
exradii opposite the vertices
denoted its inradius and the
, respectively. Suppose
. Prove that is acute,
(a) triangle (b)
. TST 2003
Problem 46 Let be a positive integer and such that such that one of
a partition of
. Prove that there exist is the sum of the other two.
,
, TST 2003
Problem 47 Let be a positive integer greater than , and let be a prime such that divides
and divides
. Prove that
is a square. TST 2003
Problem 48 Let be a cyclic quadrilateral. Let , , be the feet of the perpendiculars from to the lines , , , respectively. Show that if and only if the bisectors of with
and
are concurrent
. TST 2004 113
Problem 49 Prove that for every positive integer there exists an -digit number divisible by all of whose digits are odd. TST 2004
Problem 50 For
positive reals find the minimum value of
TST 2004
Problem 51 Given a permutation pair
of
is called an inversion of if
, an ordered and
. Let
denote the no. of inversions of the permutation . Find the average of as varies over all permutations. TST 2004
Problem 52 Prove that in any triangle
,
TST 2004
Problem 53 Find all triples
of positive integers such that TST 2004
114
Problem 54 Suppose the polynomial
has only real zeros
and let
. Assume that
has no real roots.
Prove that TST 2004
Problem 55 Let be a bijection of the set of all natural numbers onto itself. Prove that there exists positive integers such that TST 2004
Problem 56 A set of 4 points in the plane is said to be Athenian set if there is a point of the plane satisfying (*)
does not lie on any of the lines
(**) the line joining joining
for
to the midpoint of the line
to the midpoint of
,
; is perpendicular to the line
being distinct.
(a) Find all Athenian sets in the plane. (b) For a given Athenian set, find the set of all points and (**)
in the plane satisfying (*) TST 2004
Problem 57 Determine all integers such that some
is divisible by
for TST 2004
115
Problem 58 The game of
is played on an infinite board of lattice points
. Initially there is a point
at
and placing a
. A move consists of removing a at each of the points
from
and
provided both are vacant. Show that at any stage of the game there is a some lattice point
at
with TST 2004
Problem 59 Let be a triangle and let be a point in its interior. Denote by , the feet of the perpendiculars from to the lines , , , respectively. Suppose that by , , the excenters of the triangle of the triangle .
. Prove that
,
Denote is the circumcenter TST 2004
Problem 60 Show that the only solutions of the equation integers
, in positive
and prime are
(i) (ii)
and is a prime of the form
, TST 2004
Problem 61 Determine all functions
such that for all reals
where
is a given
constant. TST 2004
116
Problem 62 Let be a triangle and its incenter. Let triangles and respectively. (a) Show that there exists a function and
and
be the inradii of
such that
where
(b) Prove that TST 2004
Problem 63 Define a function (a) is nondecreasing
by the following rule:
(b) for each ,
i sthe number of times appears in the range of ,
Prove that
and
for all TST 2004
Problem 64 Two runners start running along a circular track of unit length from the same starting point and in the same sense, with constant speeds and respectively, where and are two distinct relatively prime natural numbers. They continue running till they simultaneously reach the starting point. Prove that (a) at any given time , at least one of the runners is at a distance not more than units from the starting point. (b) there is a time such that both the runners are at least the starting point. (All distances are measured along the track). integer function.
units away from is the greatest TST 2004
117
Problem 65 Let
be real numbers such that
. Prove
that TST 2004
Problem 66 Find all primes , the number
with the following property: for any prime
is squarefree (i.e. is not divisible by the square of a prime). TST 2004
Problem 67 Every point with integer coordinates in the plane is the center of a disk with radius
.
(1) Prove that there exists an equilateral triangle whose vertices lie in different discs. (2) Prove that every equilateral triangle with vertices in different discs has side-length greater than . TST 2004
118
Problem 68 Let
be an acute-angled triangle and be a circle with
as
diameter intersecting and at and respectively. Tangents are drawn at and to intersect at . Show that the ratio of the circumcentre of triangle to that if is a rational number. TST 2004
Problem 69 Let
and
two real polynomials. Suppose that there exists an interval than SUCH THAT BOTH AND ARE nEGATIVE FOR both are positive for and . Show that there is a real
be of length greater and such that TST 2004
Problem 70 An integer is said to be good if is not the square of an integer. Determine all integers with the following property: can be represented, in infinitely many ways, as a sum of three distinct good integers whose product is the square of an odd integer. TST 2004
Problem 71 Let point of triangle
be a triangle with all angles . Let be the Fermat , that is, the interior point of such that . For each one of the three triangles , , draw its Euler line - that is, the line connecting its circumcenter
and and its centroid. Prove that these three Euler lines pass through one common point. Remark. The Fermat point is also known as the first Fermat point or the first Torricelli point of triangle . TST 2005
119
Problem 72 Prove that one can find a positive integers , , such that (i) (ii)
such that
, there exist three
; is the cube of an integer. TST 2005
Problem 73 If , , are three positive real numbers such that , prove that TST 2005
Problem 74 Consider a -sided polygon inscribed in a circle ( ). Partition the polygon into triangles using non-intersecting diagonals. Prove that, irrespective of the triangulation, the sum of the in-radii of the triangles is a constant. TST 2005
Problem 75 Let denote the number of positive divisors of the positive integer . Prove that there exist infinitely many positive integers such that the equation does not have a positive integer solution . TST 2005
120
Problem 76 There are students at a university. Some students join together to form several clubs (a student may belong to different clubs). Some clubs join together to form several societies (a club may belong to different societies). There are a total of societies. Suppose that the following conditions hold: i.) Each pair of students are in exactly one club. ii.) For each student and each society, the student is in exactly one club of the society. iii.) Each club has an odd number of students. In addition, a club with students ( is a positive integer) is in exactly societies. Find all possible values of . TST 2005
Problem 77 Let be two rational numbers. Let numbers with the properties: (i)
and
(ii) if Let that
and
be a set of positive real
; , then
.
denote the set of all irrational numbers in . prove that every such , contains an element with property TST 2005
121
Problem 78 Find all functions for any two positive integers Remark. The abbreviation
satisfying and . stands for the set of all positive integers:
. By
, we mean
(and not
). TST 2005
Problem 79 A merida path of order - plane joining
to
is a lattice path in the first quadrant of
using three kinds of steps
and
, i.e.
joins
to
, etc... An ascent
in a merida path is a maximal string of consecutive steps of the form . If denotes the number of merida paths of order with exactly ascents, compute and
. TST 2005
Problem 80 Let be a convex quadrilateral. The lines parallel to and through the orthocentre of intersect and Respectively at and . prove that the perpendicular through orthocentre of triangle
to the line
passes through the TST 2005
122
Problem 81 Given real numbers that there exist integers and s.t.
s.t.
and
, prove
TST 2005
Problem 82 Consider a matrix of size whose entries are real numbers of absolute value not exceeding . The sum of all entries of the matrix is . Let be an even positive integer. Determine the least number such that every such matrix necessarily has a row or a column with the sum of its entries not exceeding in absolute value. TST 2005
Problem 83 For a given triangle ABC, let X be a variable point on the line BC such that the point C lies between the points B and X. Prove that the radical axis of the incircles of the triangles ABX and ACX passes through a point independent of X. TST 2005
Problem 84 Determine all positive integers
, such that TST 2005
123
Problem 85 For real numbers
not all equal to , define a real function . Suppose
for some real
. prove that there exist a real number s.t. TST 2005
Problem 86 Let be a positive integer divisible by . Find the number of permutations of
which satisfy the condition for all
. TST 2006
Problem 87 Let be a parallelogram. A variable line through the vertex intersects the rays and at the points and , respectively. Let and be the -excenters of the triangles and . Show that the angle is independent of the line . TST 2006
Problem 88 There are markers, each with one side white and the other side black. In the beginning, these markers are aligned in a row so that their white sides are all up. In each step, if possible, we choose a marker whose white side is up (but not one of the outermost markers), remove it, and reverse the closest marker to the left of it and also reverse the closest marker to the right of it. Prove that, by a finite sequence of such steps, one can achieve a state with only two markers remaining if and only if is not divisible by . TST 2006
124
Problem 89 Let be a triangle and let be a point in the plane of inside the region of the angle but outside triangle .
that is
(a) Prove that any two of the following statements imply the third. (i) the circumcentre of triangle
lies on the ray
(ii) the circumcentre of triangle
lies on the ray
(iii) the circumcentre of triangle
lies on the ray
. . .
(b) Prove that if the conditions in (a) hold, then the circumcenter of triangles and
lie on the circumcircle of triangle TST 2006
Problem 90 Let be a prime number and let be a finite set containing at least elements. A collection of pairwise mutually disjoint -element subsets of is called a -family. (In particular, the empty collection is a -family.) Let (respectively, ) denote the number of -families having an even (respectively, odd) number of -element subsets of Prove that and differ by a multiple of . TST 2006
Problem 91 Let and . Prove that if
be an equilateral triangle, and let respectively. Let
and
be points on
and
, then the union of the triangular regions covers the triangle
. TST 2006
125
Problem 92 Let
be a triangle with inradius , circumradius
, and with sides
. Prove that
TST 2006
Problem 93 the positive divisors Suppose
of a positive integer are ordered
. Find all possible values of
. TST 2006
Problem 94 Let be arithmetic progressions of integers, each of terms, such that any two of these arithmetic progressions have at least two common elements. Suppose of these arithmetic progressions have common difference and the remaining arithmetic progressions have common difference where . Prove that
TST 2006
Problem 95 Find all triples
such that satisfying
are integers in the set and
. TST 2006
126
Problem 96 Let be a real number for each be an integer such that
Let
and each
and be positive integers such that
integers
and let
. Prove that there exist
not all zero, such that
TST 2006
Problem 97 Let
be subsets of a finite set such that
each . For a subset of let for each subset of at least one of the following conditions holds , Prove that
,
for . Suppose
.
. TST 2006
Problem 98 Show that in a non-equilateral triangle, the following statements are equivalent: The angles of the triangle are in arithmetic progression. The common tangent to the Nine-point circle and the Incircle is parallel to the Euler Line. TST 2007
127
Problem 99 Find all integer solutions of the equation TST 2007
Problem 100 Let be the set of all bijective functions from the set to itself. For each
define
Determine (Here
for all
) TST 2007
Problem 101 Let be a trapezoid with parallel sides and lie on the line segments and , respectively, so that . Suppose that there are points segment
and
satisfying
that the points
,
,
. Points
on the line Prove
and
are concyclic.| TST 2007
Problem 102 Let
be non-negative real numbers such that and
Show that TST 2007
128
Problem 103 Given a finite string of symbols and , we denote number of s in minus the number of s (For example, ). We call a string
as the
balanced if every substring
of
(consecutive symbols) has the property (Thus is not balanced, since it contains the substring whose value is Find, with proof, the number of balanced strings of length TST 2007
Problem 104 A sequence of real numbers here denotes the greatest integer not exceeding for sufficiently large.
is defined by the formula is an arbitrary real number, , and
. Prove that TST 2007
Problem 105 Let
be a finite set of points in the plane such that no three of them are
on a line. For each convex polygon
whose vertices are in , let
be the
number of vertices of , and let be the number of points of which are outside . A line segment, a point, and the empty set are considered as convex polygons of , , and vertices respectively. Prove that for every real number where the sum is taken over all convex polygons with vertices in . TST 2007
129
Problem 106 Circles and with centers and are externally tangent at point and internally tangent to a circle at points and respectively. Line is the common tangent of and at . Let be the diameter of perpendicular to , so that are on the same side of . Prove that lines , , and are concurrent. TST 2007
Problem 107 Find all integer solutions
of the equation
where
is a prime such that TST 2007
Problem 108 Find all function(s)
satisfying the equation
For all TST 2007
Problem 109 Let be a triangle with contact of Incircle And Nine-Point Circle, Then being inradius.
.Prove that if ,
is point of
TST 2009
130
Problem 110 Let us consider a simple graph with vertex set of integers with
, are elements of V.
is connected to for all integers k. Prove that for all
Problem 111 Let
. All ordered pair
by an edge and to , there exists a path fromm
by another edge to
. TST 2009
be two distinct odd natural numbers.Define a Sequence
like following:
. Prove that there exists a natural number
such that
Problem 112 Let be circumcircle of & internally.Define Prove That
.Let
. TST 2009
be radius of circle touching
similarly. . TST 2009
131
Problem 113 Let and complex coefficients.
be two monic polynomials of degree= having
We know that there exist complex numbers
, such that
. Prove that there exists
such that . TST 2009
Problem 114 Prove The Following identity:
. The Second term on the left hand side is to be regarded as zero for j=0. TST 2009
Problem 115 Let
be any point in the interior of a
.Prove That
. TST 2009
Problem 116 Let be a natural number
which divides
.Prove That
. TST 2009
132
Problem 117 Let
and
be two polynomials with real
coefficients. Let g(x) have than .
as two of its roots. Prove That
has a positive root less TST 2009
Problem 118 For a certain triangle all of its altitudes are integers whose sum is less than 20. If its Inradius is also an integer Find all possible values of area of the triangle. TST 2009
Problem 119 Find all integers
with the following property:
There exists three distinct primes such that whenever are distinct positive integers with the property that at least one of divides one of divides all of these differences.
, TST 2009
133
Problem 120 Let and
be a simple graph with vertex set
are connected by an edge for
. Let
be the induced subgraph associated with components of Let
. be a subset of
. Let
and
be number of
having an odd number of vertices. for
Prove That
.
. TST 2009
Problem 121 Let of
,
be a triangle in which
be the altitude from
. Suppose that orthocenter of
on
, and
. Let
be the midpoint
be the altitude from
produced meets (extended) at , prove that is perpendicular to
. If .
onto
is the TST 2010
Problem 122 Two polynomials
and
have real coefficients, and is an interval on the real line of length greater than . Suppose and take negative values on , and they take non-negative values outside . Prove that there exists a real number such that
. TST 2010
134
Problem 123 For any integer
, let
be the maximum number of triples
consisting of non-negative integers (not necessarily distinct) such that the following two conditions are satisfied: (a)
for all
(b)
, then
Determine
;
, for all
and
.
. TST 2010
Problem 124 Let . Prove that
be positive real numbers such that
TST 2010
Problem 125 Given an integer distinct positive integers
and (Here prime to
, show that there exist an integer an and , all greater than , such that the sums
are both -the powers of some integers. denotes the number of positive integers less than .)
and relatively TST 2010
135
Problem 126 Let be a given integer. Show that the number of strings of length consisting of s and s such that there are equal number of and blocks in each string is equal to
TST 2010
Problem 127 Let be a cyclic quadrilateral and let be the point of intersection of its diagonals and . Suppose and meet in . Let the midpoints of and be and respectively. If is the circumcircle of triangle , prove that is tangent to . TST 2010
Problem 128 Call a positive integer good if either or can be written as product of Even number of prime numbers, not necessarily distinct. Let
where
are positive integers.
(a) Show that there exist distinct positive integers
such that
are all good numbers. (b) Suppose . Prove that
are such that .
is a good number for all positive integers TST 2010
136
Problem 129 Let be a array of positive real numbers such that the sum of numbers in row as well as in each column is . Show that there exists
and
such that
TST 2010
Problem 130 Let
be a triangle. Let
be the brocard point. Prove that
TST 2010
Problem 131 Find all functions for all reals
such that TST 2010
Problem 132 Prove that there are infinitely many positive integers exists consecutive odd positive integers and
for which there
such that
are both perfect squares. If
are two positive
integers satisfying this condition, then we have TST 2010
137
Problem 133 Let
be a triangle each of whose angles is greater than
. Suppose a circle centered with in
cuts segments
in
in
and
such that they are on a circle in counterclockwise direction in that
order.Suppose further
are equilateral. Prove that:
The radius of the circle is
where
is an area.
TST 2011
Problem 134 Let the real numbers and
satisfy the relations
Prove that TST 2011
Problem 135 A set of distinct integer weights
is said to
be balanced if after removing any one of weights, the remaining weights can be split into two subcollections (not necessarily with equal size)with equal sum. Prove that if there exist balanced sets of sizes size
then also a balanced set of
.
Prove that for all odd
there exist a balanced set of size . TST 2011
138
Problem 136 Find all positive integer satisfying the conditions
is a perfect square. TST 2011
Problem 137 Suppose
are non-integral real numbers for
is an integer for all integers is rational.
such that
. Prove that none of TST 2011
Problem 138 Let be a non-empty finite subset of positive integers . A subset of is called good if for every integer there exists an in such that . Let
Prove that : If
is not good then the number of pairs
the number of good subsets of
in
is even.
is odd. TST 2011
139
Problem 139 Let
be a convex pentagon such that and
Let
let be the circumcenter of triangle that
be the midpoint of
Given that
and prove
TST 2011
Problem 140 Prove that for no integer is
a perfect square. TST 2011
Problem 141 Consider a square grid which is divided into unit squares(think of a chess-board). The set of all unit squares intersecting the main diagonal of the square or lying under it is called an -staircase. Find the number of ways in which an -stair case can be partitioned into several rectangles, with sides along the grid lines, having mutually distinct areas. TST 2011
Problem 142 Let bisectors with
be an acute-angled triangle. Let on
be internal
respectively. Prove that
TST 2011
Problem 143 Find all pairs
of nonnegative integers for which TST 2011 140
Problem 144 Let such that
and
for all integers
be two infinite sequences of integers
. Prove that there exists a positive integer such that TST 2011
Problem 145 Let on the segment such that
be an isosceles triangle with . Let be a point such that . Let be a point on the segment . Prove that . TST 2012
Problem 146 Let
and
be real numbers. Prove that the equation has real roots. TST 2012
Problem 147 How many -tuples which simultaneously true?
of natural numbers are there for and
are TST 2012
141
Problem 148 Let
be a trapezium with
such that is between and respectively. Let intersect that
. Let
be a point on
; and let be the midpoints of in and intersect in
. Prove
. TST 2012
Problem 149 Let be integers where is a prime. Prove that the following statements are equivalent:
TST 2012
Problem 150 Let
be a function such that for all for all
. Prove that satisfies
. TST 2012
Problem 151 The circumcentre of the cyclic quadrilateral intersection point of the circles and , other than
is , is
. The second , which lies in
the interior of the triangle . Choose a point on the extension of beyond , and a point on the extension of beyond . Prove that if and only if
. TST 2012
142
Problem 152 Let complex coefficients such that
be a polynomial with and
. Prove that
TST 2012
Problem 153 Determine the greatest positive integer that satisfies the following property: The set of positive integers can be partitioned into subsets such that for all integers exist two distinct elements of whose sum is
and all
there TST 2012
Problem 154 Determine all sequences of positive integers, such that for every positive integer there exists an integer with
TST 2012
Problem 155 Show that there exist infinitely many pairs of positive integers with the property that divides , divides , and TST 2012
143
Problem 156 Suppose that students are standing in a circle. Prove that there exists an integer with such that in this circle there exists a contiguous group of students, for which the first half contains the same number of girls as the second half. TST 2012
Problem 157 Let
be a triangle with
. The angle bisector of
and let
be the midpoint of
intersects the circle through
and
at the
point inside the triangle . The line intersects the circle through and in two points and . The lines and meet at a point , and the lines and meet at a point . Show that is the incentre of triangle . TST 2012
Problem 158 Let
be a nonempty set of primes satisfying the property that for each
proper subset of , all the prime factors of the number in . Determine all possible such sets .
are also TST 2012
Problem 159 In a array we have positive reals s.t. the sum of the numbers in each of the columns is . Show that we can select a number in each column s.t. the sum of the selected numbers in each row is at most
. TST 2012
144
Problem 160 A quadrilateral a circle with center . Prove that quadrilateral
without parallel sides is circumscribed around is a point of intersection of middle lines of
(i.e. barycentre of points .
) iff TST 2012
Problem 161 Find the least positive integer that cannot be represented as for some positive integers
. TST 2012
Problem 162 Let
denote the set of all positive real numbers. Find all functions
satisfying
for all
. TST 2012
Problem 163 For a prime , a natural number and an integer , we let denote the exponent of in the prime factorisation of and
. Find all pairs
. For example,
such that
. TST 2013
145
Problem 164 Let
by a cyclic quadrilateral with circumcenter
the point of intersection of the diagonals circumcenters of triangles
and
, and
,
. Let
be
the
, respectively. Prove that TST 2013
Problem 165 We define an operation
on the set
by
For two natural numbers and , which are written in base as and
(possibly with leading 0's), we define
where written in base is . For example, we have For a natural number , let
with since , where
, for and
.
denotes the largest
integer less than or equal to . Prove that is a bijection on the set of natural numbers. TST 2013
Problem 166 Let be positive real numbers such that positive integer then prove that
. If is a
TST 2013
146
Problem 167 In a triangle
with
such that the inradii of triangles prove that
, and
is a point on the segment are equal. If
then
. TST 2013
Problem 168 A marker is placed at the origin of an integer lattice. Calvin and Hobbes play the folLowing game. Calvin starts the game and each of them takes turns alternatively. At each turn, one can choose two (not necessarily distinct) integers , neither of which was chosen earlier by any player and move the marker by units in the horizontal direction and units in the vertical direction. Hobbes wins if the marker is back at the origin any time after the first turn. Prove or disprove that Calvin can prevent Hobbes from winning. Note: A move in the horizontal direction by a positive quantity will be towards the right, and by a negative quantity will be towards the left (and similar directions in the vertical case as well). TST 2013
Problem 169 Let be an integer. There are beads numbered . Two necklaces made out of some of these beads are considered the same if we can get one by rotating the other (with no flipping allowed). For example, with , the necklace with four beads
in the clockwise order is same as the one with
in the clockwise order, but is different from the one with clockwise order.
in the
We denote by (respectively ) the number of ways in which we can use all the beads to make an even number (resp. an odd number) of necklaces each of length at least . Prove that
divides
. TST 2013
147
Problem 170 In a triangle , with , let and denote its circumcenter and orthocenter, respectively. Let be the reflection of with respect to
. Prove that
and
are collinear if and only if
. TST 2013
Problem 171 For a positive integer , a cubic polynomial is said to be -good if there exist distinct integers such that all the roots of the polynomial are integers for prove that there exists an -good cubic polynomial.
. Given a positive integer TST 2013
Problem 172 Find all functions from the set of real numbers to itself satisfying for all real numbers
. TST 2013
Problem 173 An integer is called friendly if the equation has a solution over the positive integers. a) Prove that there are at least friendly integers in the set b) Decide whether is friendly.
. TST 2013
148
Problem 174 Players and play a game with coins and boxes arranged around a circle. Initially distributes the coins among the boxes so that there is at least coin in each box. Then the two of them make moves in the order by the following rules: (a) On every move of his passes coin from every box to an adjacent box. (b) On every move of hers chooses several coins that were not involved in 's previous move and are in different boxes. She passes every coin to an adjacent box. Player 's goal is to ensure at least coin in each box after every move of hers, regardless of how plays and how many moves are made. Find the least that enables her to succeed. TST 2013
Problem 175 For a positive integer , a sum-friendly odd partition of is a sequence
of odd positive integers with and such that for all positive integers , can be uniquely written as a subsum . (Two subsums and with and are considered the same if
and
for
.) For example, is a sum-friendly odd partition of . Find the number of sum-friendly odd partitions of . TST 2013
Problem 176 In a triangle
, let denote its incenter. Points
chosen on the segments and
are
, respectively, such that . The circumcircles of triangles
intersect lines
, respectively, at points
), respectively. Prove that
(different from
are concyclic. TST 2013
149
Problem 177 Let be an integer and the set of all positive integers that are greater than or equal to . Let be a nonempty subset of such that the following two conditions hold: I. II.
if
with
if with Prove that
, then , then
.
. TST 2013
Problem 178 A positive integer is called a double number if it has an even number of digits (in base 10) and its base 10 representation has the form with for , and . For example, is a double number. Determine whether or not there are infinitely many double numbers such that is a square and is not a power of . TST 2013
Problem 179 Let
be an integer and
a sequence of
polynomials with integer coefficients. One is allowed to make moves follows: in the -th move
one chooses an element
as
of the sequence with
degree of at least and replaces it with stops when all the elements of the sequence are of degree . If
. The process
, determine whether or not it is possible to make appropriate moves such that the process stops with a sequence of identical polynomials of degree 1. TST 2013
150
Problem 180 In a triangle , with , is a point on the line such that is perpendicular to . A circle passing through and touching the line . Let
at a point
intersects the line
be a point on the line
different from
be the point of intersection of the lines
and
are concyclic if and only if
for the second time at such that
. Let
. Prove that the points
is perpendicular to
. TST 2013
Problem 181 Let be an odd prime and an odd natural number.Show that does not divide TST 2014
Problem 182 Let
be positive real numbers.Prove that . TST 2014
Problem 183 In a triangle , points and are on and respectively such that , is not perpendicular to and is not perpendicular to .Let be the circle with as center and as its radius.Find the angles of triangle given that the orthocenter of triangles and lie on . TST 2014
151
Problem 184 Let and be rational numbers, such that that is the square of a rational number.
. Prove TST 2014
Problem 185 Let be a natural number.A triangulation of a convex n-gon is a division of the polygon into triangles by drawing diagonals no two of which intersect at an interior point of the polygon.Let denote the number of triangulations of a regular n-gon such that each of the triangles formed is isosceles.Determine
in terms of . TST 2014
Problem 186 For integers
we define if
Given a natural number
if
and
. show that there exist natural numbers
such that
with
,where , being composed with itself times. TST 2014
Problem 187 Find all polynomials
with integer coefficients such that
and
are co-prime for all natural numbers . TST 2014
152
Problem 188 Let be a positive integer. Find the smallest integer with the following property; Given any real numbers such that and for , it is possible to partition these numbers into groups (some of which may be empty) such that the sum of the numbers in each group is at most . TST 2014
Problem 189 Starting with the triple sequence of triples
, define a
by
for .Show that each of the sequences to a limit and finds these limits.
converges TST 2014
Problem 190 In a triangle incircle touches the line triangle
, let be its incenter; the point at which the ; the midpoint of and the orthocenter of
. Prove that the line
is perpendicular to the line
. TST 2014
153
Problem 191 For let be non-zero real numbers, and let .Suppose that the following statements hold:
satisfy triangle inequality also satisfy triangle inequality. Prove that exactly one of
is negative. TST 2014
Problem 192 Let be a positive integer, and let be an infinite sequence of real numbers. Assume that for all nonnegative integers and there exists a positive integer
such that
Prove that the sequence is periodic, i.e. there exists some for all .
such that TST 2014
Problem 193 In a triangle , with and , is a point on line different from . Suppose that the circumcenter and orthocenter of triangles and lie on a circle. Prove that . TST 2014
154
Problem 194 Determine whether there exists an infinite sequence of nonzero digits and a positive integer such that for every integer , the number is a perfect square. TST 2014
Problem 195 In how many ways rooks can be placed on a by chess board such that every row and every column has at least one rook? (Any number of rooks are available,each square can have at most one rook and there is no relation of attacking between them) TST 2014
Problem 196 Prove that in any set of pairs
and
with
distinct real numbers there exist two or
, such that TST 2014
Problem 197 Find all positive integers and such that
. TST 2014
Problem 198 Let
be a triangle with
. Let
and
be two different
and
is located
points on line
such that
between
. Suppose that there exists an interior point
and
for which that
. Let the ray
intersect the circle
of segment at
. Prove
. TST 2014 155
Problem 199 Find all positive integers integers.
such that
and
are also TST 2015
Problem 200 A
-digit number is called a
number if its digits belong to the set
and the difference of every pair of consecutive digits is . a) Find the total number of cute numbers. b) Prove that the sum of all cute numbers is divisible by . TST 2015
Problem 201 Prove that for any triangle
, the inequality
holds. TST 2015
Problem 202 Let be a triangle in which . Let be its orthocentre and its circumcentre. Let and be respectively the midpoints of the arc not containing and arc not containing . Let and be respectively the reflections of on a circle if and only if
in
and
in
. Prove that
lie
are collinear. TST 2015
156
Problem 203 For a composite number , let
denote its largest proper divisor.
Show that there are infinitely many for which
is a perfect square. TST 2015
Problem 204 Every cell of a board is coloured either by red or blue. Find the number of all colorings in which there are no squares in which all cells are red. TST 2015
Problem 205 Let intersect at
be a convex quadrilateral and let the diagonals . Let
and
be respectively the incentre of triangles . Let
triangles
be respectively the excentres of opposite
circle if and only if
. Show that
lie on a
lie on a circle. TST 2015
Problem 206 Let and be two polynomials with integer coefficients such that the leading coefficients of both the polynomials are positive. Suppose the sets an integer such that
and
is odd and
are the same. Prove that there exists . TST 2015
157
Problem 207 Let points be given inside a rectangle such that no two of them lie on a line parallel to one of the sides of . The rectangle is to be dissected into smaller rectangles with sides parallel to the sides of in such a way that none of these rectangles contains any of the given points in its interior. Prove that we have to dissect into at least smaller rectangles. TST 2015
Problem 208 Let
be an integer, and let
be the set
Determine the largest positive integer that cannot be written as the sum of one or more (not necessarily distinct) elements of . TST 2015
Problem 209 Find all functions from , for all
such that . TST 2015
Problem 210 Let
be a simple graph on the infinite vertex set
. Suppose every subgraph of -colorable, Prove that itself is -colorable.
on a finite vertex subset is TST 2015
158
Problem 211 In a triangle the incentres of triangles
, a point and
intersect the circumcircle of triangle
is on the segment , Let and respectively. The lines and at
and
be
, respectively.
Let be the point of intersection of lines and . Suppose is also the reflection of in where is the incentre of triangle . Prove that . TST 2015
Problem 212 Find all triples positive integers and such that
consisting of a prime number and two and
are both powers of . TST 2015
Problem 213 There are lamps, each with two states: or . For each non-empty subset of the set of these lamps, there is a which operates on the lamps in ; that is, upon this button each of the lamps in changes its state(on to off and off to on). The buttons are identical and it is not known which button corresponds to which subset of lamps. Suppose all the lamps are off initially. Show that one can always switch all the lamps on by performing at most
operations. TST 2015
Problem 214 Consider a fixed circle with three fixed points Also, let us fix a real number
. For a variable point
, let be the point on the segment such that second point of intersection of the circumcircles of the triangles . Prove that as
varies, the point
and
on it. on
. Let be the and
lies on a fixed circle. TST 2015 159
Problem 215 Let in
we have
necessarily from all
be a finite set of pairs of real numbers such that for any pairs be a pair of real numbers(not
). We define
, if in
. Let
for which
there exists an integer
for all we let
; otherwise we choose a pair
and set such that
as follows: for . Show that
. TST 2015
Problem 216 Let
be a given integer. Prove that infinitely many terms of the
sequence , defined by are odd. (For a real number , denotes the largest integer not exceeding .) TST 2015
Problem 217 An acute-angled is inscribed into a circle . Let be the centroid of , and let be the altitude of this triangle. A ray meets at . Prove that the circumcircle of the triangle is tangent to TST 2016
Problem 218 Given that is a natural number such that the leftmost digits in the decimal representations of and are the same, find all possible values of the leftmost digit. TST 2016
160
Problem 219 Let a,b,c,d be real numbers satisfying . Prove that
and
TST 2016
Problem 220 We say a natural number is perfect if the sum of all the positive divisors of is equal to . For example, is perfect since its positive divisors add up to distinct prime divisors.
. Show that an odd perfect number has at least
Note: It is still not known whether odd perfect numbers exist. So assume such a number is there and prove the result. TST 2016
Problem 221 Find all functions for all reals .
such that TST 2016
161
Problem 222 An equilateral triangle with side length is divided into congruent triangular cells as shown in the figure below. Initially all the cells contain . A move consists of selecting two adjacent cells (i.e., cells sharing a common boundary) and either increasing or decreasing the numbers in both the cells by simultaneously. Determine all positive integers such that after performing several such moves one can obtain consecutive numbers some order.
in
TST 2016
Problem 223 Let be an acute triangle with orthocenter . Let be the point such that the quadrilateral is a parallelogram. Let be the point on the line such that bisects . Suppose that the line intersects the circumcircle of the triangle at and . Prove that . TST 2016
Problem 224 Suppose that a sequence
of positive real numbers satisfies
for every positive integer . Prove that for every . TST 2016
162
Problem 225 Let be a natural number. A sequence is called
if each
of
is an element of the set
numbers
and the
ordered pairs are all different for (here we consider the subscripts modulo ). Two good sequences and are called if there exists an integer such that for all (again taking subscripts modulo ). Suppose that there exists a non-trivial permutation (i.e., a permutation which is different from the identity permutation) of
and an
good sequence
which is similar to
. Show that
. TST 2016
Problem 226 Suppose positive integers each of
are two positive rational numbers. Assume for some , it is known that
and
is a rational number. Prove that
is a rational number. TST 2016
Problem 227 Let
and be positive integers such that
for are integers, then
. Define
. Prove that if all the numbers is divisible by an odd prime. TST 2016
163
Problem 228 For a finite set of positive integers, a partition of into two disjoint nonempty subsets and is if the least common multiple of the elements in is equal to the greatest common divisor of the elements in . Determine the minimum value of such that there exists a set of positive integers with exactly good partitions. TST 2016
Problem 229 Let be a natural number. We define sequences and integers as follows. We let and . For , we let
of
Given that is a power of two. TST 2016
for some natural number , prove that
Problem 230 Let be an acute triangle and let be the midpoint of . A circle passing through and meets the sides and at points and respectively. Let that
be the point such that
lies on the circumcircle of
is a parallelogram. Suppose
. Determine all possible values of . TST 2016
Problem 231 Let be an odd natural number. We consider an
grid which is
made up of unit squares and edges. We color each of these edges either or . If there are at most edges, then show that there exists a unit square at least three of whose edges are . TST 2016
164
Problem 232 Let
be an acute triangle with circumcircle . Let
and
be respectively the midpoints of the arcs and of . Show that the inradius of triangle is not less than the inradius of triangle . TST 2016
Problem 233 Find all functions such that for all (Here denotes the set of all real numbers.) TST 2016
Problem 234 Let
denote the set of all natural numbers. Show that there exists two
nonempty subsets and of such that every number in can be expressed as the product of a number in and a number in ; each prime number is a divisor of some number in and also some number in ; one of the sets and has the following property: if the numbers in this set are written as , then for any given positive integer there exists such that
. Each set has infinitely many composite numbers. TST 2016
165
Problem 235 Let
and with an integer and
real numbers, . Define
and
. (a) Find the number of unordered pairs of polynomials two common roots. (b) For any
with exactly
, find the sum of the elements of
. TST 2017
Problem 236 Find all positive integers
such that TST 2017
Problem 237 Let
be a cyclic quadrilateral inscribed in circle with
. Let lines
and
be the projections of
respectively. Let
on the
be the mid-points of sides
respectively. (a) Prove that
are concyclic.
(b) If is the radius of and is the distance between its center and , then find the radius of the circle in (a) in terms of and . TST 2017
166
Problem 238 In an acute triangle . Let
, points
and
lie on side
with
be the circumcenters of triangles , respectively. Prove that
are con-cyclic if and only if
are collinear. TST 2017
Problem 239 Let
be pairwise distinct positive integers such that is an integer. Prove that
is not a
prime number.” TST 2017
Problem 240 There are lamps arranged in a circle in that order. At any given time, each lamp is either on or off. Every second, each lamp undergoes a change according to the following rule: (a) For each lamp , if have the same state in the previous second, then is off right now. (Indices taken mod .) (b) Otherwise,
is on right now.
Initially, all the lamps are off, except for which is on. Prove that for infinitely many integers all the lamps will be off eventually, after a finite amount of time. TST 2017
167
Problem 241 Let
be distinct positive real numbers with
. Prove that
TST 2017
Problem 242 Define a sequence of integers for all
and
. Suppose
is a prime with
. Prove that it is possible to choose
such that
for any
. TST 2017
Problem 243 Let be a positive integer. An matrix is called good if each entry is a non-negative integer, the sum of entries in each row and each column is equal. A permutation matrix is an matrix consisting of ones and zeroes such that each row and each column has exactly one non-zero entry. Prove that any good matrix is a sum of finitely many permutation matrices. TST 2017
Problem 244 Suppose
are non constant polynomials. Suppose neither of
is the square of a real polynomial but square of a real polynomial.
is. Prove that
is not the TST 2017
168
Problem 245 Let be a positive integer relatively prime to . We paint the vertices of a regular -gon with three colors so that there is an odd number of vertices of each color. Show that there exists an isosceles triangle whose three vertices are of different colors. TST 2017
Problem 246 Let and plane. A nonempty, bounded subset there is a point entirely in ; and for any triangle of the indices similar.
in
be fixed points on the coordinate of the plane is said to be nice if
such that for every point
in , the segment
, there exists a unique point for which triangles
points in .
, then the product
and
and a permutation
and
Prove that there exist two distinct nice subsets and such that if
in
lies
are
of the set are the unique choices of
is a constant independent of the triangle TST 2017
Problem 247 Find all positive integers for which all positive divisors of can be put into the cells of a rectangular table under the following constraints: each cell contains a distinct divisor; the sums of all rows are equal; and the sums of all columns are equal. TST 2017
169
Problem 248 Let incenter. The line meets at of triangle .
be a triangle with and let be its meets at , and the line through perpendicular to . Prove that the reflection of in lies on the circumcircle TST 2017
Problem 249 Prove that for any positive integers and we have
TST 2017
Problem 250 Let
be an acute angled triangle with incenter . Line
perpendicular to
at meets
be the incenters of lie on a circle. Prove that
and and .
at points
and
respectively. Let
respectively. Suppose TST 2017
Problem 251 For each
define the polynomial Prove that
(a) For each (b)
,
has a unique positive real root
;
is a strictly increasing sequence;
(c) TST 2017
170
Problem 252 Let be a positive integer which is not a perfect square, and consider the equation
Let
equation admits a solution in
be the set of positive integers for which the with
, and let
integers for which the equation admits a solution in that .
be the set of positive
with
. Show TST 2017
Problem 253 Let
be an acute triangle.
are the touch points of
incircle with
respectively.
intersect incircle at
respectively. If, prove that
Then
. Also prove that there exists integers
,
such that,
. TST 2018
Problem 254 A divisible by
Problem 255 Let
digit number is called interesting if its digits are distinct and is . Then find the number of interesting numbers. TST 2018
be sequences of positive reals such that, for all
Prove that,
. . TST 2018
171
Problem 256 Let be a convex quadrilateral inscribed in a circle with center which does not lie on either diagonal. If the circumcentre of triangle lies on the line , prove that the circumcentre of triangle lies on the line . TST 2018
Problem 257 For an integer
find all
so that
(a)
(b)
(c) TST 2018
Problem 258 A convex polygon has the property that its vertices are coloured by three colors, each color occurring at least once and any two adjacent vertices having different colors. Prove that the polygon can be divided into triangles by diagonals, no two of which intersect in the interior of the polygon, in such a way that all the resulting triangles have vertices of all three colors. TST 2018
Problem 259 A rectangle with odd integer side lengths is divided into small rectangles with integer side lengths. Prove that there is at least one among the small rectangles whose distances from the four sides of are either all odd or all even. TST 2018
172
Problem 260 Let be three points in that order on a line in the plane, and suppose . Draw semicircles and respectively with and as diameters, both on the same side of . Let the common tangent to and touch them respectively at segment and in
and
,
such that the semicircle .
Prove that
. Let
and
with
be points on the
as diameter touches
in
are concyclic.
Prove that
are concyclic. TST 2018
Problem 261 Find all functions
such that for all
. TST 2018
Problem 262 For a natural number
, define
to be the set of all triplets
of natural numbers, with odd and and divides . Find all values of for which
Problem 263 In triangle
, let be the excircle opposite to
be the points where is tangent to intersects line the circle
, such that is finite. TST 2018
at
and
, and . Let
. Let
and
, respectively. The circle
be the midpoint of
. Prove that
is tangent to . TST 2018
173
Problem 264 Sir Alex plays the following game on a row of 9 cells. Initially, all cells are empty. In each move, Sir Alex is allowed to perform exactly one of the following two operations: Choose any number of the form , where is a non-negative integer, and put it into an empty cell. Choose two (not necessarily adjacent) cells with the same number in them; denote that number by . Replace the number in one of the cells with and erase the number in the other cell. At the end of the game, one cell contains , where is a given positive integer, while the other cells are empty. Determine the maximum number of moves that Sir Alex could have made, in terms of . TST 2018
Problem 265 Let be a positive integer. Define a chameleon to be any sequence of letters, with exactly occurrences of each of the letters and . Define a swap to be the transposition of two adjacent letters in a chameleon. Prove that for any chameleon , there exists a chameleon such that cannot be changed to using fewer than
swaps. TST 2018
Problem 266 Let
be a finite set, and let
. Let be an element of
, and let
that
for every in
be the set of all functions from to be the image of with
under . Suppose
. Show that
. TST 2018
174
Problem 267 Find the smallest positive integer or show no such exists, with the following property: there are infinitely many distinct -tuples of positive rational numbers
such that both are integers. TST 2018
Problem 268 Let
be a triangle and
point . Suppose each of the quadrilaterals both circumcircle and incircle. Prove that the center of the triangle.
be cevians concurrent at a and has is equilateral and coincides with TST 2018
Problem 269 Let numbers such that
be a natural number. Let and
be real If
smallest integer larger than
, the
, then show that TST 2018
Problem 270 Determine all integers having the following property: for any integers whose sum is not divisible by , there exists an index such that none of the numbers is divisible by . Here, we let when . TST 2018
175
Problem 271 In an acute angled triangle with , let denote the incenter and the midpoint of side . The line through perpendicular to intersects the tangent from to the incircle (different from line ) at a point > Show that is tangent to the circumcircle of triangle . TST 2019
Problem 272 Show that there do not exist natural numbers that the numbers powers of
such are all TST 2019
Problem 273 Let be a given positive integer. Sisyphus performs a sequence of turns on a board consisting of squares in a row, numbered to from left to right. Initially, stones are put into square , and the other squares are empty. At every turn, Sisyphus chooses any nonempty square, say with stones, takes one of these stones and moves it to the right by at most squares (the stone should say within the board). Sisyphus' aim is to move all stones to square . Prove that Sisyphus cannot reach the aim in less than turns. (As usual,
stands for the least integer
not smaller than . ) TST 2019
Problem 274 Let functions
denote the set of all positive rational numbers. Determine all satisfying
for all TST 2019
176
Problem 275 Let be a natural number. A tiling of a board is a placing of dominos (of size or ) such that each of them covers exactly two squares of the board and they cover all the board.Consider now two separate tilings of a board: one with red dominos and the other with blue dominos. We say two squares are red neighbors if they are covered by the same red domino in the red tiling; similarly define blue neighbors. Suppose we can assign a non-zero integer to each of the squares such that the number on any square equals the difference between the numbers on its red and blue neighbors i.e the number on its red neighbor minus the number on its blue neighbor. Show that is divisible by TST 2019
Problem 276 Let
be a function such that for all pairs
exists a positive integer
of positive integers. Prove that there
which divides all values of . TST 2019
Problem 277 Given any set of positive integers, show that at least one of the following two assertions holds:
(1) There exist distinct finite subsets ;
and
(2) There exists a positive rational number finite subsets of .
of such that
such that
for all TST 2019
177
Problem 278 Let circumcenter
be an acute-angled scalene triangle with circumcircle and . Suppose
incenter of triangle of triangle Let
. Let
, containing
be a point on the arc . Let
lines
. Let
and
be the orthocenter and be the
be the midpoint of the arc
of the circumcircle
. of not containing
, such that
be the circumcenter of triangle
. Prove that the
meet on . TST 2019
Problem 279 Let be a positive integer. The organizing committee of a tennis tournament is to schedule the matches for players so that every two players play once, each day exactly one match is played, and each player arrives at the tournament site the day of his first match, and departs the day of his last match. For every day a player is present on the tournament, the committee has to pay coin to the hotel. The organizers want to design the schedule so as to minimize the total cost of all players' stays. Determine this minimum cost. TST 2019
Problem 280 Determine all non-constant monic polynomials with integer coefficients for which there exists a natural number such that for all
,
divides TST 2019
178
Problem 281 Determine all functions
satisfying for all
. TST 2019
Problem 282 Let be the circumcentre, and be the circumcircle of an acute-angled triangle . Let be an arbitrary point on , distinct from , , , and their antipodes in . Denote the circumcenter of the triangles , , and by , , and , respectively. The lines , , perpendicular to , , and pass through , , and , respectively. Prove that the circumcircle of triangle formed by , , and is tangent to the line . TST 2019
Problem 283 Let
be a set of
distinct positive even numbers and
be a set of distinct positive odd numbers such that Prove that TST 2019
Problem 284 Let
be a triangle with
chosen on the sides respectively so that Let and be the perimeters of the triangles and Prove that
Points
are
, respectively. TST 2019
179
Problem 285 Let
be an integer. Solve in reals: TST 2019
Problem 286 Let the points and be the circumcenter and orthocenter of an acute angled triangle Let be the midpoint of Let be the point on the angle bisector of such that Let be the point such that is a rectangle. Prove that
are collinear. TST 2019
Problem 287 Determine all positive integers satisfying the condition that there exists a unique positive integer such that there exists a rectangle which can be decomposed into congruent squares and can also be decomposed into congruent squares. TST 2019
Problem 288 There are coins on a table. Some are placed head up and others tail up. A group of persons perform the following operations: the first person chooses any one coin and then turns it over, the second person chooses any two coins and turns them over and so on and the -th person turns over all the coins. Prove that no matter which sides the coins are up initially, the persons can come up with a procedure for turning the coins such that all the coins have the same side up at the end of the operations. TST 2019
180
Solutions for Solved Problems (Page 10 - 19)
Solutions Solution. 1. Note that g(1) = f (1) = 0, so 1 is a root of both f ( x ) and g( x ). Let p and q be the other two roots of f(x), so p2 and q2 are the other two roots of g( x ). We then get pq = −c andp2 .q2 = − a, so a = −c2 . Also, (− a)2 = ( p + q + 1)2 = p2 + q2 + 1 + 2( pq + p + q) = −b + 2b = b.Therefore b = c4 . Since f (1) = 0we therefore get 1 + c − c2 + c4 = 0 . Factorising, we get (c + 1)(c3 − c2 + 1) = 0. Note that c3 − c2 + 1 = 0 has no integer root and hence c = −1, b = 1, a = −1. Therefore a2023 + b2023 + c2023 = −1
Solution. 2. denote Sn = αn + βn + γn also ,Sn ∈ Z+ claim:- S10,000+n+k = Sk now from netwon sums clearly Sn can be recursively written in terms of Sn−1 + Sn−2 + · · · + S1 α35005 + β35005 + γ35005 ≡ S35005 ≡ S5005 ( mod 10000) S13 ≡ Sn ( mod 16) S5 ≡ Sn ( mod 625) by CRT Sn ≡ −7( mod 625) Sn ≡ 9( mod 16) Sn ≡ −7( mod 10, 000) Sn ≡ 9993( mod 10, 000), where n = 35005 so S35005 ≡ 9993( mod 10, 000)
Solution. 3. Let D = (0, 0), A = (0, a), B = (−b, 0), C = (c, 0). If you construct squares circumscribing ABWX and CAYZ whose sides are parallel to the axes, it becomes clear that: W X Y Z
= (−( a + b), b) = (− a, a + b) = ( a, a + c) = ( a + c, c)
So we need to show that M and P lie on the y-axis. Since X and Y are equidistant from the y-axis, M lies on the y-axis. The equations for lines CW and BZ are: b ( x − c) a+b+c c y= ( x + b) a+b+c We now see that the intersection, P, is 0, a+bcb+c , so we’re done. y=−
182
Solutions
√
Solution. 4. 2x + 1 = 4x + 2x+1 + 1 which can be written in another form as p √ x + 4x +1 + 2x +2 + 1, now this can be further expanded so on to get g ( x ) = 4 q p √ 4x + 4x+1 + 4x+2 + · · · so we have g( x ) = 2x + 1. so g(2021) = 22021 + 1 which is 8609( mod 10000) so we get 23 as our ans
Solution. 5. as we are given xyzw = 1 , so from this we get second equation as y z
+ yx + wx + wz = 2. so say a = yz , b = yx , wx = c, wz = d. so we get a + b + c + d = 2. from fourth equation we get 1a + 1b + 1c + 1d = −1. so we get abc + abd + acd + bcd = −1. also from third equation we get ab + bc + cd + ad + w2 y2 + x2 z2 = −3. notice we want ac and bd. so ac = x21z2 . so this gives ab + bc + cd + ad + ac + bd = −3. and abcd = 1. so we get a equation α4 − 2α3 − 3α2 + α + 1 = 0 whose roots are a, b, c, d. so we get (α + 1)(α3 − 3α2 + 1) = 0. this gives α = −1. and three distinct complex ( not necessarily non real) solutions. so as α = −1. we get any one pair say yx = −1. so x = −y = k for some k ∈ C. so as z, w, will be distinct we will get 4 quadruples from −k, k, w, z solution so we can have such 4 · 4 = 16 quadruples.
√ Solution. 6. so we construct a triangle ABC such that ∠ ACB = π2 and AB = 3, BC = √ 2, AC = 1. now choose a point P inside the triangle such√that ∠ APC = ∠ APB√= 3 2 ∠ BPC = 2π 3 . so we get [ APC ] + [ APB ] + [ BPC ] = [ ABC ]. so 4 · ( xy + yz + zx ) = 2 . √ 2√ 2 . 3
now adding the given three equations we get x2 + p √ y2 + z2 = 9−3 6 . and hence we get x + y + z = 3 + 6. now we are provided that p √ √ x2 + xz√+ z2 = 3. so we get ( x + z)2 − xz = 3 or y2 + 3 + 6 − 2y 3 + 6 − zx = 3 2√ and 9−3 6 − y2 + zx = 3. adding these two equations we get y2 = . solving on so we get xy + yz + zx = √
we get
y2
=
√ 6−2 6 9 .
3(3+ 6)
so we get m + n + p + q = 23 .
183
Solutions p Solution. 7. Squaring the given equation, we arrive at the conclusion that 2p q2 + r √ p p is an integer, or therefore q2 + r is an integer. Let q2 + r = u and s2 + t = v. Therefore, we arrive at u2 − q2 = r and v2 − s2 = t. This gives us u − q = 1 from difference of squares and r being prime, and similarly v − s = 1. Therefore, we get u + q = r and v + s = t. This gives us the following four vital equations which we will constantly use throughout the solution: 2q + 1 = r (1) 2s + 1 = t(2) u = q + 1(3) v = s + 1(4) √ p Go back to the original equation now. Since q2 + r = u = q + 1 and s2 + t = v = s + 1, plugging this back into the original equation, we arrive at p + (q + 1) = (s + 1) =⇒ p+q = s . Taking the equation modulo 2, we arrive at p = 2, q = 2, or , s = 2. Assume p p = 2, which p gives us s = q + 2. Going back to the original equation, 2 2+r = we have 2 + q (q + 2)2 + t. Therefore, p psquaring this, we get 4 + (q + r ) + 4 q2 + r = q2 + 4q + 4 + t. Therefore, r + 4 q2 + r = 4q + t =⇒ (3) =⇒ r + 4(q + 1) = 4q + t =⇒ r + 4 = t. Therefore, t = 2q + 5 using (1). Since t is prime, 2q + 5 is prime, since s is prime q + 2 is prime, and q is prime, and since r is prime 2q + 1 is prime. Therefore, we have an obvious contradiction mod 3 unless one of the values is 3. The only value that gives q being prime is 3, which gives ( p, q, r, s, t) = (2, 3, 7, 5, p11). √ If q = 2, then from q2 + r = q + 1 we have 4 + r = 3 =⇒ r = 5. Plugging this back into the original equation, we obtain p + 3 = s + 1 =⇒ p + 2 = s. We also have t = 2s + 1 from (2), so therefore from p being prime, we must have s − 2 being prime, from t being prime we must have 2s + 1 being prime, and s is prime. This is again a contradiction mod 3 unless one of the values is 3. If s = 3, then we get p = 1 absurd. If s − 2 = 3, then s = 5 and p = 3 and t = 11. There are no other solutions for this case. Therefore, we arrive at the solution ( p, q, r, s, t)√ = (3, 2, 5, 5, 11). 2 Lastly, p we have to consider s = 2. Since s + t = s + 1 = 3, we must have p + q2 + r = 3, which is clearly absurd. The solutions are whence ( p, q, r, s, t) = (2, 3, 7, 5, 11), (3, 2, 5, 5, 11) .
Solution. 8. Let P( x, y) be the assertion that f ( x f (y) + f ( x )) = 2 f ( x ) + xy. P(1, y) shows that f is surjective. Hence there exists z such that f (z) = 0. P(z, z) implies f (0) = z2 . Assume z = 0. Then P( x, 0) implies f ( f ( x )) = 2 f ( x ) and because of surjectivity we get f ( x ) = 2x for all x but this does not satisfy the original equation. Hence z ̸= 0. Now, P(z, y) implies f (z f (y)) = zy and therefore f must also be 184
Solutions injective hence bijective. P(z, 0) implies f (z3 ) = 0 = f (z) and because of injectivity we get z = z3 and thus z = ±1. In any case f (0) = z2 = 1. Now, P(−1, −1) implies f (−1) = 0 and thus z = −1. Now, P( x, −1) yields f ( f ( x )) = 2 f ( x ) − x meaning we can prove easily by induction f (n) = n + 1 for every positive integer n. Also, P(−1, y) yields f (− f ( x )) = − x so that we can extend this proof to the negative integers setting x = n. Assume f ( a) = 2a for some a. Then P( a, −4) implies f (− a) = 0 and thus a = 1 meaning this a is unique. Now, P( x, −2) implies f ( f ( x ) − x ) = 2( f ( x ) − x ) and therefore f ( x ) − x = a = 1 and hence f ( x ) = x + 1 for every real x which is indeed a solution.
Solution. 9. The question is asking, how many permutations of this set have no orbit with length greater than 2? There can be 1, 3, 5, or 7 orbits of length 1. One orbit of length 1: pick a number, then count how many pairings are possible. 7 · 5 · 3 · 1 = 105 Three orbits of length 1: choose three, then count the pairings. (73) · 3 · 1 = 105 Five orbits of length 1: choose five, then just one pairing is possible. (75) · 1 = 21 Seven orbits of length 1: that is, f ( a) = a 1 105 + 105 + 21 + 1 = 232
Solution. 10. Lemma 1: Let
jp
q
f n ( x ) ̸=
q
f n+1 ( x ) =⇒
q
f n +1 ( x ) =
q
f n +2 ( x )
k f n ( x ) = a.
a2 ≤ f n ( x ) ≤ a2 + 2a and a2 + 2a + 1 ≤ f n+1 ( x ). a2 + j2a + 1 ≤ kf n+1 ( x ) ≤ a2 + 3a + 1 = a2 + 3a + 1 < ( a + 2)2 p =⇒ f n ( x ) = a + 1. Calculating f n+2 ( x ) for the largest value of f n+1 ( x ): 2 2 f n+j2 ( x ) ≤ a2 +k 3a + 1+1+a+ jp k 1 = a + 4a + 3 < ( a + 2) p f n +1 ( x ) = f n+2 ( x ) = a + 1. ■ So q q q q Lemma 2: f n (x) = f n+1 ( x ) = a =⇒ f n +2 ( x ) = f n +3 ( x ) = a + 1 a2 ≤ f n ( x ) < f n+1 ( x ) ≤ a2 + 2a. Calculating f n+2 ( x ) for the smallest value of f n ( x ): a2 + a + 1 ≤ f n+1 ( x ) and f n+2 ( x ) ≥ a2 + a + 1 + 1 + a = a2 + 2a + 2 > ( a + 1)2 . 185
Solutions Calculating f n+2 ( x ) for the largest value of f n+1 ( x ): f n+2 ( x ) ≤ a2 + 2a + 1 + a = a2j+ 3a + 1 0, α ∈ R such that z = ρ(cos α + i sin α). α α √ The equation w3 = z has the roots: w0 = 3 ρ cos + i sin ; 3 3 α + 2π α + 4π α + 2π α + 4π √ √ 3 3 w1 = ρ cos + i sin ; w2 = ρ cos + i sin . Hence: 3 3 3 3 {z1 + z2 , z1 + z3 , z2 + z3 } ⊂ {w0 , w1 , w2 }. Using the property P results: {z1 + z2 , z1 + z3 , z2 + z3 } = {w0 , w1 , w2 }. WLOG, we can consider: z1 +z2 = w0; z1 + z3= w1 ; z 2+ √ α α √ + π − i sin +π ; z3 = w2 . Results: z1 − z2 = w1 − w2 = 3 ρ · 3 sin 3 3 α+π α+π √ √ z2 − z3 = w0 − w1 = 3 ρ · 3 sin − i cos ; z 3 − z 1 = w2 − w0 = 3 3 √ α + 2π α + 2π √ √ √ 3 ρ· 3 sin − i cos . | z1 − z2 | = | z2 − z3 | = | z3 − z1 | = 3 ρ · 3 3 3
Solution. 15. First note that
R π/2 0
sin(sin x )dx =
R1 0
√sin x dx. 1− x 2
Now we also know that
187
Solutions x−
x3 3!
≤ sin x ≤ x for all x ∈ R. So 3 Z 1 x − x3!
√
0
=⇒
Z 1
√
0
x 1 − x2
1−
x2
dx −
dx ≤
1 3!
Z 1
Z 1 0
√
0
=⇒ 1 − =⇒
sin x √ dx ≤ 1 − x2
x3 1 − x2
1 ≤ 9
8 ≤ 9
dx ≤
Z 1 0
Z π/2 0
Z 1 0
Z 1 0
√
x 1 − x2
dx
sin x √ dx ≤ 1 − x2
Z 1
√
0
x 1 − x2
dx
sin x √ dx ≤ 1 1 − x2
sin(sin x )dx ≤ 1
Hence, proved.
Solution. 16. Let L := limx→∞ x f ( x ). So there exists N > 1 such that | x f ( x ) − L| ≤ 1 for x ≥ N. Now write Z ∞ f (x)
x
1
dx =
Z N f (x)
x
1
Z ∞ f (x)
dx +
N
x
(1)
dx.
The first integral on the right-hand side of (1) is a proper integral and so convergent. For the second integral, write
| x f ( x ) − L| | L| 1 + | L| | f ( x )| | x f ( x )| ≤ + 2 ≤ . (2) = 2 2 x x x x x2 R ∞ f (x) dx is convergent, 2 N x dx is (absolutely) convergent too, by the comx
R∞ So, since N parison test. Next, put x t = y. Then t
Z a 1
f ( x t ) dx =
and so lim t
t→∞
Z a 1
Z at Z at Z at f (y) 1/t f (y) 1/t f (y) y dy = (y − 1) dy + dy 1
y
1
t
f ( x ) dx = lim
Z at f (y)
t→∞ 1
y
y
(y
1/t
y
1
− 1) dy +
Z ∞ f (y) 1
y
dy.
So we are done if we show that lim
Z at f (y)
t→∞ 1
y
(y1/t − 1) dy = 0.
(3)
To prove (3), we use (2) to write 0≤
Z at | f (y)| 1
y
(y1/t − 1) dy ≤
Z N | f (y)| 1
y
(y1/t − 1) dy + (1 + | L|)
Z at 1/t y −1 N
y2
dy. 188
Solutions So if M := maxy∈[1,N ] | f (y)|, then 0≤
Z at | f (y)| 1
y
(y1/t − 1) dy ≤ M
Z N 1/t y −1
y
1
dy + (1 + | L|)
Z at 1/t y −1 N
y2
dy.
An easy calculation shows that lim
Z N 1/t y −1
t→∞ 1
y
dy = lim
Z at 1/t y −1
t→∞ N
y2
dy = 0
and that completes the proof of (3) and the first part of your problem. For the second part of your problem, apply the first part to the function f ( x ) = which satisfies all the conditions required, to get lim t
t→∞
Z a 1
dx = 1 + xt
Z ∞ 1
1 1+ x ,
dx = ln 2. x (1 + x )
Solution. 17. Note that since RHS ∈ Z, then all solutions must be integers. Let n = 2 and the equation is x = n2 and so : x = 2k implies 2k = k and so k = 0 and so x = 0 which indeed is a solution. x = 2k + 1 implies 2k + 1 = k and so k = −1 and so x = −1 which indeed is a solution. SoA2 = {−1, 0} Let n = 3 and the equation is x = n2 + n3 and so : x = 6k implies 6k = 5k and so k = 0 and so x = 0 which indeed is a solution. x = 6k + 1 implies 6k + 1 = 5k and so k = −1 and so x = −5 which indeed is a solution. x = 6k + 2 implies 6k + 2 = 5k + 1 and so k = −1 and so x = −4 which indeed is a solution. x = 6k + 3 implies 6k + 3 = 5k + 2 and so k = −1 and so x = −3 which indeed is a solution. x = 6k + 4 implies 6k + 4 = 5k + 3 and so k = −1 and so x = −2 which indeed is a solution. x = 6k + 5 implies 6k + 5 = 5k + 3 and so k = −2 and so x = −7 which indeed is a solution. So A2 = {−7, −5, −4, −3, −2, 0} And so A2 ∪ A3 = {−7, −5, −4, −3, −2, −1, 0}
Solution. 18. Substitute x := y + 1 to the preposition to get | f (y + 1) − f (y)| ≤
|y + 1 − y| = 1. Because f is injective, | f (y + 1) − f (y)| = 1. Now set f (0) = a. Because | f (1) − f (0)| = 1, either f (1) = a + 1 or f (1) = a − 1. Suppose f (1) = a + 1. We induct that f (n) = a + n. For n = 0, 1, this is correct. Suppose for n = k, k + 1, this claim is correct, then: | f (k + 2) − f (k + 1)| = 1 f (k + 2) = f (k + 1) + 1 ∨ f (k + 1) − 1 f (k + 2) = a + k + 189
Solutions 2 ∨ a + k But f (k ) = a + k, so since f is injective, f (k + 2) = a + k + 2, and the claim is proven for n ≥ 0. For n = 1, 0, this is correct. Suppose for n = k + 1, k, this claim is correct, then: | f (k − 1) − f (k)| = 1 f (k − 1) = f (k) + 1 ∨ f (k) − 1 f (k − 1) = a + k + 1 ∨ a + k − 1 But f (k + 1) = a + k + 1, so f (k − 1) = a + k − 1, and the claim is proven for n ≤ 0. Hence f (n) = a + n for all integer n. The same argument can be applied to where f (0) = a, f (1) = a − 1 to get f (n) = a − n. Hence we have our solutions: f ( x ) = c + x for all x, or f ( x ) = c − x for all x, for any c.
Solution. 19. Let P( a, b) be the assertion a2 + ab + b2
Rb
f ( x ) dx = 3
a
t ∈ R, we have P(0, t) =⇒ t
2
Zt
f ( x ) dx = 3
0
Zt
Rb
x2 f ( x ) dx, and
a
x2 f ( x ) dx
0
since f is continuous here, we know that f ′ exists, and differentiating with respect to t on both sides gives 2
t f (t) + 2t
Zt
2
f ( x ) dx = 3t f (t) =⇒
0
Zt
f ( x ) dx = t f (t)
0
and differentiating with respect to t again gives f (t) = f (t) + t f ′ ( x ) =⇒ f ′ (t) = 0 and so f is a constant function. It is easy to check that f ( x ) = C where C ∈ R works. ■
Rt Rt Rt Solution. 20. t = 0 dx ≤ 0 e x dx ≤ 0 edx = et ⇒ 1 + t ≤ et ≤ 1 + et, (∀) t ∈ [0, 1] . R1 R 1 xn R1 1 e n n ⇒ 1 + n+ 1 = 0 (1 + x ) dx ≤ 0 e dx ≤ 0 (1 + ex ) dx = 1 + n+1 , (∀) n ∈ N R1 n ⇒ lim 0 e x dx = 1. n→∞
190
Solutions Solution. 21. Lemma: If P, Q, R are three 2 × 2 matrices, then det( P + Q + R) = det( P + Q) + det( Q + R) + det( P + R) − det( P) − det( Q) − det( R). Apply the above lemma to get that det( A + 2B) − det( B + 2A) = det(2B) − det(2A) − (det( B) − det( A)). Now use that det( A) = 0 and det( B) = 2 to get the answer as 6.
Solution. 22. Since 346346 ≡ 4 (mod 9), we need at least four perfect cubes. On the other hand, (7 · 346115 )3 + (346115 )3 + (346115 )3 + (346115 )3 = (73 + 13 + 13 + 13 ) · 346345 = 346346 . So the minimum number is 4 .
Solution. 23. Suppose , that x = c is a integer solution to this equation . Then, 2abc4 − a2 c2 − b2 − 1 = 0 =⇒ ac2 (2bc2 − a) = b2 + 1 . Note that b2 + 1 prime factors are either 2 or of form 4k + 1. Also we see that if , a is even then , we get 4|b2 + 1 a contradiction . similarly we see that c is also odd. And indeed if b is odd , then we again get a similar contradiction. Now , if a ≡ 3 (mod 4) then , we it means there is prime factor of a which is of form 4k + 3 a condtradiction. Also c must also be of form 4k + 1 . And b is even . But then we have 2bc2 − a2 ≡ 3 (mod 4) a contradiction .
Solution. 24. ∠ AUC ≡ ∠ AXB ≡ ∠ DXC ≡ ∠ AVD ⇒ ∠ AUT + ∠CUT = ∠ AVT +
∠TVP ⇒ ∠CUT ≡ ∠TVA. Denote { R} = (VPU ) ∩ AV. Using the fact that ∠CUT ≡ ∠TVR, we get that R, C and U are colinear. RP AP RP CP Now AR · AV = AP · AU ⇒ △ ARP ∼ △ AUV ⇒ UV = AV , but UV = CU , AP CP thus AV = CU ⇒ △CPU ∼ △ ACV. Similarly we prove that △CRV ∼ △ ACU ⇒ AC AV △ ACV ∼ △ ACU ⇒ ∠VAC ≡ ∠CAU ⇒ AC = AU ⇒ AV = AU ⇒ A, C and M are colinear. ∠ ATP ≡ ∠ ACP ≡ ∠VCO ≡ ∠OCU, where {O} = AC ∩ UV ∠ MVT + ∠ MAT = ∠ MVT + π − ∠TAC = ∠VUT + π − ∠TPV = π, hence MVTA is cyclic⇒ ∠ MVA ≡ ∠ MTA 191
Solutions
∠ MVA = ∠VUR =
π 2
− ∠OCU ⇒ ∠ MTA + ∠ ATP =
π 2
⇒ ∠ PTM = π2 .
Solution. 25. We prove both parts. Define MB , MC as the arc midpoints of AC and AB, O as the circumcenter, and TB , TC as the B-extouch point with AC and the C-extouch point with AB. Part 1: If AB + AC = 3BC, then P, I, Q are collinear. Proof: Observe that s = 2BC, so BTC = s − BC = BC, and similarly CTB = BC. Therefore, we have 1 ∠QCA = ∠TC CB = 90 − B 2 This implies Q is the arc midpoint of ABC. Similarly, P is the arc midpoint of APB, so P, O, MC and Q, O, MB are collinear. Observe that MB MC is the perpendicular bisector of AI. Then, 1 BC 1 BC QMC = 2R sin A = sin A = 2 sin A 2 2 cos 12 A If QMC = 12 AI, we’re done. Observe that the length of the tangent from A to the incircle is s − BC = BC, so 1 1 r sin 12 A 1 r BC tan A = = ⇒ QMC = AI 2 BC 2 = 2 2 cos 12 A and we are done. Part 2: If P, I, Q are collinear, then AB + AC = 3BC. If we let SB , SC be the touch-points of ωC , ω B with AC, AB respectively, then by homothety, P, SC , MC and Q, SB , MB are collinear. Furthermore, it is well known that ( QISB A) and ( PISC A) are cyclic. If O′ = QMB ∩ PMC , then
∠ ASC O′ + ∠ ASB O′ = ∠ AIQ + ∠ AIP = 180 which means ( ASC O′ SB ) is cyclic. Therefore, ∠ MC O′ MB = 180 − ∠ A. However, since MC MB = 90 − 12 A, this means PQ = 90 − 12 A, so PQ = MC MB . Define S = CQ ∩ PB. By pascals on PBMB QCMC , we have I, S, O′ are collinear. Since S is the exsimilicenter of the incircle and circumcircle, we have I, O, S are collinear. Now, I claim the only way for O′ , O, I to be collinear is when O = O′ . First of all, this is possible by setting P, Q as the reflection of MC , MB over O. Next, for any other placement of P, Q is fixed (since PQ = MC MB . Inverting with the circumcenter, O′ goes to the intersection of MC MB and PQ, so the locus of O′ is ( MC OMB ). However, since MC MB ∩ PQ lies outside of MC MB , this means the locus of O′ must also be within ( ABC ), so the only intersection of ( MC OMB ) with OI is O. Therefore, O′ = O. Finally, this means 1 ∠ BCTC = ∠QCA = 90 − ∠ ACMB = 90 − B 2 192
Solutions so BTC = BC, and s − BC = BC so AB + AC = 3BC.
4 x −cos2 x
Solution. 26. Proof 2sin 4 x +sin2 x
4 x −sin2 x
− 2cos
4 x +cos2 x
4 x +1−cos2 x
= cos 2x ⇔ 2sin
4 x +sin2 x
4 x +1−sin2 x
− 2cos 4
2
=
4
2x
1 − 2cos x+cos x−sin x−sin 4 2 2 cos 2x 2sin x+sin x 1 − 22 cos 2x = 2 cos 2x ⇒ 2 cos 2x 1 − 22 cos 2x ≥ 0 ⇔ cos 2x = 4 2 0 ⇒ 2sin x+sin x 1 − 22 cos 2x = 2 cos 2x ⇔ cos 2x = 0 ⇔ x ∈ ± π4 + πk, k ∈ Z 2 cos 2x ⇔ 2sin
− 2cos
= 2 cos 2x ⇔ 2sin
Solution. 27. Let f ( x ) = x2 − ( a2 + b2 + c2 + d2 + 1) x + ab + bc + cd + da, let roots of f be x = r1 , r2 . Since f ∈ Z[ X ] is monic and has an integer root, we see that it must necessarily have two integer roots. We see that r1 + r2 = a2 + b2 + c2 + d2 + 1 > 0 and r1 r2 = ab + bc + cd + da > 0, therefore r1 , r2 > 0. 1 Now, a2 + b2 + c2 + d2 = ab + bc + cd + da + [( a − b)2 + (b − c)2 + (c − d)2 + (d − 2 1 2 a) ] and so this re-arranges to (1 − r1 )(r2 + 1) = [( a − b)2 + (b − c)2 + (c − d)2 + 2 (d − a)2 ] ≥ 0 . . . (♣), however r1 , r2 ̸= 0 as ( a, b, c, d) ∈ N and so r1 , r2 ≥ 1, implying that (1 − r1 )(r2 − 1) ≤ 0 and using (♣), we have that (1 − r1 )(r2 − 1) = 0 or one of the roots r1 or r2 is 1, let r1 = 1, then a2 + b2 + c2 + d2 = r1 + r2 = r1 + 1 = ab + bc + cd + da + 1 =⇒ a2 + b2 + c2 + d2 = ab + bc + cd + da and so a = b = c = d must be true, implying that x = r1 or r2 = ab + bc + cd + da = 4a2 = (2a)2 or 1 = 12 which is as desired
Solution. 28. If x > 1 then LHS > RHS, if 0 < x < 1 then LHS < RHS. so x = 1 is the only solution
193
=
Solutions Solution. 29. a + b − c = 2 and 2ab − c2 = 4 =⇒ ( a + b − c)2 = 2ab − c2 =⇒ a2 + b2 + 2c2 − 2c( a + b) = 0 a2 + b2 + 2c(c − a − b) = 0 =⇒ 2ab − 4c ≤ a2 + b2 − 4c = 0 =⇒ 2ab − 4c ≤ 0 2ab = 4 + c2 =⇒ 2ab − 4c = 4 + c2 − 4c = (c − 2)2 ≤ 0. So c − 2 = 0 =⇒ c = 2. Therefore, a + b = 4 and 2ab = 8, ( a + b)2 = 16 and 4ab = 16 =⇒ ( a + b)2 = 4ab =⇒ a = b Then we deduce that a = b = c = 2 So △ ABC is an equilateral triangle
Solution. 30. Let ab = 1010 and suppose a and b have no zeroes in their decimal representation. One of a, b must be divisible by 2 and one must be divisible by 5, and neither can be divisible by both. Therefore a = 210 and b = 510 . But then a = 1024, which has a zero, contradiction.
Solution. 31.
n n −1 −1 ( n −1)2
=
(n−1)(nn−2 +nn−3 +···+1) ( n −1)2
=
nn−2 +nn−3 +···+1 . n −1
I now show nn−2 +
nn−3 + · · · + 1 ≡ 0 (mod n − 1). We know n ≡ 1 (mod n − 1), so nn−2 + nn−3 + · · · + 1 ≡ n − 1 ≡ 0 (mod n − 1)■
Solution. 32. The equality is obvious at x = 2 Now using a is the longest side, For x > 2 a x = a2 a x−2 = (b2 + c2 )( a x−2 ) > b x + c x
194
Solutions Solution. 33. (a) x n + x n+1 is strictly increasing and continuous on R+ .And x n + x n+1 goes from 0 to +∞ on R+ .Then by intermediate value theorem, ∃!xn > 0 s.t. xnn + xnn+1 = 1■ +1 n +2 (b) Obviously 0 < xn < 1.If xn+1 < xn ,then 1 = xnn + xnn+1 > xnn+ 1 + xn+1 which is absurd.Thus xn+1 ≥ xn .Then { xn } is increasing and upper-bounded.Therefore ∃α s.t. limn→+∞ xn = α.0 < α ≤ 1.If 0 < α < 1,then limn→+∞ ln xnn = limn→+∞ n ln xn = −∞.Hence limn→+∞ xnn = 0.And 0 < xnn+1 < xnn ,by squeeze theorem, limn→+∞ xnn+1 = 0.Thus limn→+∞ xnn + xnn+1 = 0 which is absurd.Therefore α = 1■
p Solution. 34. 1)Using power mean inequality (k p + (n − k ) p ) ≥ 2 n2 so 1 p + 2 p + p ... + (n − 1) p + n p + (n − 1) p + ... + 2 p + 1 p ≥ 2n · n2 −→ ∞ as n −→ ∞ 2)For the second case it is easy to calculate
1 p +2 p +...+(n−1) p +n p +(n−1) p +...+2 p +1 p n2
=1
Solution. 35. ∠ DFE = ∠ DAE by angles in the same segment property. ∠ ADF = 90◦ − ∠ DAF =⇒ ∠ MDF = 90◦ − ∠OAF = B using MD || AO ∠OAF = 90◦ − B hence △ FMD ∼ △ ADB by angle equalities
n −r +1 r −1 n Solution. 36. Rewrite the identity as ∑∞ d=1 ( d )(r −d) = ( r ) (1). Arbitrarily split n
objects into a group of n − r + 1 (Group 1) and r − 1 (Group 2) objects. In order to choose r objects from the n total, we can either choose 1 object from Group 1 and r − 1 from Group 2 or 2 from Group 1 and r − 2 from Group 2, etc. Thusly we can count the choosing of r objects from n in two ways, proving the equality of the L.H.S. and R.H.S. of (1). Note that d cannot be 0 because we cannot choose r objects from Group 2, which only has r − 1 objects. Also when d > n − r + 1 or d − 1 > r − 1, the binomial product vanishes (the sum is equally valid from d = 1 to min({n − r + 1, r })).
195
Solutions 1
1
1
1
ln(2)
Solution. 37. let P = 2 2 · 4 4 · 8 8 · (2n ) 2n from here we get ln( P) = 2 n ln(2) 3 3 1 2 3 n ln ( 2 ) + · · · + ln ( 2 ) + · · · + ln ( P ) = ln ( 2 ) + + + · · · + 8 2n 2n 8 2 4 8 n +1 n +1 ln( P) = ln(2) −2 21 (n + 1) − 2 12 + 2 < 2 ln(2)
+
ln(2) 2
+
p p √ √ Solution. 38. Let N = 3 13 + x + 3 13 − x p√ p √ note that N > 3 x + 3 − x = 0 p √ √ p √ p √ 3 3 3 = (13 + cubing both sides yeilds:N x ) + 3 ( 13 + x )( 13 − x )( 3 13 + x + p √ √ 3 13 − x ) + (13 − x )
√ 3
N 3 − 26 169 − x = 3N
3
−26 3 x = 169 − ( N 3N ) >0 It is easy to see that if N ≥ 5,then x < 0 therefore,N ∈ {1, 2, 3, 4} put the values N to get x = 196 as the only integer for N = 2
Solution. 39. Let P( x, y) be the assertion f (max( x, y) + min( f ( x ), f (y))) = x + y Let a = f (0) P( x, x ) =⇒ f ( x + f ( x )) = 2x Let x > y. If f ( x ) ≤ f (y), then P( x, y) =⇒ f ( x + f ( x )) = x + y = 2x and so x = y, impossible. So x > y =⇒ f ( x ) > f (y) and P( x, y =⇒ : f ( x + f (y)) = x + y ∀ x > y (I) So f ( x ) = x + y − f (y) ∀ x > f (y) Setting there y = 0, we get f ( x ) = x − a ∀ x > a (II) Let then y ∈ R and x > max(y, a − f (y)) : x > y implies f ( x + f (y)) = x + y (see I above) x + f (y) > a implies f ( x + f (y)) = x + f (y) − a (see II above) And so f (y) = y + a ∀y Plugging this back in original equation, we get a = 0 and so f ( x ) = x ∀ x
196
Solutions Solution. 40. We have ( a + d)(b + c) = ( ab + cd) + ( ac + bd) = 9 and ( a + d) + (b + c) = 6. Therefore, we must have a + d = b + c = 3. Similarly, ( a + b)(c + d) = 5 and ( a + b) + (c + d) = 6. Therefore, { a + b, c + d} = {1, 5}. Also similarly, ( a + c)(b + d) = ( ab + cd) + ( ad + bc) = 8 and ( a + c) + (b + d) = 6. Therefore, we must have { a + c, b + d} = {2, 4}. Note that 2a = ( a + b) + ( a + c) − (b + c) ∈ {0, 2, 4, 6}. Therefore, a ∈ {0, 1, 2, 3}. However, each of these gives us a unique solution (because each value of a corresponds to a unique value of a + b and a + c), and therefore all the solutions are ( a, b, c, d) = (0, 1, 2, 3), (1, 0, 3, 2), (2, 3, 0, 1), (3, 2, 1, 0)
Solution. 41. .Given tan( x + y + z) =
sin 3x +sin 3y+sin 3z cos 3x +cos 3y+cos 3z ,
then sin( x + y + z)(cos 3x +
cos 3y + cos 3z) = cos( x + y + z)(sin 3x + sin 3y + sin 3z), sin(4x + y + z) + sin(−2x + y + z) + sin( x + 4y + z) + sin( x − 2y + z) + sin( x + y + 4z) + sin( x + y − 2z) = sin(4x + y + z) + sin(2x − y − z) + sin( x + 4y + z) + sin(− x + 2y − z) + sin( x + y + 4z) + sin(− x − y + 2z), simplifying: sin(2x − y − z) + sin(− x + 2y − z) + sin(2z − x − y) = 0, [sin(2x − y y − z) + sin(− x + 2y − z)] + sin 2(z − 2x − 2 ) = 0, y 3y y y y x x x 2 sin( 2x + 2 − z) cos( 3x 2 − 2 ) + 2 sin( z − 2 − 2 ) cos( z − 2 − 2 ) = 0, sin( 2 + 2 − 3y y x z)[cos( 3x 2 − 2 ) − cos( z − 2 − 2 )] = 0. Solutions: x + y = 2z or 2x = y + z R = 1 + 2 cos answer
3( x − y ) 2
which gives 4 as desired
Solution. 42. Let x = cos θ and y = sin θ. Then the second condition becomes 4 sin(θ ) cos(θ )cos(2θ ) = 1, which becomes 2 sin(2θ ) cos(2θ ) = 1, becomes √ which √ 2 sin(4θ ) = 1. Thus, 4θ = π2 , so θ = π8 . Thus, x = cos π8 = 2+ , so the an2 2 2 swer is 2 + 2 = 4 S2 :16x2 y2 2x2 − 1 = 1 =⇒ 16x2 (1 − x2 ) 2x2 − 1 = 1 =⇒ 64x8 − 128x6 + 80x4 − 16x2 + 1 = 0 2 =⇒ 64x8√− 128x6 + 64x4 + 16x4 − 16x2 + 1 = 0 =⇒ 8x4 − 8x2 + 1 = 0 =⇒ √ −(−8)± (−8)2 −4·8·1 2± 2 2 x = = 4 2·8 √ √ 2 So the largest root is x = 2+ 2 And again, a + b = 2 + 2 = 4.
197
Solutions Solution. 43. We can rewrite f ( x ) as −( x − 2p)2 + 4p2 − p + 1. The area of this triangle is equal to half the base times the height. Taking the base as the side of the triangle on the x-axis, the base is the difference between the roots and the height is the y-coordinate of the vertex. The y-coordinate of the vertex is, from the above 4p2 − p + 1. Let this be q. √ form, p −4p± 16p2 −4p+4 From the quadratic formula, the roots are 2p ± 4p2 − p + 1, so = −2 p 2 − p + 1 = 2√ q. the base of the triangle, or the difference in the roots, is 2 4p √ √ Therefore, the area of the triangle is 12 (q)(2 q) = q q. This is an integer if and only if q is the square of an integer. Now let 4p2 − p + 1√= x2 , so that 4p2 − p + 1 − x2 = 0. From the quadratic formula, √
2
1±
(4x )2 −15
−15 = . p = 1± 16x 8 8 2 2 Now let (4x ) − 15 = y , or (4x − y)(4x + y) = 15. Therefore, either 4x − y = 1, 4x + y = 15, or 4x − y = 3, 4x + y = 5. Both of these give integral values for x, so there are two integral values for x. Each integral value for x gives two rational values for p, so we have 4 rational values. Namely, p = − 43 , 0, 14 , 1.
Solution. 44. Using L’hospital’s rule and differentiation under integral sign, we have: R 1 lim A → ∞ A1 1 A A x dx = L’Hospital = 1 −1 1 R R 1 lim A → ∞A A + 1 A A xx dx = 1 + lim A → ∞ A1 1 A Axx dx = L’Hospital 1 1 −1 1 R R =1+ lim A → ∞ AAA + 1 A A xx2 dx = 1 + lim A → ∞ A1 1 A Ax2x dx = 1 + lim A→∞ A1 · 1
A− A A ln A
=1
Solution. 45. By adding all equations we get a3 + b3 + c3 + d3 = 0 which implies that at least one of them is positive and at least one of them is negative. Suppose a is positive. If b was positive this will imply c is positive which will imply d being positive which can’t happen. Then b is negative. From d3 + a = b we get that d is negative too. Since c3 = a − d we have that c must be positive. The other cases are the same thing, basically a and c share signs and b and d also share signs, opposite to the sign of a and c. Therefore, suppose a, c are positive and b, d are negative. For simplicity, we will set a = x 2 , b = − y2 , c = z2 , d = − w2 . 198
Solutions Our equations then become 6 x − y2 = z2 − y6 + z2 = − w2 z6 − w2 = x 2 − w6 + x 2 = − y2 Which after rearranging become 6 x = y2 + z2 y6 = z2 + w2 z6 = w2 + x 2 6 w = x 2 + y2 Clearly, x6 + z6 = y6 + w6 Suppose x2 > z2 . From this we have x6 > z6 → y2 + z2 > w2 + x2 → y2 > w2 → y6 > w6 However, x2 + y2 > z2 + w2 → w6 > y6 which is a contradiction. Similarly, asumming z2 > x2 will give us a contradiction in the same way. Therefore x 2 = z2 . Using the exact same method we can prove y2 = w2 Since x6 + z6 = y6 + w6 we have x6 = y6 I will switch back to a, b, c, d keeping in mind a = c , b = d and a3 = −b3 We have the two equations ( a3 + b = a b3 + a = b Since a3 = −b3 we must have a = −b √ √ Therefore we must solve a3 = 2a. equation √ The√solutions √ √to this √ √ are √ 0,√ 2, − 2. Hence ( a, b, c, d) = (0, 0, 0, 0), ( 2, − 2, 2, − 2), (− 2, 2, − 2, 2)
Solution. 46. Let ( x, y) := ( g(0), f ( g(0))): g( f ( g(0)) − f ( g(0))) = f ( g( f ( g(0)))) + g(0) f ( g( f ( g(0)))) = 0 Let ( x, y) := ( g( f ( g(0))), 0): g( f ( g( f ( g(0))))) = f ( g(0)) + g( f ( g(0))) (1) g(0) = f ( g(0)) + g( f ( g(0))) Let ( x, y) := ( g(0), 0): (2) g( f ( g(0))) = f ( g(0)) + g(0) From (1) and then (2) we have: g(0) = f ( g(0)) + g( f ( g(0))) = f ( g(0)) + f ( g(0)) + g(0) = 2 f ( g(0)) + g(0), so f ( g(0)) = 0. Let ( x, y) := (0, 0): g( f (0)) = f ( g(0)) = 0 Let y := 0: g( f ( x )) = f ( g(0)) + x = x Let y := f ( x ): g(0) = f ( g( f ( x ))) + x, but g( f ( x )) = x, so g(0) = f ( x ) + x, so f ( x ) = − x + g(0). We use f ( x ) = − x + g(0) in g( f ( x )) = x and we get: g(− x + g(0)) = x Let x := − x + g(0) in g(− x + g(0)) = x: g( x ) = − x + g(0) So f ( x ) = g( x ) = − x + g(0). Check: LHS = g( f ( x ) − y) = g(− x + g(0) − y) = x + y − g(0) + g(0) = x + y RHS = f ( g(y)) + x = f (−y + g(0)) + x = y − g(0) + g(0) + x = x + y. So functions f ( x ) = g( x ) = − x + c for any c are solutions of this equation. 199
Solutions
Solution. 47. Case I: x = y then ( x, y) = (50, 50), (1, 1). Case II: x < y then ( x, y) = (2, 225 ), (5, 510 ), (10, 105 ), (25, 252 ). These pairs are √ 50 x found by using equation y = x50 = x x . Clearly, x must be a divisor of 50. Case III: x > y then this means x50 > y50 so y x = x50 if x > 50. But from the 50 equation in Case II, if x > 50 then x x is not an integer so there is no solutions in this condition. ∴ The all pairs of solutions are (1, 1), (2, 225 ), (5, 510 ), (10, 105 ), (25, 252 ), (50, 50).
Solution. 48. .Let the midpoint of BC be M, let AM and BE meet at H, and let BE meet AC at N. Since AB = AC, we have that AM ⊥ BD and we already know that BE ⊥ AD, so H is the orthocenter of △ ABD, so DH ⊥ AB. Yet, AC ⊥ AB, so DH ∥ AC. Thus, HM MD MC − DC = = = AH DC DC
BC 2
− BC 3
BC 3
=
BC 6 BC 3
=
1 2
It follows that since H is on median AM, we have that H is the centroid of △ ABC. Thus, N is the midpoint of AC. Now, notice that ∠ AEN = 90 = ∠ BAN, so △ AEN ∼ EN 2 2 = AN △ BAN, which means that AN BN , so BN · EN = AN = CN . This gives that EN NC NC = BN , so △ ENC ∼ △CNB, so ∠ NCE = ∠ NBC. Furthermore, from similar triangles AEN and BAN, we have that ∠EAN = ∠ ABN, so
∠ AEC = 180 − ∠EAC − ∠ECA = 180 − ∠ ABN − ∠CBN = 180 − 45 = 135 from which we conclude that ∠ DEC = 180 − ∠ AEC = 45 .
Solution. 49. We start by noting that equality holds for {n, n + 1, n + 2}. This tells us that the inequality may be hard to prove, and it’s logical to try our hand at a simpler analogue. We may construct a 2-variable version, where equality holds for {n, n + 1}. Namely, this is 1 1 a− b− ≤ ab − 2. (1) a b 200
Solutions Proof. After multiplying by ab and expanding, we arrive at a2 b2 − a2 − b2 + 1 ≤ a2 b2 − 2ab, which rearranges to 1 ≤ ( a − b)2 , which is true. Equality holds only for | a − b| = 1. ■ Using this inequality, we may easily establish the problem’s claim: 1 1 1 1 a− b− c− ≤ a− (bc − 2) ≤ abc − ( a + b + c), a b c a where the last estimate is equivalent to abc − 2a −
bc 2 + ≤ abc − ( a + b + c), a a
bc ( a − b)( a − c) 2 ≤ a−b−c+ = , a a a which is clearly true if ( a − b)( a − c) ≥ 2. This holds if a = max{ a, b, c}, which we may assume WLOG. ■
Solution. 50. WLOG a ≥ b and c ≥ d and b ≥ d abcd = 4( a + b)(c + d) ≤ 4( a + a)(c + c) = 16ac ⇒ bd ≤ 16 ⇒ d2 ≤ bd ≤ 16 ⇒ d ≤ 4 2(c + d) = ab ⇒ 2c = ab − 2d 2( a + b) = cd ⇒ 4( a + b) = 2cd ⇒ 4( a + b) = ( ab − 2d)d ⇒ abd2 − 4ad − 4bd − 2d3 = 0 ⇒ ( ad − 4)(bd − 4) = 2d3 + 16 and obviously we can put d = 1, 2, 3, 4 in the last equality,and find solutions... d = 1: ( a − 4)(b − 4) = 18 ⇒ b = 5, a = 22, c = 54 or b = 6, a = 13, c = 38 or b = 7, a = 10, c = 34 d = 2: (2a − 4)(2b − 4) = 32 ⇒ ( a − 2)(b − 2) = 8 ⇒ b = 3, a = 10, c = 13 or b = 4, a = 6, c = 10 d = 3: (3a − 4)(3b − 4) = 70 ⇒ b = 3, a = 6, c = 6 d = 4: (4a − 4)(4b − 4) = 144 ⇒ ( a − 1)(b − 1) = 9 ⇒ b = 4, a = 4, c = 4 therefore all solutions are: {{ a, b}, {c, d}} = {{22, 5}, {54, 1}}, {{13, 6}, {38, 1}}, {{7, 10}, {34, 1}} , {{10, 3}, {13, 2}}, {{6, 4}, {10, 2}}, {{6, 3}, {6, 3}}, {{4, 4}, {4, 4}}
201
About the Authors Pranav M. Sawant Pranav Milind Sawant is a Grade 12 student from Army Public School, Pune. He has been studying Olympiad mathematics for the past four years and has done exceedingly well, alongside consistently bagging single-digit ranks, in several prestigious Olympiads such as the IOQM (Indian Olympiad Qualifier in Mathematics), INMO (Indian National Mathematics Olympiad), SouthEast Asian Maths Olympiad, Asia International Math Olympiad, Purple Comet and many others. With a background in Competitive programming as well, Pranav loves to solve Combinatorics, Game Theory and Number Theory problems. His research interests include the likes of Number Theory, Stochastic Analysis, Mathematical Modelling, Game Theory and Astronomy. He has also authored two research papers and has a provisional patent to his name. You can find more about him in the links provided. Personal Website: https://pranavsawant.in Linkedin: https://www.linkedin.com/in/pranavsawant-2005/ ResearchGate: https://www.researchgate.net/profile/Pranav-Sawant-6 GoogleScholar: https://scholar.google.com/citations?user=Io6UOIQAAAAJ&hl=en&authuser=2 Academia: https://independentresearcher.academia.edu/PranavSawant
Piyush K. Jha Piyush Kumar Jha is a mathlete with multiple accolades in Mathematical Olympiads. He is currently in grade 12 at Rishabh Public School, Delhi. He has been preparing for math Olympiads for the past 3 years and coining math problems since he was in grade 10. With his commitment and hard work, he qualified for the Indian National Math Olympiad (INMO) in 2020-21. He also has excellent performances in exams such as Limit, Purple Comet and Sharygin Olympiad. To share the knowledge he acquired over these years and give back to the community he runs "Mathematical Society", an educational platform. His research interests include real analysis, complex analysis, geometry, algebra, number theory and combinatorics. To connect with Piyush or get hints and solutions for the Unsolved Challenges, he can be contacted via his email [email protected] or his AOPS id #lifeismathematics.
Anshuman Shukla’s Links Personal Website: https://anshuman.email Linkedin: https://www.linkedin.com/in/anshuman-shukla-a90a93227/ ResearchGate: https://www.researchgate.net/profile/Anshuman-Shukla-17 Medium: https://medium.com/@anshuman.shukla07
Recommended Resources for Olympiad Mathematics 1) Handouts ● Evan Chen Handouts: https://web.evanchen.cc/olympiad.html ● Yufei Zhao Handouts: https://yufeizhao.com/olympiad.html ● Alexander Remorov Handouts: https://alexanderrem.weebly.com/math-competitions.html ● Po-Shen Loh Handouts: https://math.cmu.edu/~ploh/olympiad.shtml 2) Books ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ● ●
Mathematical Circles (Russian Experience) by Fomin, Genkin and Itenberg Excursion in Mathematics by Bhaskaracharya Pratishthana, Pune Inequalities (Little Mathematical Library) by Pavel Korovkin Functional Equation by B.J. Venkatchala The Art and Craft of Problem Solving by Paul Zeitz Mathematical Olympiad Challenges by Titu Andreescu Mathematical Olympiad Treasures by Titu Andreescu Putnam and Beyond by Gelca and Andreescu Lecture Notes on Mathematical Olympiad Courses by Xu Jiagu Euclidean Geometry in Mathematical Olympiads by Evan Chen Game Theory and Strategy by Philip D. Straffin The USSR Olympiad Problem Book by Shklarsky, Chentzov and Yaglom Lemmas in Olympiad Geometry by Adreescu, Korsky and Pohoata Inequalities: Theorems, Techniques and Selected Problems by Zdravko Cvetkovski Problems in Plane Geometry by Igor Sharygin The Mathematical Olympiad Handbook by A. Gardiner Problem Solving Strategies by Arthur Engel Principles and Techniques in Combinatorics by Chi Chuan Elementary Number Theory by David Burton Polynomials by E.J. Barbeau Elementary Number Theory by Waclaw Sierpinski Graph Theory by Frank Harary Introductory Combinatorics by Richard Brualdi Secrets in Inequalities Vil. I and II by Pham Kim Hung Functional Equations and How to Solve Them - (Springer) - Christopher G. Small.